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The intersection form of the blown-up projective plane

Example

Assume the Axiom of Choice, inherited through the Euler-characteristic and blowup suppliers (The Axiom of Choice). Let k be a field, X=Pk2, let p∈X(k) be a k-rational point, let π:X′=Bl⁡pX→X be the blowup (Blowup of a scheme along an ideal sheaf), let E=π−1(p) be the exceptional curve (Exceptional subscheme of a blowup) and let l:=π∗OX(1) in Pic⁡(X′) (the pullback of the hyperplane class; it is also the strict transform of any line not passing through p). Then l⋅l=1,l⋅E=0,E⋅E=−1, so the intersection form on the sublattice Zl+ZE of Pic⁡(X′) has matrix (100−1). Moreover the strict transform m:=π∗O(1)−E of a line through p (Strict transform of a closed subscheme) satisfies m=l−E, m⋅E=1 and m⋅m=0.

Facts & Assumptions

Given: a field k, the plane X=Pk2, a k-rational point p∈X(k), the blowup π:X′=Bl⁡pX→X with exceptional curve E=π−1(p), the class l=π∗OX(1), and the Axiom of Choice (The Axiom of Choice).

[F1]

The plane X is an integral regular projective surface over k; the intersection product C⋅D of Cartier divisors is defined, symmetric and bilinear, and O(d)⋅O(e)=de on X, in particular O(1)⋅O(1)=1 (Intersection numbers of Cartier divisors on a smooth projective surface, The surface intersection product is symmetric and bilinear, The intersection pairing on the projective plane, Integral schemes).

[F2]

Blowup calculus at a k-rational point: since p is k-rational its residue field is κ(p)=k and r=[κ(p):k]=1; the blowup X′ is an integral regular projective surface over k, E is an effective Cartier divisor with E≅Pk1 and OE(E)≅OPk1(−1); for all Cartier divisors D,D′ on X one has E⋅π∗D=0 and π∗D⋅π∗D′=D⋅D′; and for a reduced effective Cartier divisor C through p with multiplicity m≥1 and strict transform C′ one has π∗C=C′+mE, C′⋅E=m and C′⋅C′=C⋅C−m2 (The intersection matrix of a point blowup of a regular surface, r=1; The normal bundle of the exceptional curve is O(-1), Pullback of a Cartier divisor).

[F3]

Pullback of divisor classes: for a Cartier divisor D the total transform π∗D is the pullback Cartier divisor with OX′(π∗D)≅π∗OX(D) (Total transform of a Cartier divisor, Pullback of a Cartier divisor computes the pullback of its line bundle); hence l=[OX′(π∗L)] for any line L on X, and the total transform of a line L not through p is its strict transform because π is an isomorphism away from p. For a line L through p the multiplicity of a local equation at p is 1, so π∗L=m+E with m the strict transform (Total transform equals strict transform plus multiplicity times the exceptional divisor, Effective cartier divisor).

[F4]

The Axiom of Choice enters through the blowup, Euler-characteristic and bilinearity suppliers of [F1]–[F3]; the point, the lines and the blowup are given data and no selection is made below.

Verification

Given: a field k, the plane X=Pk2, a k-rational point p, the blowup π:X′=Bl⁡pX→X, its exceptional curve E, the class l=π∗OX(1), and a line L through p.

1.1F2

The blowup data. Since p is k-rational, r=1; the surface X′ is integral regular projective and E is an effective Cartier divisor isomorphic to Pk1 with OE(E)≅O(−1), so the intersection product is defined on X′ and E2=−r=−1; moreover E⋅π∗D=0 and π∗D⋅π∗D′=D⋅D′ for all Cartier divisors D,D′ on X.

1.2F1F2F3

l⋅l=1. Choose a line L′ on X; its class satisfies [OX(L′)]=[OX(1)], so l⋅l=π∗OX(L′)⋅π∗OX(L′)=OX(L′)⋅OX(L′)=1 by the pullback identity and the plane computation.

1.3F2F3

l⋅E=0. With D the Cartier divisor of any line on X, so that π∗D has class l, the orthogonality clause gives E⋅π∗D=0, that is, l⋅E=E⋅l=0 by symmetry.

2.1F2step 1.1

E⋅E=−1. This is the self-intersection formula of step 1.1 with r=1.

3.1F1step 1.2step 1.3step 2.1

The matrix. Steps 1.2, 1.3 and 2.1 give l⋅l=1, l⋅E=0=E⋅l and E⋅E=−1; if al+bE=0 in Pic⁡(X′), pairing with l gives a=0 and pairing with E gives −b=0. Thus these classes freely generate the stated sublattice; by bilinearity its Gram matrix of the sublattice Zl+ZE in the basis (l,E) is (100−1).

3.2F1F2F3step 1.2step 1.3step 2.1

The strict transform of a line through p. Let L be a line through p with strict transform m. The line is reduced and its multiplicity at p is 1, so π∗L=m+E and m⋅E=1 and m⋅m=L⋅L−1=0; equivalently, taking classes and using OX′(π∗L)≅π∗OX(1), the class of m is l−E, and bilinearity and steps 1.2–2.1 give m⋅E=l⋅E−E⋅E=0+1=1 and m⋅m=l⋅l−2l⋅E+E⋅E=1−0−1=0, in agreement.

4.1F4step 3.1step 3.2∎

Conclusion and choice accounting. Steps 1.2, 1.3 and 2.1 give the matrix of the intersection form on Zl+ZE, and step 3.2 gives m=l−E, m⋅E=1, m⋅m=0 for the strict transform of a line through p. The Axiom of Choice enters through the suppliers recorded in [F4]; the point, the lines and the blowup are given data and no selection is made in the computations.

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