Alphabeta Math
DefinitionDefinition: Literature-sourcedProof: Not applicablePipeline-generatedaudited 2026-10-02
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Rational maps of integral finite-type schemes

Definition

Let k be a field and let X be an integral k-scheme of finite type and Y a k-scheme of finite type (Integral schemes, Locally finite type and finite type morphisms) with Y separated over k (Separated morphism of schemes).

A rational map φ:X⇢Y is an equivalence class of pairs (U,φU), where U⊆X is a nonempty open subscheme (Open immersions of schemes) and φU:U→Y is a k-morphism (Morphisms of schemes). Two pairs (U,φU) and (V,ψV) are equivalent when the two morphisms agree on a nonempty open subscheme of U∩V, that is, when there is a nonempty open W⊆U∩V with φU∣W=ψV∣W.

The relation is an equivalence relation. Reflexivity and symmetry are immediate. For transitivity let (U,φU)∼(V,ψV) through W⊆U∩V and (V,ψV)∼(T,χT) through Z⊆V∩T. Since X is integral, hence irreducible, any two nonempty open subschemes meet, so W∩Z is a nonempty open subscheme of U∩T, and on W∩Z the morphisms φU and χT agree with ψV, hence with one another. Thus (U,φU)∼(T,χT). No integrality or reducedness of the target is needed.

A rational map is dominant when some representative φU has dense image. This is independent of the representative: if (U,φU) and (V,ψV) are equivalent through a nonempty open W⊆U∩V, then W is dense in the irreducible scheme U, so continuity gives φU(U)⊆φU(W)‾=ψV(W)‾⊆ψV(V)‾; hence φU dominant implies ψV dominant, and the converse is symmetric. A point of X at which no representative of φ is defined is a point of indeterminacy of φ.

When X is integral and of finite type over k, its function field k(X)=OX,ηX is the stalk at the generic point, and the function field of every nonempty affine open is the fraction field of its coordinate ring (Function field of an integral finite-type scheme); this is the description used whenever a rational map of curves is converted into a map of function fields below.

Depends on

Used by

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Sources