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TheoremStatement: Literature-sourcedProof: AI-adaptedprecheck passaudited 2026-08-16
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Weierstrass M-test for complex-valued function series

Statement

Let X be a set and fn:X→C. Suppose Mn≥0, ∣fn(x)∣≤Mn for all n,x, and the real series ∑Mn converges. Then ∑fn(x) converges absolutely for every x and its partial sums converge uniformly on X in the sense of Uniform convergence and the uniformly Cauchy condition for complex-valued functions, with the componentwise dictionary.

Facts & Assumptions

Given: Functions fn and a convergent nonnegative majorant series ∑Mn as in the Statement.

[L2]

A complex-valued function sequence converges uniformly if and only if it is uniformly Cauchy (A sequence of complex-valued functions converges uniformly if and only if it is uniformly Cauchy).

[L3]

The real Weierstrass M-test states that the same majorant hypotheses give absolute pointwise and uniform convergence for real-valued functions (The Weierstrass M-test gives absolute pointwise convergence and uniform convergence of a function series).

Proof

technique · direct
1.1L1algebra

For partial sums SN(x)=∑n<Nfn(x) and q>p, [L1] gives ∣Sq(x)−Sp(x)∣≤∑p≤n<qMn for every x.

2.1step 1.1L2

Since the real series ∑Mn is Cauchy, its tails make the bound in step 1.1 uniformly small; thus (SN) is uniformly Cauchy and converges uniformly by [L2].

3.1L3∎

For each x, the nonnegative series ∑∣fn(x)∣ is bounded termwise by ∑Mn, exactly the comparison used in [L3], and therefore converges. Zero majorants and the empty set require no separate choice.

Depends on

Used by

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Sources