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Counterexamples to both centered-adjacency tail bounds in Corollary 6.6

PDF p. 35: Corollary 6.6; equations (6.5), (6.6)

Statement

Both bounds stated in the original Corollary 6.6 are false under their complete displayed quantifiers, for the loop-free independent-edge graph and the article's centering ΔA=A−pJ.

First, the original assertion is that for every p∈(0,1) and n≥1000, P(∥ΔA∥≥4np(1−p)+4+t)≤2exp⁡(−t2/4)(t>0). At n=4146144!, p=1/n, t=3, its left side is at least 4/5 and its right side is at most 8/13.

Second, the original assertion is that for every fixed γ>0 there is n0(γ) such that, whenever p=γlog⁡n/n and n≥n0(γ), P(∥ΔA∥≥8γlog⁡n)≤2n−γ. At the single fixed value γ=10−6, every even integer n with log⁡n≥2000000 violates this inequality: the left side exceeds 1/2, while the right side is at most 2/5. The left side in fact tends to one through even n→∞. Thus no choice of n0(10−6) can make the second assertion true. Norms are Euclidean operator norms, J is the all-ones matrix, and n−γ=exp⁡(−γlog⁡n).

Facts & Assumptions

[F1]

The random graph is the loop-free law with independent Bernoulli edges (The Erdős-Rényi finite random graph G(n,p)).

[F2]

The article centers it as ΔA=A−pJ (Centered graph matrices and reference degree).

[F3]

At n=4k+2k! and p=1/n, a vertex of degree at least k occurs with probability at least 4/5 (A large degree with explicitly bounded probability at fixed sparse density).

[F4]

A degree of at least k gives ∥A−J/n∥≥k−1 (A high-degree vertex forces a large centered adjacency norm).

[F5]

For γ=10−6 and every even n with log⁡n≥2000000, the logarithmic tail probability exceeds 1/2>2/5≥2n−γ and tends to one (The proposed small-gamma centered-adjacency tail has the opposite limit).

[F6]

The exponential series gives exp⁡(x)≥1+x for x≥0 (The real exponential function and the number e by a power series).

[F7]

The exponential is positive and exp⁡(−x)=1/exp⁡(x) (The exponential is positive and satisfies exp(-x)=1/exp(x)).

[F8]

Every real number has an integer ceiling at least as large as itself (Ceilings give the least positive integer meeting a real threshold).

[F9]

The factorial k! is the product of the integers from 1 to k (The factorial n! and the falling factorial n^k̲, defined by recursion in ℕ).

[F10]

The logarithm is inverse to the exponential (The natural logarithm as the inverse of the exponential function).

[F11]

The exponential is strictly increasing (The exponential function is strictly increasing).

[F12]

For a matrix B acting on Rn with its Euclidean inner product, ∥B∥=max⁡∥v∥2=1∥Bv∥2 (The operator norm is zero on the zero domain and otherwise is max_‖ v‖=1‖ Tv‖).

[F13]

On a finite probability space (Ω,w), each outcome weight w(ω) is nonnegative and every subset E⊆Ω is an event with probability P(E)=∑ω∈Ew(ω) (Finite probability spaces, outcome weights, events, and event probabilities).

[F14]

In a finite simple graph, the degree of a vertex is the number of its neighbors, and the maximum degree is the largest of these numbers when the vertex set is nonempty (Adjacency, incidence, open and closed neighbourhoods, vertex degree, minimum degree and maximum degree).

Proof

Given: The objects and hypotheses in the Statement.

Goal: Prove the asserted conclusions.

1.1F1F2F3F4F6F7F9F12F13F14givenalgebra

For the first inequality take k=144, n=4146144!, p=1/n, t=3. These satisfy n≥1000, 0<p<1 and t>0. Let E be the event that some vertex has degree at least 144, and let T be the norm event in the first displayed inequality. By [F14], having at least 144 neighbors is exactly having degree at least 144, so [F3] gives P(E)≥4/5. On E, [F4] gives ∥ΔA∥≥11, while the asserted threshold equals 41−1/n+7<11, so E⊆T. By [F13], P(T)=P(E)+∑ω∈T∖Ew(ω)≥P(E) because all outcome weights are nonnegative. Thus the event in the first displayed inequality has probability at least 4/5. By [F6] and [F7], its proposed bound 2exp⁡(−9/4) is at most 2/(1+9/4)=8/13<4/5. This is a concrete counterexample to equation (6.5).

2.1F1F2F5F8F10F11F12givenconstruct∎

For the second inequality fix γ=10−6 once and for all. Apply [F5] at every even integer n with log⁡n≥2000000. These are applicable counterexamples with valid graph probabilities. Given any proposed cutoff n0(10−6), put B=max⁡{1,n0(10−6),exp⁡(2000000)} and choose n=2⌈B/2⌉+2. By [F8] this is an even positive integer greater than B. By [F10] and [F11], log⁡n>2000000. Increasing B gives arbitrarily large such integers. The contradiction therefore persists beyond every cutoff. The limit in [F5] also proves the stated asymptotic behavior, rather than merely failure at a bounded set of sizes.

Source notes

The original PDF p. 35, Corollary 6.6, states (6.5) “For any p∈(0,1) and n≥1000” and (6.6) “for every γ>0, there is n0(γ)”. Both complete claims are retained above and refuted separately. The original page image and extracted text were inspected, together with Section 1.2, PDF p. 6, fixing the centering and norm. The sparse-degree and logarithmic-tail lemmas supply independent local counterexamples. No concentration theorem or expected-norm claim is used as a premise. This result refutes the unrestricted γ>0 statement, not every possible larger-γ variant, and it does not by itself refute the article's main synchronization statements, which impose other parameter ranges.

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