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Thermal bath spectral density and frequency signs

PDF p. 13: Eq. (S3.14)

Statement

Assume the Axiom of Choice, Countable Choice and Dependent Choice, and all hypotheses and normalization conventions of Isotropic thermal bath time correlator. In particular, c,β,γ>0, κ is Borel, and M=∫0∞∣κ(ω)∣2ω2[2(eβω−1)−1+1]dω<∞. Put N(ω)=(eβω−1)−1 and A=8π/(3γc3).

Use the positive-exponential spectral convention of Bath correlation matrix and Fourier convention, extended distributionally as follows: for a Schwartz test function φ on R, pair the spectrum with φ by (2π)−1∫RJαα(t)∫Rφ(x)eixtdx dt. A Schwartz function is a smooth function whose derivatives, multiplied by arbitrary powers of its argument, are bounded. Then this spectrum is the finite measure

Jαα(dx)=A∫0∞∣κ(ω)∣2ω2{N(ω)δ−ω(dx)+[N(ω)+1]δω(dx)} dω.

Here δa is unit point mass at a. Its Lebesgue density may be represented, for x≠0, by

J(x)=Ax2[∣κ(−x)∣2N(−x)Θ(−x)+∣κ(x)∣2(N(x)+1)Θ(x)],

where a term is evaluated only when its Heaviside factor is one and Θ(x)=1 for x>0, Θ(x)=0 for x<0. The value at zero is arbitrary. This representative describes the measure almost everywhere; no pointwise Fourier-integral identity or value at zero is asserted without further regularity. The correlation need not be integrable in time.

Facts & Assumptions

Given: The model, regulator limit, choice assumptions and integrable radial envelope in the Statement.

[F1]

The completed time-correlator supplier gives Jαα(t)=A∫0∞∣κ(ω)∣2ω2[N(ω)eiωt+(N(ω)+1)e−iωt]dω under these hypotheses. Isotropic thermal bath time correlator

[F2]

The ordinary bath spectral convention has the positive exponential and factor (2π)−1; it requires time integrability. Bath correlation matrix and Fourier convention Stationary correlation spectra and ULE kernel regularity

[F3]

Schwartz Fourier inversion holds with the supplier's 2π convention, and Schwartz functions and their derivatives are integrable. Fourier inversion on Schwartz space Schwartz derivatives are integrable

[F4]

Tonelli's theorem evaluates the nonnegative product integral, and Fubini's theorem permits interchange for an absolutely integrable function on a sigma-finite product. Tonelli's theorem for nonnegative measurable functions on a sigma-finite product Fubini's theorem for L¹ functions on a sigma-finite product

[F5]

On any measure space, a nonnegative measurable function f defines a measure by E↦∫Ef. The indefinite integral of a nonnegative measurable function is a measure

[F6]

Under Countable Choice, a C1 diffeomorphism T:U→V between open subsets of Euclidean space satisfies ∫Vf=∫U(f∘T)∣det⁡DT∣ for f∈L1(V). Change of variables for integrable functions

[F7]

For real u, eiu=cos⁡u+isin⁡u, and (sin⁡u)′=cos⁡u, (cos⁡u)′=−sin⁡u. Under Countable Choice the Lebesgue fundamental theorem gives ∫abv′=v(b)−v(a) for every complex C1 function v on [a,b]. exp(x+iy)=eˣ(cos y+i sin y), |exp(x+iy)|=eˣ, and e^iπ+1=0 The derivatives of sine and cosine are cosine and minus sine Complex integration by parts on intervals and decaying lines

[F8]

The quarter-turn values include cos⁡0=1, cos⁡π=−1, and cos⁡(u+π)=−cos⁡u; hence cos⁡(kπ)=(−1)k for each nonnegative integer k. The derivatives of sine and cosine are cosine and minus sine Quarter-turn values and shifts by pi/2 and pi

Proof

Goal: Establish the distributional frequency-sign formula and its almost-everywhere density, with the stated normalization.

1.1givenF5F6A1constructalgebra

On (0,∞) put w−(ω)=∣κ(ω)∣2ω2N(ω) and w+(ω)=∣κ(ω)∣2ω2[N(ω)+1]. These are nonnegative Borel functions with ∫0∞(w−+w+)=M<∞, so each is integrable. Define J∗(x)=Aw−(−x) for x<0, J∗(x)=Aw+(x) for x>0, and J∗(0)=0. The reflection T:(−∞,0)→(0,∞), T(x)=−x, is a C1 diffeomorphism with ∣T′(x)∣=1. Apply [F6] to w− on these open half-lines to obtain ∫−∞0w−(−x)dx=∫0∞w−(ω)dω. Thus J∗ is nonnegative Borel and integrable, with integral AM. By [F5], μ(E)=∫EJ∗(x)dx is a finite measure. For any Borel E⊆R, the function fE(ω)=w−(ω)1E(−ω) is Borel and bounded in absolute value by w−, hence is in L1(0,∞). Applying the same reflection to fE gives μ(E)=A∫0∞[w−(ω)1E(−ω)+w+(ω)1E(ω)]dω. This is exactly the stated point-mass mixture, now with countable additivity supplied by [F5].

1.2givenF1F7A1constructalgebra

To establish the possible failure of time integrability, fix any c,β,γ>0 and take the real Borel coupling κ(ω)=1(0,1)(ω)/(ω2N(ω)+1) for ω>0. Its denominator is strictly positive and finite at every positive frequency. Assign κ(0)=0 if a value at zero is wanted. Its thermal envelope is exactly 1(0,1), so M=1 and [F1] applies with the supplier's specified regulators and normalization (one may take d0=1 and E=κ). Write C(t)=Jαα(t) for this coupling. Taking real parts in the absolutely convergent frequency integral of [F1] and using [F7] gives Re⁡C(t)=A∫01cos⁡(ωt)dω=Asin⁡t/t for t≠0, by applying the Lebesgue fundamental theorem to v(ω)=sin⁡(ωt)/t on [0,1]. At t=0 the same real part is A. Thus ∣C(t)∣≥A∣sin⁡t∣/t for t>0.

2.1F1F3F4F6A1step 1.1algebra

Let φ be a Schwartz test function and write h(t)=∫Rφ(x)eixtdx. The first integral exists by [F3]. In the Fourier supplier's convention, φ^(ξ)=∫Rφ(x)e−2πixξdx and h(t)=φ^(−t/(2π)). The absolute-convergence assertion in [F3] implies φ^∈L1(R). The map T:R→R, T(t)=−t/(2π), is a C1 diffeomorphism with ∣T′∣=(2π)−1, so [F6] applied to ∣φ^∣ gives ∫R∣h(t)∣dt=2π∫R∣φ^(ξ)∣dξ<∞. After inserting [F1] into the spectral pairing, the absolute value of its double integrand is bounded by A∣h(t)∣[w−(ω)+w+(ω)]. These are product-measurable functions on the sigma-finite Lebesgue spaces R and (0,∞). Tonelli in [F4] gives the bound AM∫∣h∣<∞ on the product integral. Fubini in [F4] therefore permits interchange of time and positive frequency, and the stated pairing is finite.

3.1F1F2F3F6step 1.1step 2.1algebra

Apply [F6] with the same real-line diffeomorphism to f(ξ)=φ^(ξ)e−2πiωξ and to f(ξ)=φ^(ξ)e2πiωξ, each integrable because the exponential has modulus one. Fourier inversion [F3] then gives (2π)−1∫Rh(t)eiωtdt=φ(−ω) and (2π)−1∫Rh(t)e−iωtdt=φ(ω). Thus the spectral pairing equals A∫0∞[w−(ω)φ(−ω)+w+(ω)φ(ω)]dω. Apply the half-line reflection in [F6] to w−(ω)φ(−ω), which is integrable since a Schwartz function is bounded, to identify this expression with ∫RJ∗(x)φ(x)dx. Hence the distributional spectrum is the finite measure constructed in step 1.1. The factor 2π from inversion cancels the convention's (2π)−1; the factor γ−1 remains from [F1].

4.1step 1.1step 3.1algebra

Expanding w− and w+ in J∗ gives the displayed Heaviside density on the respective open half-lines, with each term evaluated only there. Its value at the Lebesgue-null singleton zero is immaterial; in particular μ({0})=0. This proves the almost-everywhere density assertion while allowing any assigned value at zero.

5.1F1F5F7F8A1step 1.2algebra∎

For each integer k≥1, [F7] and [F8] give ∫kπ(k+1)π∣sin⁡t∣dt≥∣∫kπ(k+1)πsin⁡t dt∣=∣cos⁡(kπ)−cos⁡((k+1)π)∣=2. Since t≤(k+1)π on that interval, step 1.2 implies ∫kπ(k+1)π∣C(t)∣dt≥2A/((k+1)π). If C belonged to L1(R), then ∣C∣ would be measurable with finite integral and [F5] would make E↦∫E∣C(t)∣dt a finite measure. The intervals can be made disjoint by omitting endpoints, which have zero Lebesgue integral. For every m≥0, summing over 2m≤k<2m+1 gives a lower bound 2m 2A/(2m+1π)=A/π. Finite additivity and monotonicity therefore bound the integral of ∣C∣ over the first L such disjoint blocks below by LA/π for every positive integer L. Since A>0, the full time integral is infinite. This proves the Statement's nonintegrability possibility without altering its distributional spectrum.

Source notes

The original article's Eq. (S3.14) states the same two frequency signs with prefactor 8π/(3c3), equivalently 8π3c3x2[∣κ(−x)∣2N(−x)Θ(−x)+∣κ(x)∣2(N(x)+1)Θ(x)]. In the completed time-correlator supplier, the explicitly retained bath-operator normalization gives the additional factor γ−1; the article-prefactor expression is therefore the spectrum of γJαα in that convention, and agrees with this item when γ=1. The article citation supplies attribution, not proof of this conditional calculation.

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