Alphabeta Math
ExampleConstruction: AI-adaptedVerification: AI-generatedSession-authored (Fable 5 assisted)precheck passaudited 2026-08-01
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

A graph is P3P_3-free if and only if every connected component is complete

Statement

A finite graph is P3P_3-free if and only if each of its connected components is complete. Such graphs are called cluster graphs.

Facts & Assumptions

Given: A finite graph GG.

[L1]

Connected components partition the vertices and contain every path between their vertices (The connected components of a graph partition its vertex set and are its maximal connected subgraphs).

Verification

technique · direct
1.1

If every component is complete, three vertices in one component induce all three edges, while vertices meeting more than one component induce edges only within their component parts and therefore at most one edge. Neither pattern is P3P_3, so GG is P3P_3-free.

L1F1F2
1.2

Conversely, suppose a component contains nonadjacent vertices x,yx,y. Choose a shortest xx-yy path x=v0,v1,,vk=yx=v_0,v_1,\ldots,v_k=y, where k2k\ge2.

chooseL1
2.1

Minimality of the path gives v0v2E(G)v_0v_2\notin E(G), so G[{v0,v1,v2}]P3G[\{v_0,v_1,v_2\}]\cong P_3.

step 1.2F2
3.1

Therefore a P3P_3-free graph cannot have a noncomplete component. Combining both directions proves the equivalence.

step 1.1step 2.1F1

Remarks

completecomponentK3completecomponentK2K3_[K2isaclustergraphandisP3-free

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · next 3 levels

Direct dependencies and their dependencies through the next three levels: 22 results over 10 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.

Sources