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The Jacobi weight defines a finite positive measure with full support
Statement
Assume Countable Choice. Let and define Let be Lebesgue measure restricted to the Borel subsets of , and set . Then is a finite positive Borel measure, its relative support is all of , and every moment is finite for .
Facts & Assumptions
Given: Countable Choice and real parameters .
The Axiom of Countable Choice (): the Countable Choice axiom is assumed.
A power above exponent minus one is Lebesgue integrable at zero: for every , on , extended by zero at zero, is nonnegative and Lebesgue integrable with integral .
Assuming countable choice, is a sigma-algebra containing every elementary set and is a complete measure extending elementary volume and Assuming countable choice, every Borel subset of is Lebesgue measurable: under [A1], Borel sets in lie in the Lebesgue sigma-algebra and Lebesgue measure is a measure there; an interval has measure its length (A box in with parameters is Lebesgue measurable of measure , whichever of its faces are included).
Continuity and derivatives of positive-base real powers, Sums, scalar multiples, products, absolute values, maxima, minima and quotients with nonvanishing denominator of continuous functions are continuous, as are constants, the identity and every polynomial function, and A composite of continuous functions is continuous, with no side hypothesis of the kind the composition of limits needs: positive-base powers are continuous, as are the finite products and compositions used in the density.
The measure with density relative to : a nonnegative measurable density defines the measure by .
For a nonempty subset of with , compactness, closedness and boundedness, pseudocompactness, and attainment of extrema by every continuous real-valued function are equivalent: a continuous real function on a compact interval attains its finite minimum and maximum.
Monotonicity and nonnegative homogeneity of the nonnegative integral: the nonnegative integral is monotone and positively homogeneous.
A bounded Riemann integrable function on a closed bounded interval is Lebesgue measurable and has the same integral: bounded Riemann-integrable functions on compact intervals have the same Lebesgue integral under [A1]; Substitution: if is differentiable on with integrable and is continuous on an interval containing , then gives the ordinary Riemann substitution on intervals away from the singular endpoints.
Monotone convergence for the integral and Closure properties of measurable functions used by the integral: increasing nonnegative measurable cutoffs have integrals increasing to the integral of their limit.
Riemann's criterion: a bounded on is Darboux integrable if and only if for every real there is a partition with : a bounded function whose Darboux gaps can be made arbitrarily small is Riemann integrable.
Proof
The density is nonnegative and continuous on by [F3]. For every real , its strict superlevel is all of when , and the relatively open set when ; thus the endpoint extension is Borel, and [F2] makes it Lebesgue measurable. Put and . On the factor is at most , and on the factor is at most .
To justify the endpoint integral comparisons, set for . Its superlevels are Borel by step 1.1. It is bounded and continuous except possibly at the two cutoff points; isolating these in intervals of arbitrarily small total length and using uniform continuity on the remaining compact pieces proves the Darboux criterion [F9]. The same argument applies to each half-interval restriction and to the corresponding power cutoffs. Consequently [F7] and the Riemann substitutions and give and , using [F1] and [F6] for the final bounds. Since pointwise, including at the endpoints, [F8] gives .
By [F4], is a positive Borel measure, and step 2.1 makes its total mass finite. If is nonempty and relatively open, choose a nondegenerate closed interval . The density is continuous and strictly positive on , so [F5] gives a minimum there. By [F2] and monotonicity [F6], . Therefore every point is in the relative support.
For every , on , so [F6] gives by step 2.1. This proves all moment claims.
Depends on
- A power above exponent minus one is Lebesgue integrable at zero
- The Axiom of Countable Choice ($\mathrm{AC}_\omega$)
- Lebesgue measurable sets, the family $\mathcal{L}(\mathbb{R}^n)$, and the restricted set function $\lambda_n$
- Assuming countable choice, $\mathcal{L}(\mathbb{R}^n)$ is a sigma-algebra containing every elementary set and $\lambda_n$ is a complete measure extending elementary volume
- Assuming countable choice, every Borel subset of $\mathbb{R}^n$ is Lebesgue measurable
- The measure with density $f$ relative to $\mu$
- Closure properties of measurable functions used by the integral
- For a nonempty subset of $\mathbb{R}^n$ with $n\ge1$, compactness, closedness and boundedness, pseudocompactness, and attainment of extrema by every continuous real-valued function are equivalent
- A box in $\mathbb{R}^n$ with parameters $a_i\le b_i$ is Lebesgue measurable of measure $\prod_{i<n}(b_i-a_i)$, whichever of its faces are included
- Monotonicity and nonnegative homogeneity of the nonnegative integral
- Substitution: if $\varphi$ is differentiable on $[c,d]$ with $\varphi'$ integrable and $f$ is continuous on an interval containing $\varphi([c,d])$, then $\int_{\varphi(c)}^{\varphi(d)} f = \int_c^d (f\circ\varphi)\,\varphi'$
- Continuity and derivatives of positive-base real powers
- Sums, scalar multiples, products, absolute values, maxima, minima and quotients with nonvanishing denominator of continuous functions are continuous, as are constants, the identity and every polynomial function
- A composite of continuous functions is continuous, with no side hypothesis of the kind the composition of limits needs
- Monotone convergence for the integral
- A bounded Riemann integrable function on a closed bounded interval is Lebesgue measurable and has the same integral
- Riemann's criterion: a bounded $f$ on $[a,b]$ is Darboux integrable if and only if for every real $\varepsilon > 0$ there is a partition $P$ with $U(f,P) - L(f,P) < \varepsilon$
Used by
- Weighted product Gauss quadrature after the Duffy transform Algorithm
- The Duffy weighted product rule has an explicit bound using pure coordinate derivatives Corollary
- The Gauss–Jacobi quadrature rule Definition
- Gauss–Jacobi nodes and weights are well-defined Lemma
- Gauss–Jacobi exactness and the derivative remainder Theorem
Dependency tree · two levels
115 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- Christopher J. Bishop, The Riemann Mapping Theorem, Chapter 3 §3, Gauss-Jacobi quadrature lecture notes (standard reference, not scraped)