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The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

An irreducible curve can have arbitrarily large tangent dimension

Example

Let k be a field, let n≥1, and assume the Axiom of Choice. Put R:=k[tn,tn+1,…,t2n−1]⊆k[t],C:=Spec⁡R, the monomial curve spanned by the n consecutive monomials of degrees n,n+1,…,2n−1. Then:

  • C is irreducible and dim⁡R=1, so C is a curve;
  • the ideal m=(tn,tn+1,…,t2n−1)R=R∩(t) is maximal, the residue field at it is R/m≅k, so 0:=m is a k-rational point of C, and the classes of tn,tn+1,…,t2n−1 form a k-basis of m/m2;
  • consequently dim⁡kT0C=n: for every n≥1 there is an irreducible curve whose tangent space at a point has dimension n;
  • there is no closed immersion C→Akn−1 of k-schemes, and hence no such curve embeds in Akn−1.

The tangent dimension is visible in the degree gap: m contains no element of degree below n and m2 contains no element of degree below 2n, so the n degrees n,…,2n−1 survive as independent tangent directions.

Facts & Assumptions

Given: A field k, an integer n≥1, the polynomial ring k[t] and the polynomial ring k[xn,xn+1,…,x2n−1] on the finite variable family {n,n+1,…,2n−1}, the point 0∈k, the subring R:=k[tn,…,t2n−1]⊆k[t], the scheme C=Spec⁡R over k, and the Axiom of Choice.

[F1]

The polynomial ring over a commutative ring as finitely supported coefficient sequences with convolution: k[t] is the set of finitely supported coefficient functions N→k with (a+b)j=aj+bj and (ab)j=∑i+l=jaibl, so tatb=ta+b and every polynomial has coefficients; iterating with the finitely many variables of the family gives k[xn,…,x2n−1].

[F2]

Universal property of a polynomial ring on an arbitrary family of indeterminates: for commutative rings R,S, a ring homomorphism φ:R→S and a family (si)i∈I in S, there is a unique ring homomorphism R[xi:i∈I]→S restricting to φ on R and sending xi↦si; for R=S= a common field this is the unique k-algebra map with prescribed values on the variables.

[F3]

First isomorphism theorem for rings: R/ker⁡f≅im⁡f: a ring homomorphism with kernel J induces an isomorphism from the quotient ring to its image.

[F4]

Monomials, coefficients, degree in each variable and total degree in F[x1,…,xn]: every polynomial in F[x1,…,xn] over a field F has a unique finite monomial expansion, so two elements of k[t] are equal exactly when all coefficients agree; each monomial has a total degree.

[F5]

A polynomial ring in finitely many indeterminates over an integral domain is an integral domain: a polynomial ring in finitely many variables over an integral domain is an integral domain; in particular k[t] is a domain and so is every subring of it.

[F6]

Every field is a commutative ring with 1≠0; it is an integral domain, and it is a commutative division ring: every field is a commutative ring with 1≠0 and is an integral domain.

[F7]

Integral elements over a commutative ring and algebraic integers: for a ring homomorphism A→B, an element b∈B is integral over A when it is a root of a monic polynomial in A[X].

[F8]

Integral elements over a nonzero base ring form a subring: for commutative rings A⊆B with A≠0, the elements of B integral over A form a subring of B.

[F9]

Injective integral extensions preserve Krull dimension: assuming the Axiom of Choice, an injective integral extension A⊆B of nonzero commutative rings satisfies dim⁡A=dim⁡B.

[F10]

A polynomial ring in n variables over a field has dimension n: for a field k and n≥0, dim⁡k[x1,…,xn]=n; in particular dim⁡k[t]=1.

[F11]

A Zariski-closed subset is irreducible exactly when its radical defining ideal is prime, and then it has a unique generic point: assuming the Axiom of Choice, a nonempty Zariski-closed subset Z⊆Spec⁡R is irreducible if and only if its radical defining ideal is prime.

[F12]

The intrinsic cotangent space: the intrinsic cotangent space is CxX=mx/mx2, a vector space over the residue field κ(x); at a k-rational point κ(x)=k.

[F13]

The intrinsic Zariski tangent space: the intrinsic tangent space is TxX=Hom⁡κ(x)(CxX,κ(x)), and at a k-rational point it is Hom⁡k(mx/mx2,k).

[F14]

The space L(V,W) of linear maps with pointwise addition and scalar multiplication: the set of linear maps between F-vector spaces is an F-vector space under pointwise operations.

[F15]

The dual family (b∗)b∈B associated to a Hamel basis B, defined by b∗(c)=δbc: for a basis B of a vector space V, the coordinate functional b∗ is defined by b∗(c)=δbc on basis elements and extended linearly using the unique finite basis expansion.

[F16]

Basis of a vector space: a linearly independent spanning subset; and ordered basis: an injective finite list whose image is a basis: a basis is a linearly independent spanning subset; every element is a unique finite linear combination of basis elements.

[F17]

Finite-dimensional vector space, and its dimension dim⁡FV; infinite-dimensional means having no finite basis: a vector space with a finite basis B≈n is n-dimensional, and dim⁡FV is that unique n; isomorphic vector spaces have equal dimension because the image of a basis under an isomorphism is a basis.

[F18]

Schemes and morphisms over a base: a k-scheme is a scheme with a morphism to Spec⁡k, and a k-morphism commutes with the structure maps; a k-rational point is a section over Spec⁡k.

[F19]

Morphisms of schemes: scheme morphisms are the morphisms of locally ringed spaces, and they compose.

[F20]

Affine schemes are contravariantly equivalent to commutative rings: ring maps A→B correspond contravariantly to morphisms Spec⁡B→Spec⁡A, so k-algebra homomorphisms A→k are the k-rational points of Spec⁡A.

[F21]

Evaluation at a point has kernel (x_1-a_1, ..., x_n-a_n): the evaluation map k[x1,…,xn−1]→k at a=(a1,…,an−1) has kernel (x1−a1,…,xn−1−an−1), which is a maximal ideal.

[F22]

Closed immersions of schemes: a morphism is a closed immersion when its underlying map is a homeomorphism onto a closed subset and the structure sheaf map is surjective.

[F23]

Closed immersions of schemes: for a closed immersion i:Z→Y, the structure-sheaf map OY→i∗OZ is surjective. At z↦y, its stalk map OY,y↠OZ,z is therefore a surjective local homomorphism. It maps the maximal ideal onto the maximal ideal, and hence induces a surjection on cotangent spaces at rational points; dualizing gives an injection on tangent spaces.

[F24]

The Jacobian kernel computes the tangent space: for any field, I⊆k[t1,…,tm], X=Spec⁡(k[t]/I), a rational point a∈X(k) and any finite generating list of I, one has TaX≅ker⁡J(a)⊆km.

[F25]

If dim⁡FV=n and U is a linear subspace of V, then U is finite-dimensional, dim⁡FU≤n, and dim⁡FU=n if and only if U=V: a linear subspace U of a finite-dimensional vector space V is finite-dimensional with dim⁡FU≤dim⁡FV.

[F28]

The Axiom of Choice: every family of nonempty sets admits a choice function; the statement and the cited steps below are the only uses recorded.

Verification

technique · direct
1.1givenF1F2F3F5F6F18

The image R=ψ(k[xn,…,x2n−1]) of the unique k-algebra map ψ with xi↦ti given by [F2] is a subring of k[t] and a finite-type k-algebra, and [F3] identifies R with k[xn,…,x2n−1]/ker⁡ψ; by [F5, F6] the ring k[t] is a domain, hence so is its subring R, and C=Spec⁡R is a k-scheme by [F18].

2.1step 1.1F1F2F3F4algebra

The subring description: every element of R is a k-linear combination of products of the generators tn,…,t2n−1 by [F2, F3], and every nonempty such product is ti1+⋯+ir with i1+⋯+ir≥n by [F1], so R⊆k⋅1+span⁡k{tj:j≥n}; conversely 1∈R and tj∈R for every j≥n, by strong induction on j (tj is a generator for n≤j≤2n−1, and tj=tj−ntn with j−n≥n for j≥2n); hence R=k⋅1⊕span⁡k{tj:j≥n} with the sum direct and coefficients unique by [F4].

2.2step 1.1F1F18F22F23

Suppose for contradiction that ι:C→Akn−1 is a closed immersion of k-schemes, where Akn−1=Spec⁡k[x1,…,xn−1] by [F1, F18]. By [F22] and [F23], the induced map on local rings is surjective at every source point.

3.1step 1.1step 2.1F3F5F11F20F28

The origin and irreducibility: the constant-coefficient map ε:R→k is a surjective k-algebra homomorphism whose kernel is m=span⁡k{tj:j≥n}=(tn,…,t2n−1)R by step 2.1, so [F3] gives R/m≅k, making m maximal with residue field k and exhibiting 0:=m as the k-rational point ε of C under [F20]; since R is a domain by step 1.1, the zero ideal is prime and [F11] applied to the nonempty closed subset Spec⁡R=V(0) shows that C is irreducible.

3.2step 1.1step 2.1F7F8F9F10F28

The dimension is one: t is integral over R because it is a root of the monic polynomial Xn−tn∈R[X] by [F7], and the integral elements of k[t] over R form a subring by [F8] containing R and t, hence containing R[t]=k[t]; thus R⊆k[t] is an injective integral extension of nonzero commutative rings and dim⁡R=dim⁡k[t]=1 by [F9] and [F10], with the Axiom of Choice entering exactly through [F9].

4.1step 2.1step 3.1F4F12F16algebra

The tangent directions: m2=span⁡k{ts:s≥2n}, because a product of two elements of m is a k-linear combination of monomials tj+l with j,l≥n and hence lies in that span, while conversely ts=ts−n⋅tn∈m2 for every s≥2n by step 2.1; therefore m=span⁡k{tn,…,t2n−1}⊕m2, and the classes bi:=ti+m2 for n≤i≤2n−1 form a k-basis of the cotangent space m/m2 by [F12, F16, F4].

4.2step 1.1step 3.1step 2.2F2F18F19F20F21

The points: 0∈C(k) by step 3.1 composes with ι to a k-rational point p=ι∘0 of Akn−1 by [F18, F19]. Under the anti-equivalence [F20] the point p corresponds to a k-algebra map k[x1,…,xn−1]→k, that is, to a tuple a∈kn−1 with maximal ideal (x1−a1,…,xn−1−an−1) by [F2, F21].

5.1step 3.1step 4.1F12F13F14F15F16F17algebra

The tangent dimension: T0C=Hom⁡k(m/m2,k) is a k-vector space by [F13, F14, F12], and for each i the coordinate functional bi∗ of [F15] is an element of it; every λ∈T0C satisfies λ=∑iλ(bi)bi∗ because both sides are k-linear and agree on the basis (bi) of [F16], and ∑icibi∗=0 forces cj=0 by evaluation at bj; hence (bn∗,…,b2n−1∗) is a k-basis of T0C with n elements and dim⁡kT0C=n by [F17].

6.1step 2.2step 4.2step 5.1F12F13F23F24F25F26algebra

The contradiction: by step 2.2 and [F23], the stalk map OAn−1,p↠OC,0 is a surjective local k-homomorphism. It maps the maximal ideal mp onto m0, hence maps mp2 onto m02 and induces a surjection mp/mp2↠m0/m02. Dualizing over the common residue field k yields an injection T0C↪TpAkn−1 by [F12, F13]. Applying [F24] to the affine space with actual ideal (0) gives TpAkn−1≅ker⁡(0:kn−1→0)=kn−1; thus [F25] and [F26] imply dim⁡kT0C≤n−1. But step 5.1 gives dim⁡kT0C=n, a contradiction. Therefore no closed immersion C→Akn−1 exists.

7.1step 3.1step 5.1step 3.2step 6.1

Conclusion: for every n≥1 the monomial curve C=Spec⁡k[tn,…,t2n−1] is irreducible of dimension one (steps 3.1 and 3.2), its tangent space at the k-rational origin has dimension exactly n (step 5.1), and it admits no closed immersion into Akn−1 (step 6.1); the tangent dimension of an irreducible curve is therefore unbounded, completing the source's exercise with an irreducible witness.

8.1step 3.1step 4.1step 5.1step 3.2step 2.2step 6.1F28algebra∎

Boundary and scope dispositions: C is nonempty and irreducible with the k-rational point 0 by step 3.1, and Ak0=Spec⁡k is nonempty, so no boundary object is empty; the zero cases are the zero ideal of k[t] used in step 3.1 and the zero vector of each k-vector space, and for n as small as possible the ideal m is nonzero and principal-generated by t; the minimal instance n=1 gives R=k[t], C=Ak1, m/m2=k⋅t of dimension 1, with the closed-embedding obstruction against Ak0 still delivered by step 6.1; the degenerate case of the construction is this same n=1 endpoint, where the subring is all of k[t], the integral extension of step 3.2 is an isomorphism and no higher-degree gap survives, while for n≥2 the degree gap [n,2n−1] between the least element of m and the least element of m2 is exactly the source of the n independent directions in steps 4.1 and 5.1, its endpoint being 2n−1; every construction is canonical, the only choice-theoretic inputs being the explicitly declared suppliers [F9, F11] named in steps 3.1 and 3.2, while the tuple a is determined by the rational point p, and no other simultaneous or dependent choice occurs; and no biconditional is asserted as a claim, the only equivalences used being the anti-equivalence of [F20], the irreducibility criterion of [F11] applied in one direction and the defining sheaf-surjectivity of [F23] applied in one direction, so the iff axes are vacuous here.

Source qualification

The source is Milne, Algebraic Geometry v6.10, Exercise 4-5 (printed p. 99): "For each n, show that there is a curve C and a point P on C such that the tangent space to C at P has dimension n (hence C cannot be embedded in An−1)." The book's solution (printed p. 223) takes C to be the union of the coordinate axes in An and adds: "Of course, if you want C to be irreducible, then this is more difficult." This item supplies the irreducible witness C=Spec⁡k[tn,…,t2n−1], the monomial curve used in the standard solution of that harder variant, and proves the three claims directly from the library's suppliers: the tangent space is computed intrinsically as the dual of m/m2 rather than through an embedded presentation, and the closed-embedding obstruction is obtained from the Jacobian kernel bound for the (hypothetical) affine quotient presentation. The source is cited for the exercise and its coordination of the two cases; the irreducibility argument, the degree-gap computation and the embedding obstruction are carried out here, and the Axiom of Choice is declared and traced to the three named suppliers in the boundary step.

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