Alphabeta Math
Pipeline-generated
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Hamiltonian Simulation and Product Formulas

1 · Prerequisites

2 · Summary

This page treats time-independent Hamiltonians as finite-dimensional self-adjoint matrices and defines simulation error in operator norm. It distinguishes a term-list access contract from sparse row and value oracles, fixes product order and signed-time conventions, proves first- and second-order error bounds, and accounts for explicit term calls and their costs. The finite Suzuki recursion, its order cancellation and a conservative error bound are proved locally. No efficient circuit or free term evolution follows from a matrix description alone.

3 · Logical flowchart

4 · Definitions, theorems and proofs

DefinitionDefinition: Literature-sourcedProof: Not applicableOpen item page →

Hamiltonian simulation error and resources

Definition

Let V be a finite-dimensional complex inner-product space and let H=H∗ be a specified endomorphism. Its exact time-t evolution is UH(t)=e−itH as defined by Finite Hermitian matrix dynamics. The notation ∥T∥ denotes the operator norm of The operator norm is zero on the zero domain and otherwise is max_{||v||=1} ||Tv||. The target register's Hilbert space is identified with V as part of the input. A Hamiltonian simulator at encoded time t and tolerance 0<ϵ<1 is a declared procedure whose output is a unitary W on the stated target register satisfying ∥W−UH(t)∥≤ϵ. If its circuit uses auxiliary registers, the exact clean or dirty contract of Clean and dirty ancillas must make the induced target unitary W well-defined; the error is measured on that target unitary. The scalar time and tolerance have exact finite descriptions under the declared input convention; their description lengths are recorded.

The resource record lists, separately, the number of calls to each named oracle, controlled calls, inverse calls, elementary gate occurrences, clean and dirty ancillary wires, coefficient bits, full circuit-description bits, and classical generation time. A coordinate not supplied by the access contract is unavailable, not zero. No matrix description supplies a circuit, oracle, controlled call, inverse call, or term exponential for free; uniform-family and cost conventions are those of Full-list uniform quantum circuit family, Circuit-family and computation cost model, Controlled Unitary Access, and Inverse Unitary Access. No polynomial resource bound is asserted by this definition.

DefinitionDefinition: Literature-sourcedProof: Not applicableOpen item page →

Term-list Hamiltonian access

Definition

A term-list access input consists of an integer m≥1, finite-dimensional self-adjoint endomorphisms H1,…,Hm on one stated register, and the exact target H=∑j=1mHj. A supported time code is a finite expression whose leaves are rational numbers or symbols ρq denoting the unique positive real root of xq=4 for an odd integer q≥1; Existence and uniqueness of n-th roots: a unique a1/n≥0 with (a1/n)n=a gives a unique nonnegative root; it is positive because 0q=0≠4. Internal operations are addition, subtraction, multiplication, or division by a nonzero expression. Its exact real value and bit length are recorded. These codes include rational times and every coefficient-scaled rational time in the finite Suzuki recursion.

For each j, the input declares which time codes are supported and supplies either the exact operation e−isHj or a full-list uniform circuit generator, in the sense of Full-list uniform quantum circuit family, that returns a unitary Vj(s) together with a certified error ηj(s)≥0 satisfying ∥Vj(s)−e−isHj∥≤ηj(s). If a circuit uses auxiliary registers, it supplies the exact clean or dirty contract of Clean and dirty ancillas so that its induced operation Vj(s) on the target is well-defined: clean registers start and return to zero for every target input, and dirty registers are acted on by the identity. The operator-norm error is measured on the induced target operation. The provider specifies how each supported code is passed to the generator and records its actual description length and generation time; no polynomial bound is inferred. This is an explicit access promise, not a claim that every matrix has such a family.

For each supported call the input records its named-oracle query counts, gate count, ancillary wires, description bits, coefficient bits, and classical generation cost. Costs of composing the calls into a full product and generating that product are separately recorded as Qwrap and Gwrap. A controlled form is available only when separately declared as the block operation of Controlled Unitary Access. Inverse access to a call is available only when separately declared under Inverse Unitary Access, with its own cost and error record. Forward access implies neither capability. The term list supplies no promise that any operation or coefficient computation is free.

DefinitionDefinition: Literature-sourcedProof: Not applicableOpen item page →

Sparse Hamiltonian row and value oracles

Definition

Fix N≥1, a sparsity bound d≥1, an integer b≥1, and an injective code enc:C→{0,1}b for a finite set C⊂C containing 0 and closed under conjugation. Put w=⌈log⁡2N⌉ and v=⌈log⁡2d⌉, identify [N] with the first N strings in {0,1}w, and regard any remaining strings as invalid labels. A valid w-bit index is zero-extended to w+1 bits. Let H=(Hxy)x,y∈[N] be Hermitian, have entries in C, and have at most d nonzero entries in every row. For each valid row x, list its nonzero column indices in increasing order. Define the total location function fH(x,ℓ) to be the ℓ-th listed index for a valid slot 0≤ℓ<d when that slot exists, and a distinguished sentinel otherwise. Invalid row labels and invalid slot labels also return the sentinel. Encode the sentinel by a fixed (w+1)-bit word outside the valid index codes. Define the total value function gH(x,y) to return enc(Hxy) on valid labels and enc(0) on invalid labels. All label widths and codes are part of the finite input description.

The row-location oracle and entry-value oracle are the coherent XOR maps OfH∣x,ℓ,z⟩=∣x,ℓ,z⊕fH(x,ℓ)⟩ and OgH∣x,y,z⟩=∣x,y,z⊕gH(x,y)⟩, where the output target has respectively w+1 and b bits. The slot register has v bits; all unused slot strings are invalid and use the sentinel. These are total Boolean-function oracles on every bitstring basis input. They are instances of Coherent XOR function oracle, whose justified-by supplier proves unitarity and involutivity for arbitrary total functions. Each named call and any separately granted controlled or inverse call is charged under Circuit-family and computation cost model. This exact-code model describes the decoded matrix H; approximating a different target matrix requires a separate bound on the matrix difference. Row and value access alone does not supply a term list or term-evolution circuits.

DefinitionDefinition: Literature-sourcedProof: Not applicablejudge pass (gpt-6-luna)Open item page →

First-order Lie product formula

Definition

For a term-list input H=∑j=1mHj, a real time h, and the announced order 1,…,m, define S1(h):=e−ihH1e−ihH2⋯e−ihHm. Operator products are written in their ordinary left-to-right algebraic order, so the rightmost factor acts first on a vector. For an integer r≥1, the r-step first-order approximation at time t is S1(t/r)r. Each exponential is the finite-matrix evolution of Finite Hermitian matrix dynamics; this definition does not identify the product with e−itH when terms fail to commute.

DefinitionDefinition: Literature-sourcedProof: Not applicablejudge pass (gpt-6-luna)Open item page →

Symmetric second-order product formula

Definition

For the announced term order 1,…,m and real h, define the palindromic product S2(h):=e−ihH1/2e−ihH2/2⋯e−ihHm−1/2e−ihHme−ihHm−1/2⋯e−ihH2/2e−ihH1/2. For m=1 this is just e−ihH1. The r-step approximation is S2(t/r)r, with r≥1. A written product acts right-to-left, as in First-order Lie product formula. Every term call and any signed-time implementation cost must be declared by Term-list Hamiltonian access.

RemarkRemark: Literature-sourcedProof: Not applicableOpen item page →

Scope of higher-order Suzuki claims

Remarks

The finite Suzuki recursion, finite-order cancellation, and the explicit conservative norm bound proved on this page are the higher-order claims supplied here. They use signed term times and charge every expanded term call. No asymptotic complexity claim with hidden commutator constants, no generic nested-commutator estimate, and no free negative-time access is part of this remark; any stronger resource assertion needs its own complete proof and access-cost accounting.

TheoremStatement: Literature-sourcedProof: AI-generatedjudge pass (gpt-6-luna)Open item page →

First-order commutator error

Statement

Let V be a finite-dimensional complex inner-product space, let H1,…,Hm be self-adjoint endomorphisms of V with m≥1, and set H=∑j=1mHj. For every real t and integer r≥1, ∥S1(t/r)r−UH(t)∥≤t22r∑1≤j<k≤m∥[Hj,Hk]∥, where S1 has the fixed order of First-order Lie product formula and UH(t)=e−itH is the finite-matrix evolution of Finite Hermitian matrix dynamics.

Facts & Assumptions

Given: The finite-dimensional space V, self-adjoint terms H1,…,Hm, m≥1, t∈R, and r≥1.

[F1]

First-order Lie product formula defines S1(h)=e−ihH1⋯e−ihHm in the announced order.

[F2]

Unitary and differential identities for finite matrix dynamics states that UK(s) is unitary, UK′(s)=−iKUK(s), and UK(s+u)=UK(s)UK(u) for every finite-dimensional self-adjoint K and real s,u.

[F3]

The operator norm is submultiplicative and satisfies ||T^*T|| = ||T||^2 gives submultiplicativity of the operator norm.

[F4]

The operator norm is zero on the zero domain and otherwise is max_{||v||=1} ||Tv|| defines the operator norm by the maximum over unit vectors.

Proof

1.1givenF2construct

If V={0}, every endomorphism is the unique zero map and both sides of the theorem are zero. Otherwise, for self-adjoint H1,H2, put A=−iH1 and B=−iH2. For h≥0 define F(s)=e(h−s)(A+B)esAesB for 0≤s≤h. Its endpoints are F(0)=eh(A+B) and F(h)=ehAehB. Differentiating the three finite-matrix evolutions using [F2] and the entrywise product rule gives F′(s)=e(h−s)(A+B)(esAB−BesA)esB.

2.1step 1.1F2F3F4algebra

For fixed s≥0, differentiating euABe(s−u)A for 0≤u≤s and integrating yields esAB−BesA=∫0seuA[A,B]e(s−u)A du. For unitaries R,S, [F2] and [F4] give ∥R∥=∥S∥=∥R−1∥=∥S−1∥=1; [F3] applied to RXS and then to R−1(RXS)S−1 gives ∥RXS∥=∥X∥. Thus the unitary factors in the integrands and in [step 1.1] give ∥F′(s)∥≤s∥[A,B]∥. Integrating from 0 to h gives ∥eh(A+B)−ehAehB∥≤h2∥[A,B]∥/2. For h<0 apply the same result to −A,−B and ∣h∣; since [A,B]=−[H1,H2], the bound is h2∥[H1,H2]∥/2 for all real h.

3.1step 2.1F1F2F3F4algebra

Put Aj=−iHj. For k=1,…,m, let Pk=ehA1⋯ehAk and Tk=eh∑j=1kAj. Adding and subtracting eh∑j<kAjehAk and applying the two-term estimate in [step 2.1] gives ∥Tk−Pk∥≤∥Tk−1−Pk−1∥+h22∥[∑j<kAj,Ak]∥. Linearity gives [∑j<kAj,Ak]=∑j<k[Aj,Ak], and [Aj,Ak]=−[Hj,Hk]; the triangle inequality from [F4] bounds this norm by ∑j<k∥[Hj,Hk]∥. Right multiplication by ehAk preserves the norm by the unitary norm argument in [step 2.1]. Starting with T1=P1 and iterating proves the local m-term bound ∥e−ihH−S1(h)∥≤h22∑j<k∥[Hj,Hk]∥.

4.1step 2.1step 3.1F1F2F3F4algebra∎

Set h=t/r. The identity Sr−Ur=∑ℓ=0r−1Sr−1−ℓ(S−U)Uℓ writes the difference as r terms. The unitary norm argument in [step 2.1] bounds each term by ∥S1(h)−UH(h)∥, so [step 3.1] gives ∥S1(h)r−UH(h)r∥≤t22r∑j<k∥[Hj,Hk]∥. By [F2], UH(h)r=UH(t).

AlgorithmAlgorithm: Literature-sourcedProof: Not applicablejudge pass (gpt-6-luna)Open item page →

First-order term-list simulator

Definition

Input: A finite term-list access input with H=∑j=1mHj, a finite time code t in the expression language of Term-list Hamiltonian access, a rational tolerance 0<ϵ<1, a certified rational C2≥0 satisfying C2≥∑1≤j<ℓ≤m∥[Hj,Hℓ]∥, and a supplied certified rational upper bound R≥0 satisfying R≥t2C2/ϵ. For t≠0, put r=max⁡{1,⌈R⌉} and h=t/r; the access declarations must supply each term call at this exact signed code h, with its implementation and costs. A call may be directly supported at h or supplied by separately declared inverse or time-reversed access, with that route's own costs. When t≠0, every approximate call must have a certified error, and the sum of those errors over all rm calls must be at most ϵ/2. The time-code and call conventions are those of Term-list Hamiltonian access.

Output: The composed unitary circuit for the declared product order, together with its query, gate, ancilla, coefficient-bit, description-bit, and classical-generation cost record.

Instructions:

  1. Compare the exact value of the supplied time code with 0. If it is 0, return the identity circuit.
  2. Otherwise set r=max⁡{1,⌈R⌉} using rational arithmetic and set h=t/r as a supported finite expression code.
  3. For each of exactly r repetitions, execute the declared term calls chronologically in order m,m−1,…,1. By Denotational semantics of a finite layered circuit, later executed gates multiply on the left. The ideal exact-call operator for one repetition is therefore e−ihH1⋯e−ihHm of First-order Lie product formula; with supplied implementations the actual operator is V1(h)⋯Vm(h), with the declared call errors accumulated separately. If the call at h is supplied through inverse or time-reversed access, use that separately declared route and its cost and error record; do not infer it from forward access alone.
  4. Keep circuit-generation, coefficient, and all oracle costs in their separate declared coordinates. When t≠0 and calls are approximate, retain their per-call error records; admissibility requires their sum over all rm calls to be at most ϵ/2.

The procedure makes no claim that the required term calls or their uniform generator exist for an arbitrary matrix.

TheoremStatement: Literature-sourcedProof: AI-generatedjudge pass (gpt-6-luna)Open item page →

Conservative second-order error

Statement

Let V be finite-dimensional, let H1,…,Hm be self-adjoint with m≥1, put H=∑jHj and M=∑j∥Hj∥. For every real t and integer r≥1, ∥S2(t/r)r−UH(t)∥≤∣t∣3M33r2, where S2 is the palindromic product of Symmetric second-order product formula and UH is the finite-matrix evolution of Finite Hermitian matrix dynamics.

Facts & Assumptions

Given: The finite-dimensional space V, self-adjoint terms H1,…,Hm, m≥1, t∈R, and r≥1.

[F1]

Unitary and differential identities for finite matrix dynamics states that each term evolution is unitary, differentiable with derivative −iHjUHj(s), and satisfies the time-composition law.

[F2]

Symmetric second-order product formula defines the palindromic product with two half-time factors for every term except the middle term.

[F4]

The operator norm is zero on the zero domain and otherwise is max_{||v||=1} ||Tv|| defines the operator norm by the maximum over unit vectors.

[L1]

In this proof, R(h)=O(ha) means there are constants C,δ>0 with ∥R(h)∥≤C∣h∣a whenever ∣h∣<δ.

Proof

1.1givenF1F2algebra

The claim is immediate on the zero-dimensional space, so assume V≠{0}. Write Aj=−iHj, A=∑jAj, P(h)=S2(h), and Q(h)=UH(h). Every factor is unitary by [F1], and the palindromic word gives P(−h)=P(h)−1; also Q(−h)=Q(h)−1. Differentiating the factors at zero, the two occurrences with coefficient 1/2 contribute a total coefficient 1 for each Aj, so P(0)=Q(0)=I and P′(0)=Q′(0)=A.

2.1step 1.1F1L1algebra

Let E(h)=P(h)−Q(h). Smoothness follows by repeatedly differentiating the constant-generator identity in [F1]. Thus E(h)=Ch2+O(h3) for some endomorphism C by [L1]. The inverse identities in step 1.1 give E(−h)=P(h)−1−Q(h)−1=−P(h)−1E(h)Q(h)−1. Since both inverse factors equal I+O(h), comparing degree-two coefficients yields C=−C, hence C=0. Therefore P and Q have matching Taylor coefficients through degree two.

3.1step 2.1F1F2F3F4algebra

Write P(h)=F1(h)⋯F2m−1(h) in its displayed order, with Fℓ(h)=ecℓhAjℓ and the coefficients cℓ equal to the half-step palindrome in [F2]. Repeated product differentiation and [F1] give ∥P′′′(h)∥≤(∑ℓ∣cℓ∣∥Hjℓ∥)3=M3: each j<m occurs twice with coefficient 1/2, and j=m occurs once with coefficient 1. Also Q′′′(h)=A3Q(h). For a unit vector v, the vector triangle inequality gives ∥Av∥≤∑j∥Hjv∥≤∑j∥Hj∥=M, so [F4] yields ∥A∥≤M. Then [F3], [F4], and unitarity give ∥Q′′′(h)∥≤M3. The integral Taylor remainder after degree two therefore gives ∥P(h)−Q(h)∥≤(2M3)∣h∣3/3!=M3∣h∣3/3.

4.1step 3.1F1F3F4algebra∎

Expand P(h)r−Q(h)r by telescoping. The definition [F4] and submultiplicativity [F3] show that unitary factors preserve the norm, so its norm is at most rM3∣h∣3/3 by [step 3.1]. With h=t/r, this is ∣t∣3M3/(3r2); [F1] gives Q(h)r=UH(t).

AlgorithmAlgorithm: Literature-sourcedProof: Not applicableOpen item page →

Finite higher-order Suzuki product formula

Definition

Input: Integers k,r≥1, a finite time code t in the expression language of Term-list Hamiltonian access, and a finite term-list access input.

Admissible conditions: If t≠0, for every term occurrence e−icνtHjν/r in the fully expanded segment, the access input supports that exact signed time code for term Hjν and declares its implementation, per-call costs, and any approximation-error record. The call may be supplied directly at the signed code or through separately declared inverse or time-reversed access with its own cost and error record. This condition includes the half-time calls in the base formula and every signed central call in the recursion.

Output: The finite product circuit and its declared query, gate, ancilla, coefficient-bit, description-bit, and classical-generation costs.

Instructions:

  1. Compare the exact value of the supplied time code with 0. If it is 0, return the identity. Otherwise begin with S2(h) from Symmetric second-order product formula, where h=t/r.
  2. For each j=2,…,k, let ρ2j−1 be the unique nonnegative root of x2j−1=4 from Existence and uniqueness of n-th roots: a unique a1/n≥0 with (a1/n)n=a; it is positive since 02j−1≠4. Put pj=(4−ρ2j−1)−1, and recursively replace the current even-order formula S2j−2(h) by S2j(h):=S2j−2(pjh)2S2j−2((1−4pj)h)S2j−2(pjh)2.
  3. Recursively expand one segment until only the term exponentials remain, retaining their displayed operator order. For exactly r repetitions, execute the factors of each expanded segment chronologically in the reverse of their displayed operator order. Since later executed gates multiply on the left by Denotational semantics of a finite layered circuit, the exact-call operator is S2k(t/r)r. If calls are approximate, execute their supplied unitary implementations in that same chronological order and retain the per-call error records; the displayed S2k remains the ideal exact-call word.
  4. For each central coefficient 1−4pj, use the implementation declared for that actual signed call time. For q=2j−1≥3, let ρq be the positive root of ρqq=4. It is positive, and ρq<4: otherwise monotonicity of positive integer powers (Monotonicity of x↦xn and of n↦an) would give ρqq≥4q>4, a contradiction. Hence 4−ρq>0, pj=(4−ρq)−1>1/4, and 1−4pj<0. Thus the central coefficient is negative; the actual call time is this coefficient times the current recursive time argument. Use the resulting signed code, which may be positive or negative, with its directly supported implementation or separately declared inverse or time-reversed access. Charge exact coefficient descriptions and classical generation separately.

The recursion is finite because j increases only from 2 through k, and each expansion makes five calls to the preceding formula. No asymptotic error or cost guarantee is part of this procedure definition.

TheoremStatement: Literature-sourcedProof: AI-generatedjudge pass (gpt-6-luna)Open item page →

First-order query and gate cost

Statement

For the term-list input H=∑j=1mHj in Term-list Hamiltonian access, let t be a finite time code in its expression language, let 0<ϵ<1 be rational, and let C2≥0 be a certified rational satisfying C2≥∑1≤j<ℓ≤m∥[Hj,Hℓ]∥. Supply a certified rational upper bound R≥t2C2/ϵ and put r=max⁡{1,⌈R⌉} and h=t/r. When t≠0, suppose each term call at the exact signed code h is supported and declared, directly or through separately declared inverse or time-reversed access, with at most qj named queries and gj gate occurrences. Let Qwrap and Gwrap be the separately declared query and gate costs of uniform circuit composition and generation. For t≠0, the algorithm First-order term-list simulator uses at most r∑jqj+Qwrap queries and r∑jgj+Gwrap gates. Its exact term product has error at most ϵ/2. If, when t≠0, implemented calls are unitary and their total operator-norm error over all rm calls is at most ϵ/2, the returned unitary is within ϵ of UH(t). When t=0, the algorithm returns the identity with no term calls. Coefficient, description-bit, ancilla, and classical-generation resources remain separate coordinates.

Facts & Assumptions

Given: A finite term-list input, finite time code t in its expression language, rational 0<ϵ<1, certified rational C2, certified rational upper bound R≥t2C2/ϵ, the resulting integer r=max⁡{1,⌈R⌉}, and the declared costs for calls at h=t/r when t≠0.

[F1]

First-order term-list simulator returns the identity with no term calls when t=0; otherwise it makes exactly r repetitions of m term calls, where r=max⁡{1,⌈R⌉} and R≥t2C2/ϵ.

[F2]

First-order commutator error bounds the exact product-formula error by t22r∑1≤j<ℓ≤m∥[Hj,Hℓ]∥.

[F3]

Term-list Hamiltonian access records per-call query and gate costs, implementation errors, and composition/generation overhead as separate charges.

[F5]

The operator norm is zero on the zero domain and otherwise is max_{||v||=1} ||Tv|| defines the operator norm as the maximum over unit vectors.

Proof

1.1givenF1F2algebra

If t=0, the algorithm returns the identity and the exact evolution is also the identity. Otherwise r=max⁡{1,⌈R⌉}≥R≥t2C2/ϵ. Since C2 bounds the commutator sum, [F2] gives exact product error at most t2C2/(2r)≤ϵ/2.

2.1F1step 1.1F3F4F5algebra

Replace the exact term calls one at a time by their supplied unitary implementations. For unitaries, the definition [F5] and submultiplicativity [F4] show that left and right multiplication preserve operator norm. Thus a telescoping expansion of the two products bounds the operator-norm change by the sum of the individual call errors. The input certificate in [F1] makes this total at most ϵ/2. The triangle inequality with step 1.1 gives total error at most ϵ.

3.1F1F3algebra∎

For t≠0, each of the m term circuits occurs once in each of r repetitions, so their query and gate totals are r∑jqj and r∑jgj. For t=0 there are no term calls, and hence zero term-call query and gate costs. Adding the separately declared composition/generation overhead gives the stated bounds in either branch; the other resource coordinates are charged separately by [F3].

LemmaStatement: Literature-sourcedProof: AI-generatedjudge pass (gpt-6-luna)Open item page →

Suzuki recursive cancellation of error terms

Statement

Let H1,…,Hm be fixed finite-dimensional self-adjoint matrices, m≥1, and let U(h)=e−ih∑jHj. The recursive formulas S2k of Finite higher-order Suzuki product formula have the same Taylor coefficients as U(h) through degree 2k at h=0. They are symmetric: S2k(−h)=S2k(h)−1 for all real h.

Facts & Assumptions

Given: Finite-dimensional self-adjoint terms H1,…,Hm, m≥1, and the recursive formulas S2k.

[L1]

In this proof, R(h)=O(ha) means there are constants C,δ>0 with ∥R(h)∥≤C∣h∣a whenever ∣h∣<δ.

[L2]

Repeatedly differentiating UK′(h)=−iKUK(h) from [F3] gives UK(n)(h)=(−iK)nUK(h) for every n≥0. The product rule gives continuous derivatives of every order for each finite formula word, so Taylor expansions below hold with operator-norm remainders to every stated finite order.

[F1]

Symmetric second-order product formula gives the palindromic base product S2(h).

[F2]

Finite higher-order Suzuki product formula defines pj=(4−41/(2j−1))−1 and the five-copy recursion with coefficients pj,pj,1−4pj,pj,pj.

[F3]

Unitary and differential identities for finite matrix dynamics gives the unitary, differentiability, and time-composition identities for each finite self-adjoint term.

[F4]

Finite Hermitian matrix dynamics defines UK(h) by the finite spectral functional calculus.

[F5]

Term-list Hamiltonian access permits signed exact time codes built from rational numbers and the positive roots used in the Suzuki coefficients.

[F6]

Existence and uniqueness of n-th roots: a unique a1/n≥0 with (a1/n)n=a gives the unique nonnegative real q-th root of 4 for every integer q≥1.

[F7]

Monotonicity of x↦xn and of n↦an states that x↦xq is increasing on the nonnegative reals and that 4q>4 for q>1.

Proof

1.1givenF1F3F4L1L2algebrabase

Put Aj=−iHj and A=∑jAj. The base word S2(h) is palindromic by [F1], so [F3] gives S2(−h)=S2(h)−1; the same identity holds for U(h) by [F3] and [F4]. Its derivative at zero is A, because the two half-time occurrences of every outer Aj sum to one full occurrence, while the middle term occurs once. Also U(0)=S2(0)=I. By [L2], E(h)=S2(h)−U(h)=Ch2+O(h3) for some matrix C. The inverse identities imply E(−h)=−S2(h)−1E(h)U(h)−1; comparing degree-two terms gives C=−C, hence C=0. Thus E(h)=O(h3), proving the base order-two claim as well as the symmetry base case.

1.2ihF2F3F5F6F7L1L2algebra

Fix j≥2 and assume as the induction hypothesis [ih] that S2j−2(−h)=S2j−2(h)−1 and that S2j−2 agrees with U through degree 2j−2. Put q=2j−1, p=pj, and c=1−4p. By [L2] and Taylor's theorem, S2j−2(h)−U(h)=Ehq+O(hq+1). By [F6], the unique nonnegative root ρq with ρqq=4 exists; it is positive because zero has zero q-th power. Since q≥3, [F7] gives ρq<4: otherwise ρqq≥4q>4, contradicting ρqq=4. Thus p=(4−ρq)−1>1/4 and c=1−4p=−ρqp<0. The five scaled copies in [F2] have leading error coefficients pqE,pqE,cqE,pqE,pqE. Their other factors equal I+O(h), so multiplying an error term by those factors changes it only by O(hq+1). The ideal factors U(ph)2U(ch)U(ph)2 equal U((4p+c)h)=U(h) by [F3]. The coefficient c is an expression in the rational and positive-root tokens of [F5], so the signed call has a finite exact code. Hence the coefficient of hq in S2j(h)−U(h) is (4pq+cq)E. Since c=−ρqp and ρqq=4, cq=−4pq, so this coefficient vanishes and the difference is O(hq+1)=O(h2j).

2.1step 1.1step 1.2F2F3L1L2algebradischarge-induction∎

Let A(h)=S2j−2(ph) and B(h)=S2j−2(ch). The recursive word is A(h)A(h)B(h)A(h)A(h). The induction hypothesis in step 1.2 gives inverse symmetry for A and B; reversing the five factors shows S2j(−h)=S2j(h)−1. Also U(−h)=U(h)−1. By step 1.2 and [L2], write S2j(h)−U(h)=Dh2j+O(h2j+1). The inverse identity gives Dh2j=−Dh2j+O(h2j+1), hence D=0 and the difference is O(h2j+1). Therefore S2j agrees with U through degree 2j and has inverse symmetry. Together with the base case in step 1.1, induction proves both claims for every finite k.

TheoremStatement: Literature-sourcedProof: AI-generatedjudge pass (gpt-6-luna)Open item page →

Higher-order product-formula error with explicit term counts

Statement

Let k,m,r≥1, let H1,…,Hm be self-adjoint endomorphisms of a finite-dimensional complex inner-product space, and put H=∑jHj, M=∑j∥Hj∥, and q=2k+1. Expand one recursive segment as S2k(h)=∏ν=1Le−ihcνHjν in its declared order and set Bk=∑ν=1L∣cν∣∥Hjν∥. For every real t, ∥S2k(t/r)r−UH(t)∥≤(Bkq+Mq)∣t∣qq! rq−1. The expanded term count is L=(2m−1)5k−1 per segment. If t is rational with an exact finite code, a rational tolerance ϵ>0 and rational upper bounds B‾≥Bk, M‾≥M are supplied, a finite integer search for the least r≥1 satisfying rq−1q!ϵ≥(B‾q+M‾q)∣t∣q makes the displayed exact-call error at most ϵ. For the resource claims when t≠0, require the term-list input to support every actual signed call code cνt/r for its term Hjν in the fully expanded segment, including half-time base calls and negative central calls, and to declare an implementation and per-call cost at each such code. An inverse or time-reversed implementation must be separately declared with its own cost and error record; forward access alone does not supply it. When t≠0 and term circuits are approximate, add the sum of all per-call operator-norm errors separately; to keep total error at most ϵ, use ϵ/2 in the integer search and require the sum of call errors over all rL calls to be at most ϵ/2. When t≠0, the term-call contributions to query and gate costs are the sums of the declared costs at the actual signed times in one expanded word, multiplied by r; when t=0, the recursive algorithm returns the identity with no term calls. The separately declared product-composition overheads Qwrap and Gwrap are added to those totals; coefficient, description-bit, ancilla, and classical-generation resources remain separate coordinates.

Facts & Assumptions

Given: The finite term list H1,…,Hm, integer k,r≥1, and real time t.

[F1]

Suzuki recursive cancellation of error terms proves that S2k and UH have matching Taylor coefficients through degree 2k.

[F2]

Finite higher-order Suzuki product formula expands each segment into five copies per recursion level, starting from the 2m−1 factors of S2.

[F3]

Unitary and differential identities for finite matrix dynamics gives unitarity and UH′(h)=−iHUH(h).

[F4]

The operator norm is zero on the zero domain and otherwise is max_{||v||=1} ||Tv|| defines the operator norm by the maximum over unit vectors (and as zero on the zero domain).

[F5]

The operator norm is submultiplicative and satisfies ||T^*T|| = ||T||^2 gives submultiplicativity of the operator norm.

[F6]

Term-list Hamiltonian access charges each supported signed term call and separately records query, gate, coefficient, and generation costs.

[A1]

For the resource claims when t≠0, each actual call in the expanded word is supported at its signed time code and has a declared implementation and per-call cost; any inverse or time-reversed route is separately declared.

Proof

1.1givenF3F4F5algebra

The claim is immediate on the zero-dimensional space, so assume V≠{0}. Write the expanded segment as P(h)=F1(h)⋯FL(h), where Fν(h)=e−ihcνHjν. Repeated differentiation gives Fν(a)(h)=(−icνHjν)aFν(h), so [F3]–[F5] imply ∥Fν(a)(h)∥≤∣cν∣a∥Hjν∥a. The full multinomial sum is ∑a1+⋯+aL=qq!a1!⋯aL!∏ν(∣cν∣∥Hjν∥)aν=(∑ν∣cν∣∥Hjν∥)q=Bkq, proving ∥P(q)(h)∥≤Bkq. Repeatedly differentiating [F3] gives UH(q)(h)=(−iH)qUH(h). The triangle inequality from [F4] gives ∥H∥≤∑j∥Hj∥=M, hence ∥UH(q)(h)∥≤Mq.

2.1step 1.1F1algebra

By [F1], P−UH has zero Taylor coefficients through degree q−1. The integral Taylor remainder of order q gives ∥P(h)−UH(h)∥≤∫0∣h∣(∣h∣−s)q−1(q−1)!(Bkq+Mq) ds=(Bkq+Mq)∣h∣qq!, using a change of variable when h<0.

3.1step 2.1F3F4F5algebra

Both P(h) and UH(h) are unitary. Their operator norms and those of their inverses are one by the unit-vector definition [F4]; submultiplicativity [F5] then shows that each unitary factor preserves the norm in a telescoping expansion. Thus their rth-power difference is at most r times the local bound in step 2.1. Substituting h=t/r yields the displayed global error.

4.1step 3.1F2F3F5F6algebra∎

The base segment has 2m−1 term calls by [F2]; every recursive level replaces one formula by five copies, so induction gives L=(2m−1)5k−1. When t≠0, [A1] supplies each call at signed time cνt/r with its query and gate costs, so r identical segments multiply their term-call contributions by r; when t=0, the procedure returns the identity and makes no term calls. Add the separately declared product-composition charges Qwrap and Gwrap to obtain total query and gate costs; coefficient, description-bit, ancilla, and classical-generation costs stay separate as required by [F6]. If the νth exact call is replaced by a unitary call with error ην, expanding the difference of the two products one factor at a time and applying the norm invariance in step 3.1 bounds the total change by ∑νην over all rL calls. Finally, the integer search terminates because its left side grows without bound; its inequality and the certified upper bounds make the exact-call error at most ϵ.

5 · Examples, counterexamples and false statements

None yet.

Sources