How statement and proof provenance work
The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.
- Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
- AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
- AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.
These labels describe origin, not correctness: citations and verification chips remain separate evidence.
The Beta density has finite positive Lebesgue integral
Statement
Assume Countable Choice. For every , the nonnegative function is Lebesgue measurable on and
Facts & Assumptions
Given: Countable Choice and positive real numbers .
Countable Choice is the axiom assumed by the bounded-Riemann-to-Lebesgue integral theorem. The Axiom of Countable Choice ().
The real Beta function is the improper integral of on . Euler's real Beta integral.
For positive , . The real Beta--Gamma identity.
The Euler Gamma integral converges to a finite real value for every positive argument. Euler's Gamma integral converges exactly for positive real parameters.
A bounded Riemann-integrable function on a closed bounded interval is Lebesgue measurable and has the same Lebesgue and Riemann integrals under Countable Choice. A bounded Riemann integrable function on a closed bounded interval is Lebesgue measurable and has the same integral.
Continuous functions on a closed bounded interval are bounded and Riemann integrable. A continuous function on is Riemann integrable, by Heine-Cantor and Riemann's criterion.
Increasing limits of nonnegative measurable functions have integrals equal to the increasing limit of their integrals. Monotone convergence for the integral.
The improper Beta integral converges for positive parameters. Euler's Beta integral converges exactly for two positive parameters.
Positive real powers are continuous on . Continuity and derivatives of positive-base real powers.
Under Countable Choice, the stated Lebesgue set function is a complete measure on the Lebesgue sigma-algebra, which contains every Borel set. We use its restriction to . Lebesgue measurable sets, the family , and the restricted set function Assuming countable choice, is a sigma-algebra containing every elementary set and is a complete measure extending elementary volume Assuming countable choice, every Borel subset of is Lebesgue measurable.
For , is the improper integral , with separate improper ends at zero and infinity. The real Gamma function by Euler's integral.
The logarithm is strictly increasing on and . Order, continuity, range, and the product, quotient, and reciprocal laws for the natural logarithm.
The exponential is continuous and strictly increasing on , and for every real . The exponential function is strictly increasing, The exponential is positive and satisfies .
Proper Riemann integration preserves nonnegativity and pointwise order; if an integrable function is bounded below by on , its integral is at least . If on and both are integrable then ; and .
Splitting a convergent improper integral at a nonsingular finite point changes its value by the corresponding proper integral and preserves convergence of the remaining tail. Improper convergence is independent of finite truncations and split points.
Proof
Given: Countable Choice and .
By [F8], is continuous and hence Borel and Lebesgue measurable on with the measure in [F9]. For each integer , one has , so its restriction to is continuous, hence bounded and Riemann integrable by [F5], and [F4] identifies its Lebesgue integral with its Riemann integral. The indicators of these intervals increase pointwise to one, so the truncated functions increase to .
Fix and put for . For , [F12] gives , so . By [F11] and [F13], . The function is continuous on by [F8] and [F13], hence bounded and Riemann integrable by [F5]. The lower integral bound [F14] therefore gives .
By [F6], the Lebesgue integral of is the limit of the truncated integrals from step 1.1. The same truncations define the improper integral in [F1], which converges by [F7]; therefore the limit is .
By [F3] and [F10], is finite. The integrand is positive on by [F11] and [F13]. Every compact truncation integral on either side of is nonnegative by [F14], and its finite improper limit is nonnegative as well. Splitting at and by [F15] gives . Thus for every , with strict positivity proved here rather than inferred from convergence alone.
Apply step 2.2 with . The identity in [F2] expresses as a quotient of finite positive numbers, hence . Together with step 2.1 this proves the displayed Lebesgue integral identity and its endpoint bounds.
Depends on
- The Axiom of Countable Choice ($\mathrm{AC}_\omega$)
- Euler's real Beta integral
- Euler's Beta integral converges exactly for two positive parameters
- The real Beta--Gamma identity
- Euler's Gamma integral converges exactly for positive real parameters
- A continuous function on $[a,b]$ is Riemann integrable, by Heine-Cantor and Riemann's criterion
- A bounded Riemann integrable function on a closed bounded interval is Lebesgue measurable and has the same integral
- Monotone convergence for the integral
- Continuity and derivatives of positive-base real powers
- Lebesgue measurable sets, the family $\mathcal{L}(\mathbb{R}^n)$, and the restricted set function $\lambda_n$
- Assuming countable choice, $\mathcal{L}(\mathbb{R}^n)$ is a sigma-algebra containing every elementary set and $\lambda_n$ is a complete measure extending elementary volume
- Assuming countable choice, every Borel subset of $\mathbb{R}^n$ is Lebesgue measurable
- The real Gamma function by Euler's integral
- Real powers for positive bases, with the zero-base positive-exponent convention
- Order, continuity, range, and the product, quotient, and reciprocal laws for the natural logarithm
- The exponential function is strictly increasing
- The exponential is positive and satisfies $\exp(-x)=1/\exp(x)$
- If $f \le g$ on $[a,b]$ and both are integrable then $\int_a^b f \le \int_a^b g$; and $m(b-a) \le \int_a^b f \le M(b-a)$
- Improper convergence is independent of finite truncations and split points
Used by
- Beta distribution Definition
- Beta-Binomial conjugate update Theorem
- Dirichlet density normalization by iterated Beta integrals Theorem
Dependency tree · two levels
114 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- Gelman et al., Bayesian Data Analysis, 3rd ed., §2.1 (standard reference, not scraped)
- Johnson, Ott & Dogucu, Bayes Rules!, Chapter 3, §3.1 (standard reference, not scraped)