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Periodic Fourier differentiation identity and equivalence of the derivative and Fourier-weight Sobolev norms

Statement

Assume the Axiom of Countable Choice ACω (The Axiom of Countable Choice (ACω)). Let s≥0 be an integer, and let T2π3, μ, χk, u^(k), the weak derivatives Dα and the spaces Hs(T2π3;RN) be as in The 2 pi-periodic three-torus, its normalized measure, test functions and the Sobolev spaces H^s, and put Ns(u)2:=∑k∈Z3(1+∣k∣2)s ∣u^(k)∣2,∣k∣2:=k12+k22+k32.

(a) Let u∈Hs and let α∈N03 with ∣α∣≤s. Then Dαu∈Hs−∣α∣ and Dαu^(k)=(ik)α u^(k)(k∈Z3),(ik)α:=∏j=13(ikj)αj.

(b) Let u∈L2(T2π3;RN) satisfy Ns(u)<∞. Then u∈Hs(T2π3;RN), and there are constants 0<cs≤Cs<∞, depending only on s, such that cs Ns(u)2≤∥u∥Hs2≤Cs Ns(u)2. The right-hand inequality holds for every u∈Hs, so the two norms are equivalent on Hs.

Facts & Assumptions

Given: Countable Choice, an integer s≥0, the torus T2π3 with its normalized measure μ and characters χk, the weak derivatives Dα, and the spaces Hs.

[L1]

(χk)k∈Z3 is an orthonormal basis of the complex L2: for f,g∈L2 one has the norm and pairing identities ∥f∥22=∑k∣f^(k)∣2 and ⟨f,g⟩=∑kf^(k)g^(k)‾, the series converging absolutely, and the coefficient map is a surjective linear isometry onto ℓ2(Z3) (The Fourier basis and Parseval's identity on the finite torus, The 2 pi-periodic three-torus, its normalized measure, test functions and the Sobolev spaces H^s).

[L2]

v=Dαu means ∫u Dαφ dμ=(−1)∣α∣∫v φ dμ for every smooth test function φ; the real and imaginary parts of χl are smooth real tests; adding their test identities extends the identity complex-linearly to χl (The 2 pi-periodic three-torus, its normalized measure, test functions and the Sobolev spaces H^s).

[L3]

For a C1 function G on an interval [a,b], ∫abG′=G(b)−G(a): the derivative G′ is continuous, hence integrable, and the second fundamental theorem of calculus applies (The second fundamental theorem: if G is differentiable on [a,b] with G′=f and f is integrable, then ∫abf=G(b)−G(a), A continuous function on [a,b] is Riemann integrable, by Heine-Cantor and Riemann's criterion).

[L4]

Multinomial expansion: for any finite real tuple (x1,…,xd) and s∈N0, (x1+⋯+xd)s=∑∣γ∣=s(s!/γ!)xγ, over the finite set of d-component multi-indices. The coefficients are nonnegative integers and sum to ds, by taking all xi=1 (The multinomial coefficient equals n!/∏i<mki!, and (x0+⋯+xm−1)n=∑ι ⁣(nk)∏i<mxiki in R, Ck maps and multi-index derivative notation in Euclidean space).

Proof

technique · direct
1.1L2L3algebra

(One-variable periodic integration by parts.) For smooth 2π-periodic G,H and each j, ∫T2πG ∂jH dμT=−∫T2π(∂jG) H dμT: indeed ∫02π∂j(GH) dxj=(GH)∣02π=0 by the second fundamental theorem of calculus and periodicity [L3], and the product rule gives the claim; the remaining coordinates integrate out by the product-measure convention. Consequently, for every smooth φ, every k and every α, ∫χkDαφ dμ=(−1)∣α∣(ik)α∫χkφ dμ: induct on ∣α∣, moving one variable derivative from φ onto χk by the one-variable identity and using ∂jχk=ikjχk. In particular Dαχk=(ik)αχk in the weak sense of [L2], the case φ=χ−l tested against χk having Fourier coefficients χk^(l)=δkl.

1.2L4algebra

(The symbol bounds.) For k∈Z3 put qk:=∑∣α∣≤s∣kα∣2. Each term is at most (1+∣k∣2)s, and there are at most (s+1)3 terms, so qk≤(s+1)3(1+∣k∣2)s. Conversely, the multinomial expansion of (1+k12+k22+k32)s is ∑∣α∣≤scα∣kα∣2, where cα=s!/((s−∣α∣)!α!). These nonnegative integer coefficients sum to 4s by setting all four variables to 1, so every cα≤4s. It follows that (1+∣k∣2)s≤4sqk. This includes s=0, where both sides are 1. Hence 4−s(1+∣k∣2)s≤qk≤(s+1)3(1+∣k∣2)s.

2.1step 1.1L2algebra

(The differentiation identity (a).) If u∈Hs and ∣α∣≤s, then Dαu∈Hs−∣α∣: a weak derivative of Dαu of order ∣β∣≤s−∣α∣ is the weak derivative Dα+βu, because the defining test identity for the iterated derivative follows by applying the two defining identities in succession and noting that Dβφ is again a smooth test function. Testing the defining identity for Dαu against φ=χ−k gives Dαu^(k)=(−1)∣α∣∫u Dαχ−k dμ=(−1)∣α∣(−ik)α∫u χ−k dμ=(ik)αu^(k), where the middle equality uses step 1.1 for the smooth test function Dαχ−k=(−ik)αχ−k and the last uses (−1)∣α∣(−i)α=iα.

2.2step 1.2L1algebra

(The norm bounds for u∈Hs.) By Parseval [L1] applied to the L2 classes Dαu, ∥Dαu∥22=∑k∣kα∣2∣u^(k)∣2, so the definition of the Hs norm gives ∥u∥Hs2=∑kqk∣u^(k)∣2. Combining with step 1.2, ∥u∥Hs2≤(s+1)3Ns(u)2 and Ns(u)2≤4s∥u∥Hs2, which are the right-hand inequality and the converse inequality of (b) whenever u∈Hs.

3.1step 2.1L1L2algebra

(Converse direction of (b): the weighted series produce weak derivatives.) Let u∈L2 with Ns(u)<∞. For each ∣α∣≤s the sequence k↦(ik)αu^(k) is square-summable because ∣kα∣2≤(1+∣k∣2)∣α∣≤(1+∣k∣2)s; by the surjectivity of the coefficient isometry [L1] there is a unique class wα∈L2 with wα^(k)=(ik)αu^(k). Since u is real, u^(−k)=u^(k)‾ by conjugating its integral. Thus ak:=(ik)αu^(k) satisfies a−k=ak‾. Also wα‾^(k)=wα^(−k)‾=ak, again by conjugating the integral. Injectivity in [L1] gives wα‾=wα as L2 classes, so wα has a real-valued representative, componentwise. For a smooth real test φ, Parseval's pairing identity [L1] gives ∫u Dαφ dμ=∑ku^(k)Dαφ^(k)‾=∑ku^(k)(ik)αφ^(k)‾=∑k(−1)∣α∣(ik)αu^(k)φ^(k)‾=(−1)∣α∣∫wαφ dμ, where the second equality is step 2.1 applied to the smooth φ and the third uses (ik)α‾=(−i)αkα=(−1)∣α∣(ik)α. Hence Dαu=wα weakly for every ∣α∣≤s, so u∈Hs.

4.1step 3.1step 2.1step 2.2constructdischarge-construct∎

(Conclusion.) By step 3.1 and step 2.2, for u with Ns(u)<∞ the class lies in Hs and satisfies 4−sNs(u)2≤∥u∥Hs2≤(s+1)3Ns(u)2, so (b) holds with cs=4−s and Cs=(s+1)3, while (a) was proved in step 2.1.

Remarks

Depends on

Dependency tree · 2 levels

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