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Local mass balance: conservation on every material subregion implies ∂tρ+div⁡(ρu)=0

Statement

Assume the Axiom of Countable Choice ACω (The Axiom of Countable Choice (ACω)), as used by the transport theorem. Let I⊆R be a nonempty open interval, let B⊆R3 be a material region, let χ:I×O→R3 be a motion of B on I with spatial velocity u (Continuum motions, spatial velocity, material acceleration and swept regions), and let J0⊆I be an open interval with J0‾⊆I. Define the swept region

Σ:={(t,x):t∈J0‾, x∈χt(B‾)}.

Write Dχ:={(t,x):t∈I, x∈χt(O)} for the open domain of the spatial velocity u (Continuum motions, spatial velocity, material acceleration and swept regions). Let U⊆Dχ be open and contain the swept region Σ. Let ρ:U→(0,∞) be of class C1 (Ck Euclidean maps and diffeomorphisms); call it a density field. A material subregion is a nonempty bounded open B′⊆B with B′‾⊆B (Material regions, densities and their mass); for such B′ the same χ is a motion of B′.

(i) Localization. Assume for every material subregion B′ and every t∈J0

ddt∫χt(B′)ρ(t,x) dx=0,(CM)

It is sufficient to assume this identity only for those pairs (t,B′) for which χt(B′) is an open Euclidean ball with closure inside χt(B). Under either version of the conservation hypothesis,

∂tρ(t,x)+div⁡(ρu)(t,x)=0

for every (t,x)∈J0×χt(B), with the material derivative and divergence of Euclidean spatial calculus: gradient, divergence and material derivative.

(ii) Converse. Conversely, if ∂tρ+div⁡(ρu)=0 on an open neighbourhood of Σ in U, then (CM) holds for every material subregion B′ and every t∈J0.

Facts & Assumptions

Given: ACω; the motion χ; the open interval J0; the C1 density field ρ; the conservation hypothesis (CM) in (i), or the local equation in (ii).

[F1]

Transport theorem: for every material subregion B′ and every function f of class C1 on a neighbourhood of its swept region, ddt∫χt(B′)f=∫χt(B′)(∂tf+div⁡(fu)) at each t in the interior of the relevant interval (The transport theorem for a C2 family of diffeomorphisms: ddt∫ψt(B)f=∫ψt(B)(∂tf+div⁡(fw)), Continuum motions, spatial velocity, material acceleration and swept regions).

[F2]

Localization lemma: if H is continuous on an open W⊆R3 and ∫AH dx=0 for every member A of a family F of nonempty open subsets of W such that every point of W has members of F contained in each of its neighbourhoods, then H=0 on W (Localization: a continuous function whose integrals vanish over a neighbourhood-basis family is identically zero). The supporting order rule for the nonnegative Lebesgue integral and the positivity of box volumes are those cited there (Monotonicity and nonnegative homogeneity of the nonnegative integral, The Lebesgue integral is linear on L1(μ), A box in Rn with parameters ai≤bi is Lebesgue measurable of measure ∏i<n(bi−ai), whichever of its faces are included, Half-open boxes in Rn and their volume, Integral over a measurable subset).

[F3]

For each fixed t the map χt is a homeomorphism of O onto the open set χt(O) and is continuous at each point X0; every neighbourhood of y0=χt(X0) contains the image of a sufficiently small box around X0 (Continuum motions, spatial velocity, material acceleration and swept regions, Open ball, closed ball and sphere in a metric space, Half-open boxes in Rn and their volume).

Proof

technique · direct; transport the vanishing integral to the reference region, then localize with an elementary open-set argument
1.1givenF1algebra

Assume (CM), either on all material subregions or on the stated current-ball test pairs. Fix a test pair (t,B′) to which the chosen hypothesis applies. The domain of f:=ρ is the open set U, which contains Σ, and ρ is C1, so [F1] applies to the motion of B′ and gives 0=ddt∫χt(B′)ρ(t,x) dx=∫χt(B′)(∂tρ+div⁡(ρu))(t,x) dx.

2.1step 1.1givenF3construct

Put H:=∂tρ+div⁡(ρu), a continuous function on the common open field domain. Fix t∈J0 and an open ball A with A‾⊆Wt:=χt(B). Its preimage B′:=χt−1(A) is nonempty, open and bounded; indeed χt−1(A‾) is compact and contained in B, so B′‾⊆B. Thus B′ is a material subregion and (t,B′) is a permitted current-ball test pair. Step 1.1 gives ∫AH(t,⋅) dx=0.

3.1step 2.1F2F3construct

The family Ft of all open balls with closures in the open Wt contains, around each point, a member inside any prescribed neighbourhood: choose a sufficiently small positive radius. Step 2.1 gives vanishing integrals on every member. Applying [F2] to the continuous function H(t,⋅) and this family yields H(t,y)=0 for every y∈Wt.

4.1step 1.1step 3.1F1F4algebra∎

Steps 1.1 and 3.1 prove (i): for every t∈J0 and every y0∈χt(B), ∂tρ+div⁡(ρu)=0 at (t,y0). Conversely, if ∂tρ+div⁡(ρu)=0 on a neighbourhood of Σ, then for every material subregion B′, [F1] applies to f=ρ on the swept region of B′ (contained in Σ), and its integrand vanishes identically, so the derivative in (CM) is zero for every t∈J0. This proves (ii).

Remarks

  • Positivity of ρ is part of the density reading and is not used by the implication (i); only C1 regularity on U and the conservation hypothesis enter. The converse also uses only the stated regularity.

  • The two implications are conditional on the adopted conservation law (CM) or on the local equation; neither direction asserts that a physical density is conserved. Localization needs the full stated neighbourhood family: all small current balls suffice. Conservation on only one chosen region is insufficient.

  • The statement is local in the current region: it concludes the equation at every point of χt(B) for t∈J0, and says nothing on ∂χt(B) or at the endpoints of I, where the transport theorem is not asserted.

Depends on

Dependency tree · 2 levels

Sources