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TheoremStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedverified 2026-10-22 (gpt-6.1-sol)
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Cubic semilinear DN identification by third linearization

Statement

Assume the Axiom of Choice and Countable Choice.

Let (M,g) be a three-dimensional transversally anisotropic product domain with compact connected simple surface transversal (M0,g0). Let q1,q2∈C∞(M‾,R). Suppose that for every finite family of smooth boundary directions, the corresponding small-data nonlinear Dirichlet-to-Neumann maps for −Δgu+qju3=0 agree for all sufficiently small real parameter values. Then q1=q2 on M‾.

Facts & Assumptions

[A1]

The Axiom of Choice is inherited from the small-data, third-linearization, and four-factor suppliers [F1]--[F3].

[A2]

The Axiom of Countable Choice (ACω) is inherited from the small-data, third-linearization, and four-factor suppliers [F1]--[F3].

Given: the CTA product with simple surface transversal, real smooth cubic coefficients, and equality of the finite-parameter nonlinear DN maps for every finite list of smooth boundary directions.

[F1]

Small-data solvability and third differentiability of the cubic DN map: each finite-parameter solution and its nonlinear DN data are C3 in the real parameters near zero.

[F2]

Third linearization identity for the cubic Dirichlet-to-Neumann map: the third DN derivative determines 6∫Mq v1v2v3v4‾ dVg for any four harmonic boundary solutions.

[F3]

Four-harmonic-product realization of a longitudinal Fourier integral: the claimed four-factor limit at any transversal intersection is a nonzero constant times the longitudinal Fourier transform of the coefficient difference.

[F4]

Uniqueness of the L1 Fourier transform: an L1(R) function with identically zero Fourier transform vanishes almost everywhere.

[F5]

The four-factor supplier imports the smooth harmonic-product density theorem of Lassas--Liimatainen--Lin--Salo, Proposition 5.1, PDF p. 14; its hypotheses are a compact oriented CTA manifold of dimension at least three, a C1 coefficient, and four or more smooth harmonic factors. The orientation hypothesis follows here because the local definition Simple surface and geodesic X-ray transform agrees with Paternain--Salo--Uhlmann, Definition 3.8.1: their Theorem 3.8.2 and Propositions 3.8.4--3.8.5 yield unique geodesics and show M0 is diffeomorphic to a closed disk, hence orientable; M inherits the product orientation. See Geometric inverse problems, with emphasis on two dimensions, Section 3.8 (author-hosted full text). For this adjudication the complete argument in LL--LS Section 5, PDF pp. 14--23, including Lemma 5.2, and the cited simple-manifold statements and proofs were read; only the density conclusion is imported, not locally reconstructed. The local four-factor supplier uses that density conclusion and rescales one smooth harmonic factor to realize the target integral. Its witnesses are therefore smooth on M‾, depend on the coefficient being tested, and are constant in τ. They are distinct from the τ-dependent Gaussian beams used to prove density in LL--LS. Thus the smooth-boundary identity [F2] applies directly; no extension of that identity to arbitrary H1 boundary traces is required. Theorem 1.3, pp. 5--6, is the corresponding nonlinear uniqueness theorem, not a replacement local proof here.

Proof

Given: the data in the statement.

1.1A1A2F1F2givenalgebra

Fix four smooth boundary directions h1,h2,h3,h4. Equality of the finite-parameter DN maps for q1 and q2 implies equality of their mixed third derivatives at the origin. Applying [F2] to each coefficient and subtracting gives ∫M(q1−q2)v1v2v3v4‾ dVg=0 for every four harmonic functions vj arising from smooth boundary data.

2.1F2step 1.1algebra

The identity in step 1.1 holds also for complex smooth harmonic functions: write their boundary values as real and imaginary parts and expand the separately linear or conjugate-linear expression. Since the Laplacian has real coefficients, conjugation preserves harmonicity; replacing the fourth function by its conjugate therefore gives ∫MQw1w2w3w4 dV=0 for every four smooth complex harmonic functions, where Q=q1−q2.

3.1A1A2F3F5step 2.1

Fix p∈M0∘ and ξ∈R. Choose the transverse boundary-to-boundary geodesic segments through p supplied by [F3] (their existence is established in that supplier's proof). Apply [F3] with Q=q1−q2. Its witnesses are smooth by [F5], so their product integral is zero for every τ by step 2.1. Taking their stated limit gives c(p,γ1,γ2)∫Ipe−iξx1(q1−q2)(x1,p) dx1=0, where c>0 is the crossing normalization. The coefficient transform therefore vanishes for every ξ and every p.

4.1F4step 3.1algebra∎

For each p, extend x1↦(q1−q2)(x1,p) by zero outside Ip. It is a compactly supported L1(R) function. By step 3.1, [F4] makes this section zero almost everywhere; its smoothness in the interior of M then makes q1−q2=0 on M∘, and continuity gives equality on M‾. Thus the theorem follows.

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