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For a finite module, support is the set of primes containing the annihilator
Statement
If is a finitely generated left -module, then
Facts & Assumptions
Given: A commutative ring and a finitely generated left -module .
A prime ideal lies in exactly when some element of has annihilator inside it (A prime lies in the support exactly when some element has annihilator inside it).
If generate , then (A finite module has the union of its generator-cyclic supports).
The annihilator of is (Annihilators, torsion elements and the torsion subset of a module).
Proof
If , [L1] gives with . Since every element of kills every element of , one has .
Choose generators of . If and no is contained in , choose for every . Then , but annihilates every generator and hence all of , so , a contradiction. Thus for some , and [L2] gives .
Steps 1.1 and 1.2 prove the support-annihilator formula.
Depends on
Used by
Dependency tree · two levels
11 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- A. Altman and S. Kleiman, A Term of Commutative Algebra, 13th ed., (13.27) (standard reference, not scraped)
- The Stacks Project, Lemma 10.40.5 (standard reference, not scraped)