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The winding number vanishes on the unbounded component of the complement of the trace
Statement
Let be a closed complex contour with trace and length . Then has exactly one unbounded connected component , and
More precisely, if satisfies and , then and .
Facts & Assumptions
Given: A closed complex contour .
For a compact , the complement has exactly one unbounded connected component , every other component is bounded, and whenever satisfies (The complement of a compact plane set has exactly one unbounded connected component).
The index is constant on every connected component of (The winding number is constant on each connected component of the complement of the trace).
The winding number of a closed complex contour about a point off its trace is an integer (The winding number of a closed contour is an integer).
If on the trace of a rectifiable contour , with , then (ML estimate: a contour integral is bounded by a supremum bound times path length).
A compact subset of a metric space is closed and bounded (A compact subset of a metric space is closed and bounded); the continuous image of a compact subset is compact (The image of a compact metric space under a continuous map is compact, and so is the image of any compact subset); a closed bounded interval is compact (Heine-Borel in : with the Euclidean metric a subset of is compact if and only if it is closed and bounded, and the proof by bisection uses no choice principle; the same holds on the real line).
The connected component is the union of all connected subsets containing (Connected components, quasicomponents, and totally disconnected spaces) and contains every connected subset containing (The components of a space are its maximal connected subsets, they partition it, and each of them is closed).
A subset of a metric space is bounded when it is empty or contained in some ball (Bounded subset, diameter, distance from a point to a set, and distance between two sets in a metric space).
The integers form an ordered commutative ring and their canonical image in is discrete; in particular the only integer of modulus below is (The integers form a commutative ring, The integers form a totally ordered ring, Integer part: for every real there is exactly one integer with ).
Proof
The trace is the continuous image of a compact interval, hence compact by [L6], and bounded by [L6], so there is with . By [L1] the set has exactly one unbounded component , and .
Let . For one has , so by [L9]; hence and on the trace. By [L4] and [L5], .
If in addition then , so step 2.1 gives ; since is an integer by [L3], it is by [L10]. Such exist, for instance , and each lies in by step 1.1.
By [L2] the index is constant on the connected component , and step 3.1 exhibits a point of where its value is ; hence for every , which by [L7] contains every connected unbounded subset of that meets it.
Depends on
- The complement of a compact plane set has exactly one unbounded connected component
- The winding number is constant on each connected component of the complement of the trace
- The winding number of a closed contour is an integer
- ML estimate: a contour integral is bounded by a supremum bound times path length
- The winding number of a closed contour about a point off its trace
- A compact subset of a metric space is closed and bounded
- The image of a compact metric space under a continuous map is compact, and so is the image of any compact subset
- Heine-Borel in $\mathbb{R}^n$: with the Euclidean metric a subset of $\mathbb{R}^n$ is compact if and only if it is closed and bounded, and the proof by bisection uses no choice principle; the same holds on the real line
- Connected components, quasicomponents, and totally disconnected spaces
- The components of a space are its maximal connected subsets, they partition it, and each of them is closed
- Bounded subset, diameter, distance from a point to a set, and distance between two sets in a metric space
- Conjugation is an involutive real-field automorphism, $z\overline z=|z|^2$, and modulus is definite, multiplicative, and subadditive
- The integers as equivalence classes of pairs of naturals
- The integers form a commutative ring
- The integers form a totally ordered ring
- Integer part: for every real $x$ there is exactly one integer $m$ with $m \le x < m + 1$
Used by
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Sources
- L. V. Ahlfors, Complex Analysis, 3rd ed., Ch. 4 §2.1, Properties (i) and (ii) (standard reference, not scraped)