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Theorem 1.1: exact outer boundary controllability

PDF p. 4: Theorem 1.1; (1.7); PDF p. 16: proof begins; PDF p. 17: proof concludes

Statement

Assume the Axiom of Choice. Let n∈{2,3} and let Θ⊂Rn be a nonempty compact obstacle with smooth boundary, connected exterior Ω=Rn∖Θ, and non-trapping generalized reflected and glancing rays: each such ray leaves every compact set in finite forward time. Choose R0>0 with Θ⊂BR0(0) and set Ω0=BR0(0)∖Θ, Γ1=∂BR0(0) and Γ2=∂Θ.

Let T>0, s∈{1,2} and λ∈R∖{0}. Write Xs(Ω0)={f∈Hs(Ω0):γΓ2f=0}, with the inherited Hs norm; γ denotes the Sobolev value trace. Then there is δ>0 such that, for every u0,u1∈Xs(Ω0) with ∥u0∥Hs,∥u1∥Hs≤δ, there are u∈C([0,T];Hs(Ω0)) and h∈C([0,T];Hs−1/2(Γ1)) satisfying

i∂tu+Δu+λ∣u∣2u=0in D′((0,T)×Ω0),

with u(0)=u0, u(T)=u1, γΓ1u=h, and γΓ2u=0. The boundary equalities are Sobolev trace equalities at every time, and C([0,T];Y) means norm-continuous paths in Y.

Facts & Assumptions

[F1]

The geometry and non-trapping convention are those of Exterior and truncated obstacle domains and Non-trapping obstacle. The state space and trace convention are those of States compatible with the uncontrolled obstacle boundary, the boundary equation is that of Cubic NLS and boundary control formulations, and time continuity and distributional equality have the meanings in Continuous and mixed time-space function spaces and Distributional equation convention for complex Schrödinger solutions. The assumed choice principle is The Axiom of Choice.

[F2]

Under these geometric and Choice hypotheses, Lemma 3.11: extension preserving the obstacle Dirichlet condition supplies a bounded linear extension E:Xs(Ω0)→HDs(Ω) with (Ef)∣Ω0=f. Here Dirichlet spectral Sobolev scale and duality defines HDs(Ω)=D((I−ΔD)s/2) with its spectral norm, and Low-order identifications of the Dirichlet scale identifies it with Hs(Ω)∩H01(Ω) for the present s, with equivalent norms.

[F3]

For R=R0+1, Control region and nested real cutoffs supplies a smooth cutoff φ equal to zero on ∣x∣≤R, positive on ∣x∣>R, and one on ∣x∣≥R+1. With this cutoff and m=3, Theorem 1.3: cubic internal control near zero gives a positive exterior endpoint radius and an integral solution and control continuous in HDs for every pair of exterior endpoints inside that radius. The controlled equation is specified by Linear and nonlinear internally controlled exterior systems.

[F4]

The integral-solution convention in Mild formulation of the controlled power NLS requires g(v)=λ∣v∣2v and φk to be Bochner integrable in X=HDs(Ω). Writing f=ig(v)−iφk, B for the generator on X, and qX(t)=∫0tv(r) dr, it gives qX(t)∈D(B) and v(t)=v(0)+BqX(t)+∫0tf(r) dr. The group on X is the consistent extension of W(t)=eitΔD on L2(Ω) by Scale isometries and free Schrödinger evolution.

[F5]

The Dirichlet realization in Dirichlet Laplacian and positive shift is self-adjoint on L2(Ω), with D(ΔD)=H2(Ω)∩H01(Ω), and its action there is the weak spatial Laplacian. Since A=I−ΔD≥I, the spectral norm in Dirichlet spectral Sobolev scale and duality gives the bounded inclusion J:X→L2(Ω): ∥Jw∥2≤∥w∥X. For this self-adjoint ΔD, Flow calculus of a self-adjoint generator: commutation, invariance and differentiability, part (a), identifies the full L2 generator domain of W with D(ΔD) and the generator with iΔD. That supplier has domain mathematics, assumes AC and Countable Choice, and uses no physical premise; both choice hypotheses follow from the assumed AC.

[F6]

On the smooth bounded truncated domain Ω0, Collar traces and extension across an artificial boundary supplies the bounded trace H1(Ω0)→H1/2(Γ2), agreeing with classical restriction on smooth functions. Its traces at orders 1≤s≤2 agree in L2(Γ2) with this first-order trace and are local, so restriction from an exterior collar gives the same obstacle trace.

[F7]

Bounded linear maps commute with Bochner integration applies to the bounded inclusion J and to bounded spatial test functionals on L2. Holder's inequality for integrals, including the endpoint cases, applied to absolute values with exponents 2,2, gives ∥a∥L1(K)≤∣K∣1/2∥a∥2 on every spatial set K of finite measure. Fubini's theorem for L¹ functions on a sigma-finite product permits exchanging the integrals of absolutely integrable complex functions on the Lebesgue time and space products used below. The time interval is finite, spatial test supports are compact, and these measures are sigma-finite.

[F8]

Transfer from exterior internal control to outer boundary control transfers an exterior solution satisfying the distributional equation, local integrability and zero obstacle trace, together with its endpoint values and outer trace, to the stated boundary problem when the cutoff vanishes on Ω0.

Proof

Given: The hypotheses and endpoint data in the Statement.

Goal: Construct a boundary control and a solution with the prescribed endpoints, equation and traces.

1.1F2F3given

Choose R=R0+1 and the cutoff in F3. Let δ1>0 be the radius supplied there, and let E be the extension in F2. The operator norm ∥E∥ is positive: a nonzero smooth function compactly supported in Ω0 belongs to Xs(Ω0) and is recovered by restriction after applying E. Set δ=δ1/∥E∥. Then ∥Euj∥HDs≤δ1 for j=0,1.

2.1F3F4F5F7step 1.1

Apply F3 to the extended endpoints. It supplies k,v∈C([0,T];X) with v(0)=Eu0 and v(T)=Eu1, where X=HDs(Ω), and the integral-solution identity in F4. Retain its notation f=iλ∣v∣2v−iφk and qX(t)=∫0tv(r) dr. In particular g(v),φk,f∈L1(0,T;X). By the inclusion J and the local estimate in F7, their L2 realizations, and also the continuous L2 paths v and k, have jointly measurable, locally integrable space-time representatives. For example, for compact K⊂Ω, ∫0T∫K∣Jf(t,x)∣ dx dt≤∣K∣1/2∫0T∥f(t)∥X dt. Jointly measurable local representatives can be obtained from Bochner simple approximations, which converge in local space-time L1 by the same estimate.

3.1F4F5F7step 2.1

Fix t and put q(t)=JqX(t)=∫0tJv(r) dr, where the equality is F7. Since qX(t)∈D(B), its right group difference quotient converges in X to BqX(t). Applying J and the consistency in F4 gives convergence of the same quotient in L2 to JBqX(t). For a unitary group a right limit is also the left limit: for h>0, (W(−h)q−q)/(−h)=W(−h)(W(h)q−q)/h, and strong continuity preserves the limit. Thus the full generator identification in F5 gives q(t)∈D(ΔD) and JBqX(t)=iΔDq(t). Applying J to the integral identity therefore yields Jv(t)=Jv(0)+iΔDq(t)+p(t) in L2, where p(t)=∫0tJf(r) dr. On this full domain, ΔDq(t)=Δxq(t) in spatial distributions by F5.

3.2F2F6step 2.1

Fix any t∈[0,T]. By F2, v(t)∈H01(Ω), so there are wj∈Cc∞(Ω) converging to v(t) in H1(Ω). Their restrictions converge to v(t)∣Ω0 in H1(Ω0): every whole-space H1 representative of their difference from v(t) on Ω is also a representative on Ω0, so restriction cannot increase the quotient norm. Each wj vanishes near Γ2, so its classical trace there is zero. Boundedness of the first-order trace in F6 makes the H1/2(Γ2) trace of v(t)∣Ω0 zero. Since v(t)∣Ω0∈Hs(Ω0) and the order-s trace agrees in L2 with that first-order trace, its Hs−1/2(Γ2) trace is zero as well. Trace locality identifies this with the exterior obstacle trace. This argument applies separately at every t, including the endpoints, and requires no convergence of wj in H2.

4.1F1F5F7step 2.1step 3.1

The primitives in step 3.1 satisfy ∂tq=Jv and ∂tp=Jf in space-time distributions. Explicitly, for a=Jv or a=Jf, Pa(t)=∫0ta(r) dr and arbitrary η∈Cc∞((0,T)×Ω;C), bounded spatial test functionals and Fubini give ∫0T∫ΩPa(t,x)∂tη(t,x) dx dt=∫0T∫Ωa(r,x)(∫rT∂tη(t,x) dt) dx dr=−∫0T∫Ωa(r,x)η(r,x) dx dr. Absolute integrability follows from the estimate in step 2.1, the finite time interval, and boundedness of the test function and its derivative. This calculation uses the bilinear distribution pairing, with no conjugation. The L2 identity in step 3.1 also gives Δxq=(Jv−Jv(0)−p)/i as a locally integrable space-time distribution. Differentiating that identity, commuting spatial and temporal distributional derivatives, and using the two primitive identities gives ∂tv=iΔxv+f. Multiplication by i and the definition of f give i∂tv+Δxv+λ∣v∣2v=φk in distributions. No assertion that v(t) itself lies in D(ΔD) is used.

5.1F1F8step 1.1step 2.1step 3.1step 4.1step 3.2∎

The cutoff vanishes on Ω0, since R>R0. Steps 2.1, 3.1, 3.2 and 4.1 verify local integrability, the exterior distributional equation and zero obstacle trace, so all hypotheses of the boundary-transfer proposition in F8 hold for v,E and m=3. It gives u=v∣Ω0 and h=γΓ1v with the asserted path regularity, endpoint values and boundary traces, and with the unforced cubic equation in distributions on (0,T)×Ω0. These are precisely the conditions in the Statement.

Source notes

The frozen article is cited for attribution of Theorem 1.1 and its extension-and-restriction reduction. The proof above uses the separately supplied internal-control theorem, extension and transfer proposition; it does not use the article's boundary-control claim as a premise.

The integral-to-distribution and zero-trace bridges above are local arguments using the declared mathematical suppliers, including a Physics Library item whose actual domain is mathematics. The article citation is used only for original-theorem attribution; no prerequisite is imported from the article and no independent acceptance is claimed.

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