Alphabeta Math
ExampleConstruction: AI-adaptedVerification: AI-generatedprecheck pass
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Direct check of the flat vacuum data with a cosmological parameter against the Friedmann-system equations

Example

Fix real constants c>0, GN>0, A>0, t0∈R and Λ∈R. Then:

  1. If Λ>0, put HΛ:=cΛ/3 and define a:R→(0,∞) by a(t):=Aexp⁡(HΛ(t−t0)), together with ε:=0 and p:=0 on I:=R. Then the Friedmann-system datum (c,GN,Λ,I,0,a,ε,p) satisfies (F), (A), (C) and (S) of The Friedmann, acceleration and continuity equations of an FLRW model datum on all of I.
  2. If Λ<0, then for every nonempty open interval I⊆R and every smooth a:I→(0,∞) the datum (c,GN,Λ,I,0,a,0,0) fails the Friedmann equation (F) at every point of I; in particular no such flat vacuum datum satisfies the Friedmann-system equations.

Facts & Assumptions

Given: The constants c,GN,A,t0,Λ with c>0, GN>0, A>0, the functions a,ε,p of the example, and the equations (F), (A), (C), (S) of The Friedmann, acceleration and continuity equations of an FLRW model datum.

[L2]

For Λ>0 the real power Λ/3=(Λ/3)1/2 is a strictly positive real number with (Λ/3)1/2⋅(Λ/3)1/2=(Λ/3)1=Λ/3, and real powers satisfy (xr)s=xrs and (xy)r=xryr for x,y>0 (Real powers for positive bases, with the zero-base positive-exponent convention, The exponent, product, quotient, and iterated-power laws for positive real bases and real exponents). Hence HΛ=c(Λ/3)1/2 satisfies HΛ>0 and HΛ2=c2Λ/3. For Λ<0 the number Λc2/3 is negative.

[L3]

The equations of The Friedmann, acceleration and continuity equations of an FLRW model datum with k=0 and ε=p=0 read

H2=Λc23,a¨a=Λc23,ε˙+3H(ε+p)=0,−2aa¨+a˙2c2+Λa2=0,

where the four displays are (F), (A), (C) and (S) at every point of I; the third holds identically for ε=p=0.

[L4]

For every real number x one has x2≥0: if x=0 this is clear, and if x≠0 then x2>0 (Squares of nonzero elements are positive). Since c>0 gives c2>0, for Λ<0 the product Λc2/3 is negative (Order on the reals).

Verification

1.1L1givenalgebra

(The exponential datum is admissible.) The function a(t)=Aexp⁡(HΛ(t−t0)) is smooth on R and strictly positive because A>0 and exp⁡>0; by [L1] its logarithmic derivative is H(t)=a˙/a=HΛ and a¨/a=HΛ2. The zero functions ε,p are smooth, and (c,GN,Λ,I,0,a,ε,p) with I=R is a Friedmann-system datum.

1.2L2L3L4algebra

(Λ<0 obstruction.) Suppose Λ<0, let I⊆R be a nonempty open interval and let a:I→(0,∞) be smooth, and suppose the datum (c,GN,Λ,I,0,a,0,0) satisfies (F). By [L3] the Friedmann equation reads H(t)2=Λc2/3 at every t∈I; by [L4] the right-hand side is negative while H(t)2≥0 for the real number H(t), a contradiction. Hence no such datum satisfies (F), proving claim 2.

2.1L2L3step 1.1algebra

(Friedmann equation for Λ>0.) By [L3] and step 1.1, (F) reads H2=Λc2/3; the left-hand side is HΛ2 and HΛ2=c2Λ/3=Λc2/3 by [L2]. Hence (F) holds on I.

2.2L2L3step 1.1algebra

(Acceleration equation for Λ>0.) By [L3] and step 1.1, (A) reads a¨/a=Λc2/3, and a¨/a=HΛ2=Λc2/3 by [L2]. Hence (A) holds on I.

2.3L2L3step 1.1algebra

(Continuity and spatial-component equations for Λ>0.) For ε=p=0 every term of (C) vanishes, so (C) holds identically. For (S), step 1.1 gives 2aa¨+a˙2=2a⋅HΛ2a+(HΛa)2=3HΛ2a2, hence −(2aa¨+a˙2)/c2+Λa2=−3HΛ2a2/c2+Λa2=−3(c2Λ/3)a2/c2+Λa2=0, which is (S) with zero pressure. This completes claim 1.

3.1step 2.1step 2.2step 2.3step 1.2∎

(Conclusion.) Steps 2.1, 2.2 and 2.3 verify (F), (A), (C) and (S) for the exponential datum of claim 1 on all of R, and step 1.2 proves the failure of (F) for every flat vacuum datum with Λ<0, which is claim 2. The verification used only differentiation of the exponential and the sign of a square; no field equation, no reference to the A page and no physical premise was used.

Remarks

  • What is checked. The example verifies the two sign regimes directly in the defining equations of The Friedmann, acceleration and continuity equations of an FLRW model datum: for Λ>0 the exponential datum satisfies all four scalar equations, and for Λ<0 the Friedmann equation alone is already unsatisfiable because a square cannot equal a negative number. The physical reading of the datum as a vacuum solution of the field law belongs to the A page and is not asserted here.

  • What is not claimed. No uniqueness of the solutions for Λ>0, no statement about the flat Λ=0 case, no numerical value of Λ or HΛ, and no physical claim about an expanding universe is made.

Depends on

Dependency tree · 2 levels

Sources