How statement and proof provenance work
The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.
- Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
- AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
- AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.
These labels describe origin, not correctness: citations and verification chips remain separate evidence.
Mean-zero score and the information identity
Statement
Assume the Axiom of Choice for the selected density representatives. Let be open in , let be a fixed sigma-finite dominating measure, and let be the selected densities of a statistical model. Fix . Suppose that on a neighborhood of there are a fixed measurable support and a -null set such that, for every , and has continuous first and second partial derivatives on ; outside , for all . Suppose there are nonnegative that uniformly dominate every first partial derivative and every second partial derivative, respectively, on . Also assume .
Then , and, entrywise, For a scalar parameter this reads and .
This common-support, integrable-envelope setup is sufficient, not necessary: the theorem does not claim that every model with valid score identities must have common support or these envelopes.
Facts & Assumptions
Given: AC; open; a fixed sigma-finite dominating measure ; a selected density family ; a fixed support and common null set on a neighborhood ; pointwise continuous first and second partial derivatives on ; integrable uniform envelopes for those derivatives; and a finite second moment of the score.
The Axiom of Choice: AC says every family of nonempty sets has a choice function; here it supplies the simultaneous family of density representatives.
Dominated statistical experiments: every sampling law is dominated by the fixed sigma-finite positive measure .
Likelihood densities: is a selected measurable Radon–Nikodym representative of .
The measure with density relative to and Integrating against a density agrees with integrating the product: if , then for nonnegative . For real integrable , apply this identity to and ; applying it first to shows is integrable, so the signed identity follows from the definition of the signed integral.
The mean value theorem, as the case of Cauchy's: for continuous on with and differentiable on there is with : for a differentiable function on an interval, the difference quotient between two endpoints equals its derivative at an intermediate point.
Dominated convergence: pointwise almost-everywhere convergence under one integrable majorant implies convergence of the integrals.
Score and Fisher information: on , the score is and the information matrix has entries .
The chain rule, in one line from Carathéodory: if is differentiable at and is differentiable at , then is differentiable at with , Sums, scalar multiples, products and quotients: , , , and when , and The natural logarithm has derivative 1/x and equals the integral from 1 to x of 1/t: on the positive support, and .
Expectation of a nonnegative or integrable random variable and Integrable real and complex functions, and their integrals: expectations are integrals and signed expectations require integrability.
The Lebesgue integral is linear on : for integrable functions, the integral commutes with differences and scalar multiplication.
Proof
By [F2]–[F4], every selected density has . Fix a coordinate and a sequence with . For almost every , the mean value theorem [F6] bounds by , and the quotient converges to . Dominated convergence [F7] therefore gives convergence of the quotient integrals. Linearity [F11] shows each quotient integral is , so . Since and is a probability, is integrable (use ). On , the signed density identity [F5] and [F8] identify with this integral; outside the law is zero. Thus every score coordinate has mean zero.
For any coordinates , apply the same sequence argument to . The mean value theorem bounds its difference quotient by , so [F7] interchanges this derivative and the integral. Step 1.1 holds at every parameter in , hence throughout ; linearity [F11] turns each difference-quotient integral into the difference of these zero integrals. Dominated convergence then gives .
On , differentiate using [F9]. Multiplying the Hessian formula by , integrating with the signed density identity [F5] and linearity [F11], and using step 2.1 yields . The terms are integrable: , and .
The coordinate identities in step 3.1 give the asserted matrix identity; when they give the scalar identity. Step 1.1 supplies the score mean-zero claim in both cases.
Depends on
- The Axiom of Choice
- Score and Fisher information
- Dominated statistical experiments
- Likelihood densities
- Probability measures and probability spaces
- A sigma-finite signed measure that is absolutely continuous with respect to a sigma-finite positive measure has a unique almost-everywhere density
- The measure with density $f$ relative to $\mu$
- Integrating against a density agrees with integrating the product
- Expectation of a nonnegative or integrable random variable
- Integrable real and complex functions, and their integrals
- Higher derivatives and the classes $C^k$ and $C^\infty$
- The mean value theorem, as the case $g(x) = x$ of Cauchy's: for $f$ continuous on $[a,b]$ with $a < b$ and differentiable on $(a,b)$ there is $c \in (a,b)$ with $f(b) - f(a) = f'(c)(b-a)$
- Dominated convergence
- The Lebesgue integral is linear on $L^1(\mu)$
- The chain rule, in one line from Carathéodory: if $g$ is differentiable at $c$ and $f$ is differentiable at $g(c)$, then $f \circ g$ is differentiable at $c$ with $(f \circ g)'(c) = f'(g(c))\,g'(c)$
- Sums, scalar multiples, products and quotients: $(f+g)'(c) = f'(c) + g'(c)$, $(\alpha f)'(c) = \alpha f'(c)$, $(fg)'(c) = f'(c)g(c) + f(c)g'(c)$, and $(f/g)'(c) = \bigl(f'(c)g(c) - f(c)g'(c)\bigr)/g(c)^{2}$ when $g(c) \ne 0$
- The natural logarithm has derivative 1/x and equals the integral from 1 to x of 1/t
Used by
Dependency tree · two levels
65 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- George Deligiannidis, SB2.1 Foundations of Statistical Inference, §3.1–3.2, Theorems 3.4 and 3.7, PDF pp. 21–24 (standard reference, not scraped)
- Peter Kempthorne, MIT 18.655 Lecture 13: Unbiased Estimation and Risk Inequalities, PDF pp. 6–8, 16–17 (standard reference, not scraped)