Alphabeta Math
AlgorithmAlgorithm: Literature-sourcedProof: Not applicablePipeline-generated
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Finite higher-order Suzuki product formula

Definition

Input: Integers k,r≥1, a finite time code t in the expression language of Term-list Hamiltonian access, and a finite term-list access input.

Admissible conditions: If t≠0, for every term occurrence e−icνtHjν/r in the fully expanded segment, the access input supports that exact signed time code for term Hjν and declares its implementation, per-call costs, and any approximation-error record. The call may be supplied directly at the signed code or through separately declared inverse or time-reversed access with its own cost and error record. This condition includes the half-time calls in the base formula and every signed central call in the recursion.

Output: The finite product circuit and its declared query, gate, ancilla, coefficient-bit, description-bit, and classical-generation costs.

Instructions:

  1. Compare the exact value of the supplied time code with 0. If it is 0, return the identity. Otherwise begin with S2(h) from Symmetric second-order product formula, where h=t/r.
  2. For each j=2,…,k, let ρ2j−1 be the unique nonnegative root of x2j−1=4 from Existence and uniqueness of n-th roots: a unique a1/n≥0 with (a1/n)n=a; it is positive since 02j−1≠4. Put pj=(4−ρ2j−1)−1, and recursively replace the current even-order formula S2j−2(h) by S2j(h):=S2j−2(pjh)2S2j−2((1−4pj)h)S2j−2(pjh)2.
  3. Recursively expand one segment until only the term exponentials remain, retaining their displayed operator order. For exactly r repetitions, execute the factors of each expanded segment chronologically in the reverse of their displayed operator order. Since later executed gates multiply on the left by Denotational semantics of a finite layered circuit, the exact-call operator is S2k(t/r)r. If calls are approximate, execute their supplied unitary implementations in that same chronological order and retain the per-call error records; the displayed S2k remains the ideal exact-call word.
  4. For each central coefficient 1−4pj, use the implementation declared for that actual signed call time. For q=2j−1≥3, let ρq be the positive root of ρqq=4. It is positive, and ρq<4: otherwise monotonicity of positive integer powers (Monotonicity of x↦xn and of n↦an) would give ρqq≥4q>4, a contradiction. Hence 4−ρq>0, pj=(4−ρq)−1>1/4, and 1−4pj<0. Thus the central coefficient is negative; the actual call time is this coefficient times the current recursive time argument. Use the resulting signed code, which may be positive or negative, with its directly supported implementation or separately declared inverse or time-reversed access. Charge exact coefficient descriptions and classical generation separately.

The recursion is finite because j increases only from 2 through k, and each expansion makes five calls to the preceding formula. No asymptotic error or cost guarantee is part of this procedure definition.

Depends on

Used by

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Sources