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Aubin–Lions compactness with exact time exponent

Statement

Assume the Axiom of Choice. Let (V,H,J) be a Banach evolution triple with compact inclusion i:V⋐H and continuous canonical inclusion J:H↪V∗. Let T<∞, 1<p<∞, and 1<q≤∞. Suppose uj∈Lp(0,T;V) have distributional derivatives uj′∈Lq(0,T;V∗) and sup⁡j(∥uj∥Lp(0,T;V)+∥uj′∥Lq(0,T;V∗))<∞. Then (uj) is relatively compact in Lp(0,T;H). If also sup⁡j∥uj∥L∞(0,T;H)<∞, each subsequence converging in Lp(0,T;H) converges, after the same subsequence, in every Lr(0,T;H) with 1≤r<∞.

Facts & Assumptions

Given: The Axiom of Choice, the Banach evolution triple, compact and continuous embeddings, T<∞, 1<p<∞, 1<q≤∞, and the stated uniform bounds.

[F1]

Compact embedding means every bounded sequence in V has an H-convergent subsequence; the canonical map J is continuous and ⟨Jh,v⟩=(h,iv)H (Compactly embedded normed spaces, Banach evolution triples and weak time derivatives).

[F2]

In this theorem, g=uj′∈Lq(0,T;V∗) means ∫0T(iuj(t),iv)Hϕ′(t) dt=−∫0T⟨g(t),v⟩ϕ(t) dt for every v∈V and ϕ∈Cc∞(0,T). This is the scalar-test convention of Banach evolution triples and weak time derivatives, here extended to the stated independent exponent q; membership in Lp′(V∗) is not required. Both integrals exist by the finite-interval L1 bounds from [F3]. In particular, t↦(iuj(t),iv)H has scalar weak derivative t↦⟨g(t),v⟩.

[F3]

Hölder and Minkowski control scalar pairings, integrals and finite Bochner sums (Holder's inequality for integrals, including the endpoint cases, Minkowski's inequality for integrals, including p=∞).

[F4]

A scalar W1,q(0,T) class, 1≤q≤∞, has an absolutely continuous representative on [0,T] (One-dimensional W1,p functions have unique absolutely continuous representatives).

[F5]

The Bochner space Lp(0,T;H) is complete (Bochner Lp is complete for a Banach value space).

Proof

1.1A1F1givenchoose

Fix ε>0. Compactness in [F1] makes the image in H of the V unit ball totally bounded. Take a finite ε/2-net in H for this image; since the range i(V) is dense in H by [F1], approximate each net point within ε/2 by a point of i(V). Let E⊂i(V) be the span of these finitely many points. The H-orthogonal projection PE is the best approximation from E, so ∥(I−PE)iv∥H≤ε∥v∥V(v∈V). After orthonormalizing a basis, write eℓ=ivℓ with vℓ∈V.

1.2A1F2F3F4given

For each j,ℓ, put ajℓ(t)=(uj(t),eℓ)H. Its weak derivative is ⟨uj′(t),vℓ⟩ by [F2]. The uniform bounds and the continuous V→H inclusion give uniform Lp bounds on ajℓ and uniform Lq bounds on their derivatives. Since T<∞, each coefficient is in L1(0,T) and its derivative is in L1(0,T); hence it is in scalar W1,1(0,T) and [F4] gives an absolutely continuous representative. For any such representative, some s∈[0,T] has ∣ajℓ(s)∣≤T−1/p∥ajℓ∥Lp; otherwise its Lp norm would exceed that bound. Its total variation is at most T1−1/q∥ajℓ′∥Lq (with T1−1/q=T for q=∞). Thus all coefficients are uniformly bounded, and Hölder gives the common modulus ∣ajℓ(t)−ajℓ(s)∣≤C∣t−s∣1−1/q for q<∞, with C∣t−s∣ for q=∞.

2.1A1F3step 1.2choose

The finitely many coefficient functions of PEuj are uniformly bounded and share the modulus from step 1.2. Choose a finite time grid so the modulus between adjacent grid points is below ε, and finite ε-nets for their bounded coefficient vectors at each grid point. The piecewise-linear interpolants of the finitely many rounded grid values form a finite family; each coefficient vector is within 2ε of its corresponding interpolant in the uniform norm, by the common modulus and the grid-point rounding error. Hence {PEuj} is totally bounded in Lp(0,T;H).

3.1F3step 1.1step 2.1algebra

By step 1.1, ∥uj−PEuj∥Lp(0,T;H)≤ε∥uj∥Lp(0,T;V). For each desired accuracy, choose ε small and use step 2.1 to approximate the projected family by a finite net. The displayed remainder then shows that the full family is totally bounded in Lp(0,T;H).

4.1A1F3F5step 3.1algebra∎

From total boundedness, [A1] selects a Cauchy subsequence; [F5] makes it convergent in Lp(0,T;H). This proves relative compactness. If the L∞(H) bound is M, pairwise differences have L∞(H) norm at most 2M. For r<p, finite-interval Hölder gives convergence in Lr(H); for r≥p, ∥uj−uk∥Lr(H)r≤(2M)r−p∥uj−uk∥Lp(H)p. Completeness in each Lr(H) then gives convergence for every finite r. These limits equal the Lp(H) limit since both convergences imply convergence in measure, whose limit is unique up to almost-everywhere equality.

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