Alphabeta Math
TheoremStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedverified 2026-10-22 (gpt-6.1-sol)
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

CTA complex geometrical optics solvability and remainder bound

Statement

Assume the Axiom of Choice and Countable Choice.

Let (M,g) be a transversally anisotropic product domain, let q∈C∞(M‾,R), and let ψ∈C∞ be real on a neighborhood of the transversal projection of M, with ∣dψ∣g0=1. Suppose a∈C∞(M‾,C) satisfies 2∂x1a+2i g0(∇g0ψ,∇g0a)+i(Δg0ψ)a=0. Then, for all sufficiently large τ, there is an exact solution uτ=e−τ(x1+iψ)a+e−τx1rτ,(−Δg+q)uτ=0 in M∘, with rτ∈H1(M) and ∥rτ∥L2(M)≤Cτ−1∥(−Δg+q)a∥L2(M). No boundary value is prescribed for rτ.

Facts & Assumptions

[A1]

The Axiom of Choice is used for the Hahn--Banach extension in the product Carleman right solver [F2].

[A2]

The Axiom of Countable Choice (ACω) is used for its Hilbert-space Riesz representation [F2].

Given: the product domain, smooth real q, real eikonal function ψ with unit transversal gradient, and smooth transport amplitude a.

[F1]

Transversally anisotropic product domain: g=dx12⊕g0 and Δg=∂x12+Δg0.

[F2]

Limiting Carleman estimate and right solvability on a product domain: for φ=x1, the conjugated operator Pφ,h,q=eφ/hh2(−Δg+q)e−φ/h has a distributional right inverse on L2 with norm at most Ch−1.

[F3]

Riemannian gradient and Laplace–Beltrami operator as the trace of the Hessian: the product metric extends the gradient bilinearly to complex phases, and Δg=div⁡g∇g.

[F4]

External input: Dos Santos Ferreira--Kurylev--Lassas--Salo, Proposition 2.1 (PDF p. 10), for a compact oriented CTA manifold, bounded potential, either sign of sufficiently large real τ, and arbitrary f∈L2, gives r∈H1 solving eτx1(−Δg+q)e−τx1r=f, with ∥r∥Hα≤C∣τ∣α−1∥f∥2 for 0≤α≤1, with no prescribed boundary value. We import this statement, not a reconstructed shifted Carleman proof. Its statement and the application in Propositions 2.1--2.2, PDF pp. 10--11, were inspected; the older Proposition 4.4 citation issue is not treated as a local proof.

[F5]

The orientation restriction in [F4] is removed for scalar equations by the orientation double cover of M0. Lift M,q,f to its product cover, solve there, and average the solution with its deck transform. The invariant solution descends to H1(M) and solves the original equation. The degree-two factors in the squared L2 norms cancel in the estimate; the same applies to the local Sobolev norms. A disconnected cover is handled componentwise, using only finitely many choices.

Proof

Given: the data in the statement.

1.1F1F3givenalgebra

Put Φ=x1+iψ. By [F1] and ∣dψ∣g0=1, g(dΦ,dΦ)=1+i2∣dψ∣g02=0. Direct conjugation gives (−Δg+q)(e−τΦa)=e−τΦ[−τ2g(dΦ,dΦ)a+τ(2g(∇gΦ,∇ga)+(ΔgΦ)a)+(−Δg+q)a]. The τ2 term vanishes by the eikonal equality, and the coefficient of τ is exactly the transport equation in the statement. Hence the residual is e−τΦ(−Δg+q)a.

2.1A1A2F4F5step 1.1algebra

Set h=τ−1 and conjugate by the real weight e−τx1. The equation for the correction is Px1,h,qrτ=−h2e−iτψ(−Δg+q)a. The right side is in L2 and has norm h2∥(−Δg+q)a∥2. By [F4]--[F5], with the equation divided by h2, there is an H1 correction (and hence a distributional) rτ∈L2(M) with ∥rτ∥2≤Ch−1h2∥(−Δg+q)a∥2=Cτ−1∥(−Δg+q)a∥2. Thus the asserted remainder estimate and the equation hold distributionally.

3.1F4F5step 1.1step 2.1∎

Choose the H1 correction from step 2.1. Multiplication by the smooth exponentials preserves H1(M) for each fixed τ, and the correction equation cancels the residual computed in step 1.1. Thus uτ is exact, has the stated remainder bound, and has no imposed correction boundary value. The additional boundary regularity is the external input [F4], rather than a consequence asserted for the L2 solver [F2].

Depends on

Used by

Dependency tree · two levels

25 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources