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✓ 3 results · all verified · 3 also independently AI-judged
Every result on this page is machine-checked by a proof checker and read in full and owner-audited; the judge is an additional, independent cross-model AI review of the proofs; all 3 also cleared it.

Real Forms and Reflection Geometry

1 · Prerequisites

2 · Summary

Reflections require a form and a nonisotropic normal, not an unstated Euclidean structure. This page begins with finite-dimensional real vector spaces and distinguishes positive-definite, indefinite and degenerate forms before assigning any chamber interpretation.

The real Coxeter form, its radical, reflections, and form-preserving maps fixes a finite set S, a Coxeter matrix m and the real vector space V=RS, and defines the Coxeter form B on the basis es by B(es,es)=1 and B(es,et)=−cos⁡(π/m(s,t)) (and −1 when m(s,t)=∞), together with its radical, its B-preserving linear maps and the reflection ra(v)=v−2B(v,a)a/B(a,a) for B(a,a)≠0. Neither positive definiteness nor nondegeneracy is presumed, and ra is left undefined for null a. Reflections: involutivity, form invariance, fixed hyperplane, and exact rank-two order proves that this form is well defined, that every ra is a B-preserving linear involution with fixed hyperplane ker⁡B(−,a), and computes the rank-two plane Res+Ret: the Gram matrix (1−c−c1) is positive definite for finite m (the square-sum identity (xs−cxt)2+sin⁡2(π/m) xt2) and positive semidefinite with radical R(es+et) for m=∞; the product rsrt has determinant 1, exact order m for finite m (trace 2cos⁡(2π/m)) and is unipotent of infinite order for m=∞.

The canonical reflection homomorphism, roots, reflections, and the positive cone names the canonical reflection homomorphism ρ:W→GL(V) with ρ(s)=rs through the universal property of the presented Coxeter group, together with the roots Φ, the reflections T and the positive and negative cones; Descent of the reflection representation, unit root norms, and conjugation of reflections verifies the relators, proves existence and uniqueness of ρ, shows that every root has B-norm 1 and that ρ(wsw−1)=rρ(w)es. Positivity, faithfulness, discreteness and nondegeneracy are deliberately left to later pages.

The dual action, chambers, faces, and root hyperplanes passes to the algebraic dual V∗ with the contragredient action (w⋅f)(v)=f(ρ(w)−1v) — used even when B is degenerate — and defines the closed chamber, its interior, the faces CI and the root hyperplanes Hα. The dual action, the faces, and the rank-two chamber tiling verifies the action axioms, exhibits every face CI explicitly and proves the rank-two chamber structure: the finite case tiles P∗ by 2m sectors on which Ws,t acts simply transitively, and in the infinite case the chambers have pairwise disjoint interiors with union {φ:φ(es+et)>0}∪{0} — the closed half-plane {φ:φ(es+et)≥0} with the nonzero points of its boundary line removed — and wall traces on {φ:φ(es+et)=1} exactly the integers. All six items are choice-free. Their worked examples are collected on real-forms-and-reflection-geometry-examples.

3 · Logical flowchart

4 · Definitions, theorems and proofs

DefinitionDefinition: Literature-sourcedProof: Not applicablejudge pass (gpt-6.1-sol)audited 2026-10-08Open item page →

The real Coxeter form, its radical, reflections, and form-preserving maps

Definition

Let S be a finite set and let m be a Coxeter matrix on S, so that m(s,s)=1 and m(s,t)=m(t,s)∈{2,3,… }∪{∞} for s≠t (Coxeter matrices, the presented Coxeter group, reduced words, length, and standard parabolic subgroups).

(1) The space and its distinguished functions. Let V:=RS be the real vector space of all functions S→R, with pointwise operations (The vector space FX of all functions X→F with pointwise operations, and Fn as the case X=n={0,1,…,n−1}); it is a vector space over the ordered field R (The reals form a totally ordered field). Write u(s) for the value of u at s and put es(s):=1, es(t):=0 for t≠s.

(2) The Coxeter form. For finite m(s,t) put c(s,t):=cos⁡(π/m(s,t)) (Sine and cosine defined by their real power series, Pi as twice the smallest positive zero of cosine) and for m(s,t)=∞ put c(s,t):=1; then c(s,t)=c(t,s) and c(s,s)=cos⁡π=−1. The Coxeter form B is the unique symmetric bilinear form on V with B(es,et)=−c(s,t) for all s,t∈S; in particular B(es,es)=1 and B(es,et)=−cos⁡(π/m(s,t)) for finite m(s,t), while B(es,et)=−1 when m(s,t)=∞ (Bilinear forms, and symmetric, skew-symmetric, and alternating bilinear forms, Bilinear forms on V correspond linearly and bijectively to linear maps V→V∗). No positive definiteness, definiteness or nondegeneracy of B is presumed: rad⁡(B):={u:B(u,v)=0 for all v∈V} may be nonzero (The matrix, left and right radicals, rank, and nondegeneracy of a bilinear form on a finite-dimensional space), and the form may be indefinite (Positive and negative definiteness, the inertia (p,q,r), rank p+q, and signature p−q of a real symmetric bilinear or quadratic form). A linear map g:V→V is B-preserving when B(gu,gw)=B(u,w) for all u,w∈V.

(3) Reflections. For a∈V with B(a,a)≠0 define the reflection with normal a by ra(v):=v−2B(v,a)B(a,a)a. The definition asserts neither that ra is linear or an involution nor that ker⁡B(−,a)={v:B(v,a)=0} is a hyperplane; these are proved in Reflections: involutivity, form invariance, fixed hyperplane, and exact rank-two order ↗. When B(a,a)=0 the symbol ra is not defined.

LemmaStatement: Literature-sourcedProof: AI-adaptedprecheck passjudge pass (gpt-6.1-sol)audited 2026-10-08Open item page →

Reflections: involutivity, form invariance, fixed hyperplane, and exact rank-two order

Statement

Let S, m, V=RS, B and ra be as in The real Coxeter form, its radical, reflections, and form-preserving maps.

(1) Well-definedness of B. The functions es (s∈S) form a basis of V, and there is exactly one symmetric bilinear form B on V with B(es,et)=−cos⁡(π/m(s,t)) for finite m(s,t) and B(es,et)=−1 for m(s,t)=∞; it satisfies B(u,w)=∑s,t∈Su(s)w(t)B(es,et) for all u,w∈V.

(2) Reflection identities. Let a∈V with B(a,a)≠0. Then ra is linear, ra2=idV, ra(a)=−a, ra(v)=v for every v with B(v,a)=0, and B(rau,raw)=B(u,w) for all u,w∈V. Moreover ker⁡B(−,a) is a linear subspace of dimension dim⁡V−1 (a hyperplane of V, in the codimension-one sense) and is fixed pointwise by ra.

(3) The rank-two plane. Let s≠t in S, put P:=Res+Ret and c:=c(s,t) as in The real Coxeter form, its radical, reflections, and form-preserving maps (so c=1 when m(s,t)=∞). Then:

(i) B∣P has Gram matrix (1−c−c1); for finite m it is positive definite, with B(xses+xtet, xses+xtet)=(xs−cxt)2+sin⁡2(π/m) xt2; for m=∞ it is positive semidefinite, i.e. B(x,x)≥0 for all x∈P, with radical R(es+et).

(ii) rs and rt fix every element of P⊥={v∈V:B(v,es)=B(v,et)=0} pointwise; and if m<∞ then V=P⊕P⊥.

(iii) The product A:=rsrt has, in the ordered basis (es,et) of P, the matrix A=(4c2−1−2c2c−1), of determinant 1.

(iv) If m<∞ then tr⁡A=2cos⁡(2π/m), Am=idV, and Ak≠idV for 0<k<m. If m=∞ then A=idP+N on P for some N with N≠0 and N2=0; hence (rsrt)k∣P=idP+kN for every k∈Z, so rsrt has infinite order on V.

Facts & Assumptions

Given: a finite set S, a Coxeter matrix m on S, the real vector space V=RS, the Coxeter form B and the maps ra defined for B(a,a)≠0 of The real Coxeter form, its radical, reflections, and form-preserving maps, and, for the rank-two clauses, distinct s,t∈S with c:=c(s,t).

[F1]

The data fixed by the Statement: m(s,s)=1 and m(s,t)=m(t,s)∈{2,3,… }∪{∞} for s≠t; es∈V is the function with es(s)=1 and es(t)=0 for t≠s; and c(s,t)=cos⁡(π/m(s,t)) for finite m(s,t), while c(s,t)=1 when m(s,t)=∞ (The real Coxeter form, its radical, reflections, and form-preserving maps, The vector space FX of all functions X→F with pointwise operations, and Fn as the case X=n={0,1,…,n−1}).

[F2]

A bilinear form on V is a function V×V→R that is linear in each variable separately, and it is symmetric when B(u,v)=B(v,u) for all u,v∈V (Bilinear forms, and symmetric, skew-symmetric, and alternating bilinear forms, The real Coxeter form, its radical, reflections, and form-preserving maps).

[F3]

For a linear map T of a finite-dimensional vector space over R one has dim⁡V=dim⁡(ker⁡T)+dim⁡(im⁡T), and dim⁡RR=1; if a linear map V→R has a nonzero value then its image is all of R and its rank is 1 (Rank-nullity: dim⁡FV=nullity⁡T+rank⁡T, Rank and nullity of a linear map with finite-dimensional domain, The standard list e:n→Fn with ei(i)=1F and ei(j)=0F for j≠i is an ordered basis of Fn; hence dim⁡FFn=n, and F0 is the zero space with basis ∅ and dimension 0).

[F4]

In ordered bases the matrix of a composite is the product of the matrices of the factors, matrix powers are iterated products, and I2 denotes the identity matrix (Coordinate columns [v]B and matrices [T]BC of linear maps relative to ordered bases, [S∘T]BD=[S]CD[T]BC, Rectangular matrix multiplication and the identity matrix In, including zero-sized shapes).

[F5]

Trigonometric values and identities: the addition formulas sin⁡(x+y)=sin⁡xcos⁡y+cos⁡xsin⁡y and cos⁡(x+y)=cos⁡xcos⁡y−sin⁡xsin⁡y; sin⁡2x+cos⁡2x=1; sin⁡x=0 if and only if x∈πZ, and cos⁡x=0 if and only if x=(k+12)π for some k∈Z; cos⁡(π/2)=0, cos⁡π=−1, cos⁡(x+π)=−cos⁡x, and cos⁡0=1 by the defining series evaluated at 0 (The addition formulas for sine and cosine, Parity and the Pythagorean identity for sine and cosine, The zero sets of sine and cosine and the least positive common period 2 pi, Quarter-turn values and shifts by pi/2 and pi, Sine and cosine defined by their real power series).

[F7]

In the ordered field R one has 2≠0, so 2a=0V implies a=0V (The reals form a totally ordered field).

Proof

technique · direct finite-dimensional computation, in layers: first the basis and reflection algebra, then the rank-two plane with its trigonometry, and finally the order statements on the whole space
1.1givenF1F2

The functions es are linearly independent: if ∑s∈Sλses=0V then evaluating at s gives λs=0. They span V: every u∈V satisfies u=∑s∈Su(s)es, since the right side is a finite sum (S is finite) whose value at any t∈S is u(t). So (es)s∈S is a basis of V. Consequently, for all u,w∈V one has B(u,w)=∑s,t∈Su(s)w(t)B(es,et): expanding u and w in the basis and distributing with bilinearity in each variable gives that finite sum. In particular a bilinear form on V is determined by the numbers B(es,et).

1.2givenF1F2algebra

The displayed ra for B(a,a)≠0 is linear in v, because v↦B(v,a) is linear and ra(v)=v−2B(v,a)B(a,a)a is a sum of the identity and the composite of that functional with scalar multiplication by a; also ra(a)=a−2B(a,a)B(a,a)a=a−2a=−a, and ra(v)=v for every v∈ker⁡B(−,a). Moreover B(rav,a)=B(v,a)−2B(v,a)B(a,a)B(a,a)=−B(v,a), so ra(ra(v))=ra(v)−2B(rav,a)B(a,a)a=ra(v)+2B(v,a)B(a,a)a=v; hence ra2=idV. Finally, expanding with bilinearity and cancelling the equal cross terms via symmetry B(u,a)=B(a,u) and B(w,a)=B(a,w), B(rau,raw)=B(u,w)−2B(u,a)B(a,w)B(a,a)−2B(w,a)B(a,u)B(a,a)+4B(u,a)B(w,a)B(a,a)=B(u,w), so ra is B-preserving.

1.3givenF1F2F3

Put φ(v):=B(v,a). By B(a,a)≠0 the value φ(a) is nonzero, so the image of φ is all of R and its rank is 1; the kernel ker⁡B(−,a)=ker⁡φ is a linear subspace and rank-nullity gives dim⁡ker⁡B(−,a)=dim⁡V−1.

1.4givenF1F2F4algebra

For distinct s,t∈S, evaluating the definition of r at es and et with B(es,es)=B(et,et)=1 and B(es,et)=−c gives rs(es)=−es, rs(et)=et+2ces, rt(et)=−et and rt(es)=es+2cet. Hence in the ordered basis (es,et) the matrices are [rs]=(−12c01) and [rt]=(102c−1), and the composite A:=rsrt has matrix [A]=[rs][rt]=(4c2−1−2c2c−1),det⁡[A]=(4c2−1)(−1)−(2c)(−2c)=1.

1.5givenF1F2F5F6algebra

On P=Res+Ret write x=xses+xtet. Bilinearity and the values B(es,es)=B(et,et)=1, B(es,et)=−c give B(x,x)=xs2−2cxsxt+xt2=(xs−cxt)2+(1−c2)xt2. For finite m one has 1−c2=sin⁡2(π/m) and sin⁡(π/m)≠0 because 0<π/m≤π/2 and the sine zero set is πZ; hence B(x,x)>0 whenever x≠0, so B∣P is positive definite. For m=∞ one has c=1 and B(x,x)=(xs−xt)2≥0, which vanishes exactly when xs=xt, i.e. on R(es+et); and R(es+et) is precisely the radical of B∣P, since B(x,es)=xs−cxt and B(x,et)=xt−cxs vanish for all such x, while xs≠xt makes B(x,es)≠0.

1.6givenF1F4F5algebra

Assume m<∞ and put θ:=π/m, so c=cos⁡θ. The trace of the matrix in 1.4 is tr⁡[A]=4c2−2=2(2c2−1)=2cos⁡2θ by the double-angle instance of the addition formulas, and the 2×2 Cayley-Hamilton identity, verified directly from the displayed entries, reads A2=2cos⁡2θ A−I2. For m≥3 one has 2θ∈(0,π) and sin⁡2θ≠0, and for m=2 one has c=cos⁡(π/2)=0, so [A]=−I2.

2.1givenF5step 1.6algebra

Assume m≥3; then sin⁡2θ≠0 and induction on k≥1 using A2=2cos⁡2θ A−I2 and the product-to-sum identity 2sin⁡xcos⁡y=sin⁡(x+y)+sin⁡(x−y) gives Ak=sin⁡(2kθ)A−sin⁡(2(k−1)θ)I2sin⁡2θ for every k≥1: the case k=1 is sin⁡0=0, and the induction step replaces Ak+1=A⋅Ak using the displayed identity. Hence Am=I2 because sin⁡(2mθ)=sin⁡(2π)=0 and sin⁡(2(m−1)θ)=−sin⁡2θ. If 1≤k<m and Ak=I2, then sin⁡(2kθ)A=(sin⁡2θ+sin⁡(2(k−1)θ))I2; were sin⁡(2kθ)≠0, the matrix A would be scalar, contradicting its nonzero off-diagonal entry −2c (for m≥3 the value c is nonzero, since c=0 would force π/m=(j+12)π, that is 2/m=2j+1>0 for an integer j, so j≥0 and 2/m≥1, impossible because m≥3). So sin⁡(2kθ)=0, and then sin⁡(2(k−1)θ)=sin⁡(2kθ−2θ)=−cos⁡(2kθ)sin⁡2θ forces cos⁡(2kθ)=1; with sin⁡(2kθ)=0 it gives 2kθ∈2πZ (indeed sin⁡x=0 writes x=ℓπ, and cos⁡(ℓπ)=(−1)ℓ follows from cos⁡0=1 and cos⁡(x+π)=−cos⁡x, so cos⁡(2kθ)=1 forces ℓ even), hence m∣k, contradicting 1≤k<m. Hence Ak≠I2 for 0<k<m.

2.2givenF4F7step 1.4algebra

Assume m=∞, so c=1 and [A]=(3−22−1)=I2+N with N=(2−22−2). Then N≠0 and N2=0 by direct multiplication, so the binomial theorem gives Ak=I2+kN for every k≥0, while A−1=I2−N because (I2+N)(I2−N)=I2−N2=I2, so (I2−N)j=I2+(−j)N for j≥0 and Ak=I2+kN for every k∈Z. For k≠0 the matrix kN has entry 2k≠0 in its first column, so Ak≠I2; the product A=rsrt therefore has infinite order on P.

2.3givenF1F2F5step 1.1

The Coxeter form B of the Statement is well defined: the prescription B(u,w):=∑s,t∈Su(s)w(t)(−c(s,t)) is a finite sum of scalar multiples of products of coordinate values, hence a function V×V→R linear in each variable; it is symmetric because c(s,t)=c(t,s), which follows from m(s,t)=m(t,s) and the symmetry of cosine; and it has B(es,et)=−c(s,t) for all s,t. By 1.1 it is the unique symmetric bilinear form with these values, and c(s,s)=cos⁡(π/1)=cos⁡π=−1 gives B(es,es)=1.

2.4givenF1F2F6step 1.2step 1.4step 1.5

The maps rs and rt fix P⊥={v∈V:B(v,es)=B(v,et)=0} pointwise, since rs(v)=v−2B(v,es)B(es,es)es=v and likewise for t. If m<∞, then V=P⊕P⊥: the Gram matrix (1−c−c1) of B∣P has determinant 1−c2=sin⁡2(π/m)≠0, so for given v the 2×2 system B(p,es)=B(v,es), B(p,et)=B(v,et) has a unique solution p∈P; then z:=v−p satisfies B(z,es)=B(z,et)=0, hence z∈P⊥ and v=p+z, so P+P⊥=V. If p∈P∩P⊥ then B(p,p)=0 with p∈P, and positive definiteness of B∣P forces p=0; thus P∩P⊥={0} and V=P⊕P⊥.

3.1givenstep 1.6step 2.1step 2.2step 2.4∎

Let A=rsrt. If m<∞, then Am∣P=I2 and Ak∣P≠I2 for 0<k<m by steps 1.6 and 2.1 and the case m=2 of step 1.6, while A∣P has the matrix displayed in step 1.4; on P⊥ the map A fixes every vector by step 2.4, so Am=idV and Ak≠idV for 0<k<m because its restriction to the direct summand P differs from I2. If m=∞, then [A]=I2+N with N≠0, N2=0 and Ak∣P=I2+kN≠I2 for every k≠0 by step 2.2, so Ak≠idV for every k≠0 and rsrt has infinite order on V.

DefinitionDefinition: Literature-sourcedProof: Not applicablejudge pass (gpt-6.1-sol)audited 2026-10-08Open item page →

The canonical reflection homomorphism, roots, reflections, and the positive cone

Definition

Let S, m, V, B be as in The real Coxeter form, its radical, reflections, and form-preserving maps, let W be the presented Coxeter group of Coxeter matrices, the presented Coxeter group, reduced words, length, and standard parabolic subgroups with its universal property, and put rs:=res for s∈S (Reflections: involutivity, form invariance, fixed hyperplane, and exact rank-two order).

(1) Write GL(V) for the group of invertible linear maps V→V, the unit group of the monoid of linear endomorphisms under composition (Invertible linear maps, linear isomorphisms, and inverse linear maps, The space L(V,W) of linear maps with pointwise addition and scalar multiplication, Identity maps and composites of linear maps are linear, The invertible elements of a monoid form a group under the restricted operation). The canonical reflection homomorphism is the group homomorphism ρ:W→GL(V) (Monoid homomorphism and group homomorphism) that satisfies ρ(s)=rs for every s∈S; its existence and uniqueness are established by Descent of the reflection representation, unit root norms, and conjugation of reflections ↗, which is this definition's recorded justifier. For w∈W and v∈V write ρ(w)v for the image.

(2) The root system of the pair is Φ:={ρ(w)es:w∈W, s∈S}⊂V; its elements are the roots. The set of reflections of W is T:={wsw−1:w∈W, s∈S}⊂W; that ρ(wsw−1) is the reflection rρ(w)es and that every root is B-non-isotropic are proved in Descent of the reflection representation, unit root norms, and conjugation of reflections ↗.

(3) The positive cone is V+:={∑s∈Sλses:λs∈R, λs≥0} and the negative cone is −V+ (Linear combination of a finite list, and the span span⁡(S) as the smallest linear subspace containing S).

No positivity of ρ(w)es for fixed w, no faithfulness or injectivity of ρ, no discreteness and no nondegeneracy of B is asserted by this definition.

LemmaStatement: AI-adaptedProof: AI-adaptedprecheck passjudge pass (gpt-6.1-sol)audited 2026-10-08Open item page →

Descent of the reflection representation, unit root norms, and conjugation of reflections

Statement

Let S, m, V, B, W, rs, ρ, Φ, T be as in The canonical reflection homomorphism, roots, reflections, and the positive cone.

(1) Relators and descent. For every s∈S one has rs2=idV, and for all s≠t with m(s,t)<∞ one has (rsrt)m(s,t)=idV. Consequently the assignment s↦rs sends every relator of the presentation to the identity, and by the universal property of Coxeter matrices, the presented Coxeter group, reduced words, length, and standard parabolic subgroups there is a unique group homomorphism ρ:W→GL(V) with ρ(s)=rs for all s∈S.

(2) ρ preserves the form. For every w∈W and all u,w′∈V, B(ρ(w)u,ρ(w)w′)=B(u,w′).

(3) Roots have unit norm. For every w∈W and s∈S, B(ρ(w)es,ρ(w)es)=1; hence every root α∈Φ satisfies B(α,α)=1≠0 and rα is defined.

(4) Conjugation of reflections. Let g∈GL(V) be B-preserving and let a∈V with B(a,a)≠0. Then grag−1=rga. In particular, for every w∈W and s∈S, ρ(wsw−1)=ρ(w)rsρ(w)−1=rρ(w)es, so every t=wsw−1∈T acts on V as the reflection in the root ρ(w)es∈Φ.

Facts & Assumptions

Given: a finite set S, a Coxeter matrix m, the space V=RS, the Coxeter form B, the reflections ra and the presented Coxeter group W with its universal property, all as in the Statement of The canonical reflection homomorphism, roots, reflections, and the positive cone; here rs:=res for s∈S.

[F1]

For a∈V with B(a,a)≠0 the map ra is linear, satisfies ra2=idV and B(rau,raw)=B(u,w) for all u,w∈V; and for distinct s,t∈S with m(s,t)<∞ the product A=rsrt satisfies Am(s,t)=idV (Reflections: involutivity, form invariance, fixed hyperplane, and exact rank-two order, clauses (2) and (3)(iv)).

[F2]

The Coxeter form satisfies B(es,es)=1 for every s∈S, the symbol rs abbreviates res, and a linear map g is B-preserving when B(gu,gw)=B(u,w) for all u,w∈V (The real Coxeter form, its radical, reflections, and form-preserving maps).

[F3]

A subset H of a group W that is closed under the group operation and under inverses and contains a generating set S equals W, because W=⟨S⟩ is the smallest subgroup containing S; a group homomorphism satisfies φ(gh)=φ(g)φ(h) and φ(g−1)=φ(g)−1 (The subgroup ⟨S⟩ generated by a subset, the cyclic subgroup ⟨g⟩, and cyclic groups, Group and abelian group, Monoid homomorphism and group homomorphism).

Proof

technique · verify the relators, descend through the presentation's universal property, and propagate the form preservation along the subgroup generated by the images of the generators
1.1givenF1F2F4

For every s∈S the map rs=res is linear, B-preserving and satisfies rs2=idV: these are the identities of [F1] for a=es, whose hypothesis B(es,es)≠0 holds by [F2]. Since rs2=idV, the map rs is invertible with rs−1=rs, so rs∈GL(V).

1.2givenF1F2

For all distinct s,t∈S with m(s,t)<∞ one has (rsrt)m(s,t)=idV, directly from the exact order statement of [F1] applied to the plane spanned by es and et: the product rsrt acts there with exact order m(s,t), so its m(s,t)-th power is the identity on V.

1.3givenF1F2algebra

Conjugation formula. Let g∈GL(V) be B-preserving and let a∈V with B(a,a)≠0. Then B(ga,ga)=B(a,a)≠0, and for every v∈V the B-preservation of g gives B(g−1v,a)=B(g(g−1v),ga)=B(v,ga). Substituting into the definition of rga and writing v=g(g−1v), rga(v)=g(g−1v)−2B(g−1v,a)B(a,a)ga=g(g−1v−2B(g−1v,a)B(a,a)a)=grag−1(v), so grag−1=rga.

2.1givenF4step 1.1step 1.2

Descent. The assignment s↦rs sends the relator s2 to rs2=idV by 1.1 and the relator (st)m(s,t) to (rsrt)m(s,t)=idV by 1.2; these are exactly the relators of the presented Coxeter group W of Coxeter matrices, the presented Coxeter group, reduced words, length, and standard parabolic subgroups, and the images rs lie in the group GL(V). So the universal property of that presentation gives a unique group homomorphism ρ:W→GL(V) with ρ(s)=rs for every s∈S.

3.1givenF2F3step 1.1step 2.1

ρ preserves the form, and roots have unit norm. Let H:={w∈W:B(ρ(w)u,ρ(w)w′)=B(u,w′) for all u,w′∈V}. Every s∈S lies in H by 1.1, since ρ(s)=rs. If g,h∈H then B(ρ(gh)u,ρ(gh)w′)=B(ρ(g)ρ(h)u,ρ(g)ρ(h)w′)=B(ρ(h)u,ρ(h)w′)=B(u,w′), using the homomorphism property of 2.1 and the B-preservation of ρ(g) and then of ρ(h), so gh∈H; and if g∈H, then B(ρ(g−1)u,ρ(g−1)w′)=B(ρ(g)ρ(g−1)u,ρ(g)ρ(g−1)w′)=B(u,w′), so g−1∈H. Thus H is a subgroup containing S, and since every element of W is the value of a finite word in S (Coxeter matrices, the presented Coxeter group, reduced words, length, and standard parabolic subgroups), so that the images of the elements of S generate W, [F3] gives H=W. In particular B(ρ(w)es,ρ(w)es)=B(es,es)=1 for all w∈W and s∈S by [F2], so every root α∈Φ has B(α,α)=1≠0 and the reflection rα is defined.

4.1givenstep 1.3step 2.1step 3.1∎

Conjugation of reflections by ρ. Let w∈W and s∈S. By 3.1 the map ρ(w) is B-preserving, and rs=ρ(s) by 2.1; applying the conjugation formula 1.3 with g=ρ(w) and a=es therefore gives ρ(w) rs ρ(w)−1=rρ(w)es. Since ρ is a homomorphism, ρ(w)−1=ρ(w−1) and ρ(w)ρ(s)ρ(w)−1=ρ(wsw−1), so ρ(wsw−1)=rρ(w)es. Hence for every t=wsw−1∈T the element ρ(t) is the reflection in the root ρ(w)es∈Φ, as asserted.

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The dual action, chambers, faces, and root hyperplanes

Definition

Let S, m, V, B, W, ρ, Φ be as in The canonical reflection homomorphism, roots, reflections, and the positive cone, and let V∗ be the algebraic dual of V (Linear functionals and the algebraic dual V∗=L(V,F)).

(1) The dual action. For w∈W and f∈V∗ define w⋅f∈V∗ by (w⋅f)(v):=f(ρ(w)−1v). This is the dual (contragredient) action of ρ; that it really is a left action by linear maps is proved in The dual action, the faces, and the rank-two chamber tiling ↗. The dual action is used even when B is degenerate: no identification of V with V∗ through B is made or assumed.

(2) Chambers, faces, root hyperplanes. The closed chamber is C:={f∈V∗:f(es)≥0 for all s∈S}, its interior is C∘:={f∈V∗:f(es)>0 for all s∈S}, and for I⊆S the face CI is CI:={f∈V∗:f(es)=0 for s∈I and f(es)>0 for s∉I}, the set of functionals of C vanishing exactly on I. For a root α∈Φ the root hyperplane is Hα:={f∈V∗:f(α)=0}=ker⁡(evα), the kernel of the evaluation functional f↦f(α) (Kernel and image of a linear map).

Neither the nonemptiness of the CI nor any orbit or tiling property is asserted here; existence of the faces and the exact rank-two chamber structure are proved in The dual action, the faces, and the rank-two chamber tiling ↗.

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The dual action, the faces, and the rank-two chamber tiling

Statement

With the notation of The dual action, chambers, faces, and root hyperplanes:

(1) The dual action is an action by linear maps. For all w1,w2∈W and f∈V∗ one has id⋅f=f and w1⋅(w2⋅f)=(w1w2)⋅f, and for each w the map f↦w⋅f is linear.

(2) The faces are nonempty. Let fs∈V∗ be the dual basis functionals of the basis (es) of V, i.e. fs(et)=δst (The dual family (b∗)b∈B associated to a Hamel basis B, defined by b∗(c)=δbc, The dual family of a finite basis is a basis of the dual space, with the same dimension). For I⊆S the functional fI:=∑s∉Ifs satisfies fI(es)=1 for s∉I and fI(es)=0 for s∈I; hence fI∈CI and every face is nonempty. In particular C∘∋∑s∈Sfs is nonempty and CS={0}.

(3) Rank two. Let s≠t in S and put P:=Res+Ret. Let P∗:=Hom(P,R) be the algebraic dual space of the 2-dimensional space P (Linear functionals and the algebraic dual V∗=L(V,F)), with the dual basis fs,ft of the basis (es,et) of P; functionals on P are the restrictions of functionals on V. Let Ws,t:=⟨ρ(s),ρ(t)⟩⊆GL(V) be the matrix subgroup generated by the two reflections. It preserves P. For g∈Ws,t and φ∈P∗ define (g⋅φ)(v):=φ(g−1v) for v∈P; this is a left action of Ws,t on P∗ by linear maps, the contragredient of its restriction to P. The abstract subgroup ⟨s,t⟩≤W acts through its image Ws,t; no action of all of W on P∗ is asserted. Writing c:=c(s,t) (so c=1 for m(s,t)=∞) and coordinates (ys,yt) on P∗, so that φ=ysfs+ytft and φ(es)=ys, φ(et)=yt, the dual generators act by ρ(s)∗(ys,yt)=(−ys, 2cys+yt),ρ(t)∗(ys,yt)=(ys+2cyt, −yt); each is an involution fixing the line {φ:φ(es)=0}={ys=0} pointwise, respectively {φ:φ(et)=0}={yt=0}, and the functional δ(φ):=φ(es+et) is preserved by Ws,t when m(s,t)=∞. Put ΦP:=Ws,t{es,et}⊂P, the rank-two root system. For β∈ΦP the rank-two root hyperplane is Hβ∩P∗:={φ∈P∗:φ(β)=0}.

(i) If m:=m(s,t)<∞: Ws,t is a dihedral group of order 2m, and the 2m chambers wCP (w∈Ws,t), where CP:={f∈P∗:f(es)≥0, f(et)≥0}, are exactly the 2m closed sectors cut out in P∗ by the m root hyperplanes Hβ∩P∗ (β∈ΦP), ΦP:=Ws,t{es,et}. They have pairwise disjoint interiors, their union is all of P∗, Ws,t acts simply transitively on them, and any two distinct chambers are separated by at least one root hyperplane, i.e. there is β∈ΦP with the two interiors in opposite open half-planes of Hβ.

(ii) If m(s,t)=∞: the chambers wCP (w∈Ws,t) have pairwise disjoint interiors and their union is {φ∈P∗:φ(es+et)>0}∪{0}, that is, the closed half-plane {φ:φ(es+et)≥0} with the nonzero points of its boundary line removed; any two distinct chambers are separated by at least one root hyperplane Hβ∩P∗ (β∈ΦP), and the traces Hβ∩{φ:φ(es+et)=1} are exactly the integers in the coordinate ys on that affine line.

Facts & Assumptions

Given: a finite set S, a Coxeter matrix m, the space V=RS, the Coxeter form B, the reflections ra, the presented group W, the canonical homomorphism ρ:W→GL(V) with roots Φ, and the dual action, chambers, faces and root hyperplanes on V∗ of The dual action, chambers, faces, and root hyperplanes; for distinct s,t∈S the plane P=Res+Ret and the number c=c(s,t).

[F1]

B(es,es)=1 and B(es,et)=−c for all s,t; for B(a,a)≠0 the map ra is a linear involution preserving B with ra(a)=−a and ra the identity on ker⁡B(−,a); for a=es this gives rs(es)=−es and rs(et)=et+2ces, and symmetrically rt(et)=−et, rt(es)=es+2cet; and for finite m(s,t) the restriction B∣P is positive definite (The real Coxeter form, its radical, reflections, and form-preserving maps, Reflections: involutivity, form invariance, fixed hyperplane, and exact rank-two order, clauses (2) and (3)(i)–(iv), and Proof step 2.1). In particular, rsrt has exact order m on P for finite m, while for m=∞ its restriction is I2+N with N=(2−22−2) and (rsrt)k∣P=I2+kN.

[F2]

ρ:W→GL(V) is the unique homomorphism with ρ(s)=rs for s∈S, it satisfies ρ(gh)=ρ(g)ρ(h) and ρ(g−1)=ρ(g)−1, every ρ(w) preserves B, every root has B-norm 1, and ρ(wsw−1)=rρ(w)es for all w∈W, s∈S, so all reflections of W act as the reflections in the roots ρ(w)es∈Φ (The canonical reflection homomorphism, roots, reflections, and the positive cone, Descent of the reflection representation, unit root norms, and conjugation of reflections, clauses (1)–(4)).

[F3]

The dual action is (w⋅f)(v)=f(ρ(w)−1v); the closed chamber is C={f∈V∗:f(es)≥0 for all s∈S}, its interior is C∘={f:f(es)>0 for all s}, the face of type I is CI={f:f(es)=0 for s∈I, f(es)>0 for s∉I}, and Hα={f∈V∗:f(α)=0} for α∈Φ (The dual action, chambers, faces, and root hyperplanes).

[F4]

For a finite-dimensional space the dual space, the dual family of a basis and its basis property are as recorded in the algebraic-dual and dual-basis items; in particular fs(et)=δst defines unique elements fs of the dual of P (Linear functionals and the algebraic dual V∗=L(V,F), The dual family (b∗)b∈B associated to a Hamel basis B, defined by b∗(c)=δbc, The dual family of a finite basis is a basis of the dual space, with the same dimension).

[F5]

V=RS consists of the functions S→R with pointwise operations, the functions es form a basis of V, and u=∑s∈Su(s)es for u∈V (The vector space FX of all functions X→F with pointwise operations, and Fn as the case X=n={0,1,…,n−1}, Reflections: involutivity, form invariance, fixed hyperplane, and exact rank-two order, clause (1)).

[F6]

Trigonometric facts: the addition formulas; sin⁡2x+cos⁡2x=1; sin⁡x=0 if and only if x∈πZ, and cos⁡x=0 if and only if x=(k+12)π for some k∈Z; cos⁡(x+π)=−cos⁡x, cos⁡π=−1; cos⁡2x=cos⁡2x−sin⁡2x and sin⁡2x=2sin⁡xcos⁡x follow from the addition formulas (The addition formulas for sine and cosine, Parity and the Pythagorean identity for sine and cosine, The zero sets of sine and cosine and the least positive common period 2 pi, Quarter-turn values and shifts by pi/2 and pi).

[F7]

π>0 and R is a totally ordered field, so 0<π/m≤π/2 for m≥2 and the order arithmetic below is the order of R (Pi as twice the smallest positive zero of cosine, The reals form a totally ordered field).

[F8]

Every real τ has an integer j with j≤τ<j+1 (Integer part: for every real x there is exactly one integer m with m≤x<m+1).

[F9]

A nonzero linear map from a finite-dimensional real vector space to R is onto, because any nonzero value can be scaled to any prescribed real value. Its kernel therefore has codimension one by Rank-nullity: dim⁡FV=nullity⁡T+rank⁡T.

Proof

technique · first the action and face identities, then the explicit two-dimensional model, then the finite and infinite chamber computations
1.1givenF2F3F4

The dual action is an action by linear maps. For w∈W and f∈V∗ the formula (w⋅f)(v)=f(ρ(w)−1v) defines an element of V∗ because a composite of linear maps is linear, and f↦w⋅f is linear because evaluation at v is linear in f. Moreover id⋅f=f, since ρ(id)=id, and w1⋅(w2⋅f)=f∘ρ(w2)−1∘ρ(w1)−1=f∘ρ(w1w2)−1=(w1w2)⋅f, using ρ(w1w2)=ρ(w1)ρ(w2) and hence ρ(w1w2)−1=ρ(w2)−1ρ(w1)−1.

1.2givenF1F2F3F4algebra

Generators on the dual plane. The formulas in [F1] show rs(P)=P=rt(P), since each map preserves P and is its own inverse. Hence every g∈Ws,t=⟨rs,rt⟩ and its inverse preserve P. The restriction g↦g∣P is a homomorphism into GL(P), so (g⋅φ)(v)=φ(g−1v) is well-defined on P∗ and is a left action: (gh)⋅φ=φ∘h−1∘g−1=g⋅(h⋅φ), and the identity acts trivially. Here s⋅φ and t⋅φ denote the actions of rs and rt respectively. The dual basis vectors satisfy (s⋅fs)(es)=fs(ρ(s)−1es)=fs(−es)=−1 and (s⋅fs)(et)=fs(ρ(s)et)=fs(et+2ces)=2c, while (s⋅ft)(es)=ft(−es)=0 and (s⋅ft)(et)=ft(et+2ces)=1; hence in coordinates s⋅(ysfs+ytft)=(−ys)fs+(2cys+yt)ft, that is ρ(s)∗(ys,yt)=(−ys, 2cys+yt). The same computation with s replaced by t gives ρ(t)∗(ys,yt)=(ys+2cyt, −yt). Both displayed maps are involutions: applying the first twice returns (ys,yt), and applying the second twice returns (ys,yt). The first fixes the line {φ:φ(es)=0}={ys=0} pointwise and the second fixes {φ:φ(et)=0}={yt=0} pointwise, since these are exactly the vectors whose coordinate in question vanishes. For the functional δ(φ)=φ(es+et)=ys+yt one has δ(s⋅φ)=(2c−1)ys+yt and δ(t⋅φ)=ys+(2c−1)yt, so each generator preserves δ exactly when c=1, i.e. when m(s,t)=∞; in that case Ws,t preserves δ because it is generated by rs and rt.

1.3givenF2F4F5F9

Faces. Let I⊆S and put fI:=∑s∉Ifs∈V∗. By the dual-basis property fI(es)=1 for s∉I and fI(es)=0 for s∈I; hence fI∈CI and every face is nonempty. In particular I=∅ gives ∑s∈Sfs∈C∘, so the interior is nonempty, and I=S gives CS={f:f(es)=0 for all s∈S}={0}, since a functional vanishing on the basis (es) of V is zero. For a root α, B(α,α)=1 makes α≠0, so some coordinate α(s)≠0 and fs(α)=α(s)≠0. Thus evα:V∗→R is a nonzero linear map and Hα is a hyperplane by [F9].

1.4givenF1F2F5F6F7algebra

The finite rank-two model. Assume m<∞ and put θ:=π/m and c=cos⁡θ. Then 0<θ≤π/2, sin⁡θ≠0 and 1−c2=sin⁡2θ. On P put u:=es and v:=(et+ces)/sin⁡θ. Then B(u,u)=B(es,es)=1, B(u,v)=(B(es,et)+cB(es,es))/sin⁡θ=(−c+c)/sin⁡θ=0 and B(v,v)=(B(et,et)+2cB(es,et)+c2B(es,es))/sin⁡2θ=(1−2c2+c2)/sin⁡2θ=(1−c2)/sin⁡2θ=1: thus (u,v) is a B∣P-orthonormal basis of P and es=u, et=−cu+sin⁡θ v. Since rs fixes ker⁡B(−,es)∩P=Rv pointwise and sends u=es to −u, in the coordinates (xu,xv) of the basis (u,v) it is rs(xu,xv)=(−xu,xv); since ker⁡B(−,et)∩P is spanned by (sin⁡θ,c) and rt(et)=−et, the map rt is the reflection in the line R(sin⁡θ,c). Consequently the composite A:=rsrt satisfies A(u)=rs(es+2cet)=rs((1−2c2)u+2csin⁡θ v)=(2c2−1)u+2csin⁡θ v=(cos⁡2θ)u+(sin⁡2θ)v and A(v)=−sin⁡2θ u+cos⁡2θ v, so in the orthonormal coordinates A(xu,xv)=(xucos⁡2θ−xvsin⁡2θ, xusin⁡2θ+xvcos⁡2θ), the rotation through 2θ, whose order is exactly m.

2.1givenF1F2F6step 1.4

The rank-two roots. Assume m<∞ and keep the orthonormal coordinates (u,v) of 1.4, in which A is the rotation through 2θ. Then Akes=(cos⁡2kθ)u+(sin⁡2kθ)v for every k∈Z, and rsAkes=(−cos⁡2kθ)u+(sin⁡2kθ)v=(cos⁡(m−2k)θ)u+(sin⁡(m−2k)θ)v because π=mθ and cos⁡(π−α)=−cos⁡α, sin⁡(π−α)=sin⁡α. Moreover et=−cos⁡θ u+sin⁡θ v=(cos⁡(m−1)θ)u+(sin⁡(m−1)θ)v, and the same two formulas applied to et give Aket and rsAket at angles (m−1+2k)θ and (1−2k)θ. As k varies over Z the angles 2kθ are exactly the even multiples of θ and the angles (1−2k)θ are exactly the odd multiples, so every element of S:={(cos⁡jθ)u+(sin⁡jθ)v:j=0,1,…,2m−1} is one of the four displayed families and S⊆ΦP; conversely S contains es and et and is stable under A (which adds 2θ to an angle) and under rs (which sends an angle φ to π−φ=(mθ−φ)), hence stable under Ws,t=⟨ρ(s),ρ(t)⟩=⟨ρ(s),A⟩, so ΦP⊆S. Therefore ΦP=Ws,t{es,et}={(cos⁡jθ)u+(sin⁡jθ)v: j=0,1,…,2m−1}, a set of exactly 2m unit vectors, and ΦP is stable under β↦−β.

2.2givenF1F2F8step 1.2algebra

The infinite case. Assume m=∞, so c=1 and by 1.2 the generators act by s⋅(ys,yt)=(−ys,2ys+yt) and t⋅(ys,yt)=(ys+2yt,−yt) and preserve δ=ys+yt. On the affine line {δ=1} parametrized by τ=ys these maps read τ↦−τ and τ↦2−τ, the two reflections of the line about 0 and 1. Every word in the two involutions rewrites to Ak or Akrs with k∈Z, where A=rsrt; their actions on this affine line are respectively τ↦τ−2k and τ↦−τ−2k. These are pairwise distinct, so restriction to P is faithful on Ws,t. The interval images are Ak[0,1]=[−2k,1−2k] and Akrs[0,1]=[−1−2k,−2k], so they are exactly [j,j+1] for j∈Z, with distinct elements giving distinct intervals. These cover the affine line by [F8] and have pairwise disjoint interiors. Since CP is the cone on [0,1] in the half-plane {δ≥0} and the action is linear, the chamber wCP is the cone on the interval corresponding to w; these cones have pairwise disjoint interiors and their union is {φ:δ(φ)>0}∪{0}, because every point with δ>0 is a positive multiple of a unique point of {δ=1} lying in a unit interval, while every point of a cone on a unit interval has δ≥0 and only 0 has δ=0. By [F1] and the normal forms above, the roots are precisely the four families Akes=(1+2k,2k), Aket=(−2k,1−2k), Akrses=(−1−2k,−2k) and Akrset=(2+2k,1+2k) for k∈Z. Equivalently ΦP={(j+1,j),(j,j+1):j∈Z}, since the first and fourth families cover the even and odd values of j in the first pair, and the second and third do so in the second pair. On {δ=1} the equation φ(aes+bet)=0 is (a−b)ys+b=0, so the two root families give wall traces −j and j+1, exactly the integers. If two chamber intervals are [j,j+1] and [l,l+1] with j<l, the wall whose trace is j+1 places their interiors in opposite open half-planes, because its defining linear form on {δ>0} has the sign of ys/δ−(j+1) up to a fixed nonzero factor.

3.1givenF1F2F3F6step 1.4step 2.1

The rank-two walls. Assume m<∞. The map ♭:P→P∗, x↦B(x,⋅), is an isomorphism: in the orthonormal basis (u,v) of 1.4 its inverse sends φ to φ(u)u+φ(v)v. Moreover it intertwines the two actions, since (g⋅♭(x))(z)=B(x,g−1z)=B(gx,z)=♭(gx)(z) for g∈Ws,t. For β∈P one has ♭(β⊥)=Hβ∩P∗, where β⊥={x∈P:B(x,β)=0}: indeed ♭(x)(β)=B(x,β) vanishes exactly when x∈β⊥. By 2.1 each β∈ΦP is a unit vector at an angle jθ, so β⊥ is the line at angle jθ+π/2, and the lines Hβ∩P∗ depend only on the pair {β,−β}: there are exactly m of them, at angles π/2+jθ, j=0,…,m−1, equally spaced by θ. The chamber CP={φ∈P∗:φ(es)≥0, φ(et)≥0} corresponds under ♭ to {x∈P:B(x,es)≥0, B(x,et)≥0}, whose boundary lines are es⊥ (the line at angle π/2) and et⊥ (the line at angle (m−1)θ+π/2, i.e. π/2−θ): so CP=♭ of the closed sector between these two consecutive walls, of angle θ, and no root hyperplane line meets CP∘ because the m walls are equally spaced by θ and contain both boundary lines.

4.1givenF1F2F3step 1.2step 1.4step 2.1step 3.1∎

The finite chamber tiling. Assume m<∞. Put a:=rs, b:=rt, and A:=ab. Since a2=b2=1 and aAa=A−1, every word in a,b rewrites to Ak or Aka. The finite relation Am=1 therefore gives at most 2m elements, represented by 0≤k<m. Their restrictions to P are all distinct: the rotations Ak∣P are distinct by their exact order m, the maps Aka∣P are distinct after cancellation of a∣P, and a rotation cannot equal a reflection because their determinants on P are 1 and −1. Thus restriction to P is faithful on this matrix subgroup, ∣Ws,t∣=2m, and it is the dihedral group of order 2m. Its contragredient action on P∗ has the same distinct elements. The action maps the set of m walls to itself, because g⋅(Hβ∩P∗)=Hgβ∩P∗ for g∈Ws,t and ΦP is Ws,t-stable, so it permutes the 2m closed sectors; it maps the sector CP to the sectors obtained by successive rotations through 2θ and by the reflection ρ(s), which realizes all 2m of them: under ♭−1, CP has angular interval [π/2−θ,π/2] and rsCP has interval [π/2,π/2+θ]; their Ak images add 2kθ, giving all consecutive sectors modulo 2π. Thus the orbit of CP is exactly the set of closed sectors cut out by the m root hyperplanes. Since ∣Ws,t∣=2m equals the number of sectors, the action on the orbit is simply transitive, and the sectors have pairwise disjoint interiors and union P∗ as the 2m sectors of m distinct lines through the origin. Finally, a sign choice for each of the m wall forms defines an intersection of open half-planes. If nonempty it is convex, by linearity of those forms, and so lies in a single sector: the segment joining any two of its points meets no wall. Thus distinct sector interiors have different signs for some wall form, which supplies a root hyperplane separating their entire interiors.

Remarks

Davis, Example D.2.1(i), printed p. 442, describes the infinite-dihedral Tits cone as the closed half-plane. For the literal union of the chamber images, step 2.2 shows that every nonzero point of its boundary is absent; the closed half-plane is the closure of that union.

5 · Examples, counterexamples and false statements

None yet.

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