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TheoremStatement: Literature-sourcedProof: AI-adaptedSession-authored (Fable 5 assisted)precheck passaudited 2026-08-16
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Weierstrass M-test for complex-valued function series

Statement

Let X be a set and fn:XC. Suppose Mn0, fn(x)Mn for all n,x, and the real series Mn converges. Then fn(x) converges absolutely for every x and its partial sums converge uniformly on X in the sense of Uniform convergence and the uniformly Cauchy condition for complex-valued functions, with the componentwise dictionary.

Facts & Assumptions

Given: Functions fn and a convergent nonnegative majorant series Mn as in the Statement.

[L2]

A complex-valued function sequence converges uniformly if and only if it is uniformly Cauchy (A sequence of complex-valued functions converges uniformly if and only if it is uniformly Cauchy).

[L3]

The real Weierstrass M-test states that the same majorant hypotheses give absolute pointwise and uniform convergence for real-valued functions (The Weierstrass M-test gives absolute pointwise convergence and uniform convergence of a function series).

Proof

technique · direct
1.1

For partial sums SN(x)=n<Nfn(x) and q>p, [L1] gives Sq(x)Sp(x)pn<qMn for every x.

L1algebra
2.1

Since the real series Mn is Cauchy, its tails make the bound in step 1.1 uniformly small; thus (SN) is uniformly Cauchy and converges uniformly by [L2].

step 1.1L2
3.1

For each x, the nonnegative series fn(x) is bounded termwise by Mn, exactly the comparison used in [L3], and therefore converges. Zero majorants and the empty set require no separate choice.

L3

Depends on

Used by

Dependency tree · next 3 levels

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Sources