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A coercive non-symmetric form can have non-real Galerkin eigenvalues
Example
On let , and . Then is bounded and coercive with constant , since ; but the eigenvalues of are , which are non-real. Consequently for every real the equation for all has no nonzero solution: this non-symmetric coercive form has no weak eigenpair with a real eigenvalue, and its Galerkin matrix has a conjugate pair of non-real eigenvalues. This shows that the reality of the eigenvalues in the discrete spectral theorem is a consequence of symmetry and not of coercivity.
Facts & Assumptions
Given: a real , the matrix , and the sesquilinear form on .
Boundedness and coercivity of a sesquilinear form on a Hilbert space are defined by and , with the form linear in the first argument and conjugate-linear in the second (Bounded, coercive and symmetric sesquilinear forms).
is a complex Hilbert space with the standard inner product, and is computed by matrix multiplication and conjugation accordingly (Real and complex inner-product spaces and their induced length, Hilbert space, Rectangular matrix multiplication and the identity matrix , including zero-sized shapes, Real and imaginary parts, complex conjugation, and modulus).
For an endomorphism of a finite-dimensional complex vector space the spectrum is the root set of its characteristic polynomial, the characteristic polynomial of a matrix is , and a weak eigenpair identity for all is equivalent to when (Eigenvalues, eigenvectors, eigenspaces , and the spectrum of an endomorphism, For , the characteristic polynomial is when , with for the unique matrix, For every finite-dimensional space, is exactly the set of roots in of ).
Cauchy--Schwarz: (Cauchy–Schwarz: , with equality exactly for dependent pairs).
Verification
Coercivity. For one computes and because is purely imaginary and is real. Hence and is coercive with constant .
Boundedness. Applying Cauchy--Schwarz in the index, and , so Thus , and [F4] gives , so is bounded.
Spectrum. The characteristic polynomial is , and because its two roots are , which are not real. By [F3] the spectrum of the endomorphism is exactly , a conjugate pair of non-real eigenvalues of the Galerkin matrix .
No real-eigenvalue weak eigenpair. Let be real and suppose a nonzero satisfies for every . Subtracting, for every , and testing with gives , so ; by [F3], would be a real eigenvalue of , contradicting step 1.3. Hence there is no real with a nonzero weak eigenpair. Since is nevertheless bounded and coercive by steps 1.1 and 1.2, this two-dimensional model shows that coercivity alone does not force real eigenvalues. Its complex eigenpairs at do exist; the exclusion just proved concerns real eigenvalues.
Depends on
- Bounded, coercive and symmetric sesquilinear forms
- For $A\in M_n(F)$, the characteristic polynomial is $\chi_A(x)=\det(xI_n-A)$ when $n\geq1$, with $\chi_A(x)=1$ for the unique $0\times0$ matrix
- Real and imaginary parts, complex conjugation, and modulus
- The Axiom of Countable Choice ($\mathrm{AC}_\omega$)
- Eigenvalues, eigenvectors, eigenspaces $E_\lambda(T)=\ker(T-\lambda I)$, and the spectrum $\sigma_F(T)$ of an endomorphism
- Hilbert space
- Rectangular matrix multiplication and the identity matrix $I_n$, including zero-sized shapes
- Real and complex inner-product spaces and their induced length
- Cauchy–Schwarz: $|\langle x,y\rangle|\le\|x\|\,\|y\|$, with equality exactly for dependent pairs
- For every finite-dimensional space, $\sigma_F(T)$ is exactly the set of roots in $F$ of $\chi_T$
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Sources
- Richard S. Laugesen, Linear Analysis and Partial Differential Equations (University of Illinois, 2020, complete 158-page graduate notes) (standard reference, not scraped)
- Richard S. Laugesen, Spectral Theory of Partial Differential Equations (University of Illinois lecture notes, arXiv:1203.2344, complete 120 pages) (standard reference, not scraped)