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The p-adic completion is a complete valued field
Statement
Let be the completion of The p-adic numbers as a metric completion. Then termwise addition and multiplication of rational Cauchy sequences descend to well-defined operations on , the absolute value extends to a nonarchimedean absolute value on , every nonzero element has an inverse, and the resulting valued field is complete.
Facts & Assumptions
Given: A prime and as the completion of .
Every metric space has a completion built from equivalence classes of Cauchy sequences, and that completion is complete (Every metric space has a completion, constructed as the equivalence classes of its Cauchy sequences).
The rational -adic absolute value is multiplicative and nonarchimedean (The p-adic absolute value is nonarchimedean).
is the Cauchy-sequence completion of selected in The p-adic numbers as a metric completion.
Proof
By the specific construction fixed in [L3] and supplied by [L1], an element of is represented by a -Cauchy sequence in , and the distance between classes is Define
The nonarchimedean inequality in [L2] shows that sums and differences of Cauchy sequences are Cauchy. A Cauchy sequence in a nonarchimedean metric is bounded, so products of Cauchy sequences are again Cauchy, and equivalent representatives give equivalent sums and products because Passing to the limit through [L2] proves representative independence of the extended absolute value as well.
Let be nonzero. Then , and step 1.1 says in . So there are a real constant and an index with for all . In particular eventually. For , and the right-hand side tends to because is Cauchy. Thus is eventually defined and Cauchy, so every nonzero class has an inverse.
Multiplicativity and the strong triangle inequality on follow by taking limits of the corresponding rational identities from [L2]. Completeness is already part of [L1]. Thus is a complete nonarchimedean valued field.
Depends on
Used by
Dependency tree · two levels
27 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- Andrew V. Sutherland, 18.782 Lecture 8, Theorem 8.1 (standard reference, not scraped)
- J. S. Milne, Algebraic Number Theory, Chapter 7 (standard reference, not scraped)