Alphabeta Math
LemmaStatement: AI-adaptedProof: AI-generatedSession-authored (Fable 5 assisted)precheck passaudited 2026-08-01
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  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
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Distinct connected components are anticomplete, and distinct anticonnected components are complete

Statement

Distinct connected components of a graph are anticomplete to one another. Distinct anticomponents are complete to one another.

Facts & Assumptions

Given: A finite graph GG.

[L1]

Connected components partition the vertices into maximal connected parts (The connected components of a graph partition its vertex set and are its maximal connected subgraphs).

[L2]

Anticomponents of GG are connected components of G\overline G (The anticonnected components of GG are exactly the connected components of G\overline G).

[L3]
[F1]

Anticomplete and complete pairs have respectively no and all cross edges (Edges between disjoint vertex sets; complete, anticomplete, pure and mixed pairs).

Proof

technique · direct
1.1

No edge joins two distinct connected components, since such an edge would connect them into one component. Thus distinct components are anticomplete.

L1F1
2.1

Distinct anticomponents of GG are distinct connected components of G\overline G, so they are anticomplete in G\overline G by step 1.1 applied there.

L2step 1.1
3.1

Complementing back makes those two sets complete in GG.

step 2.1L3

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · next 3 levels

Direct dependencies and their dependencies through the next three levels: 18 results over 10 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.

Sources