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A Gaussian error contrast has the induced multivariate-normal law

Statement

Assume AC and the Gaussian branch of the finite-dimensional mixed model. Let X∈Rn×p have full column rank with p<n, let K∈Rn×(n−p) be an error-contrast matrix, and let V=ZGZT+R=Cov⁡(Y). Then KTY∼Nn−p(0,KTVK). The contrast law does not depend on β. The matrix KTVK may be singular; positive definiteness is a separate hypothesis when a density is needed.

Facts & Assumptions

Given: The centered Gaussian mixed model, AC, a full-rank fixed design, and an error-contrast matrix K.

[F1]

Y=Xβ+Zb+ε with centered b,ε, covariance matrices G,R, and b independent of ε. Finite-dimensional linear mixed model with explicit longitudinal roles.

[F2]

Under AC, the concatenated vector (b,ε) has a multivariate-normal law. Gaussian branch of the linear mixed model.

[F3]

The response covariance is V=ZGZT+R. Marginal covariance of the linear mixed model.

[F4]

An error-contrast matrix has shape n×(n−p) and satisfies XTK=0. Error-contrast matrix for a full-rank fixed design.

[F5]

Every scalar linear projection of a multivariate-normal vector has the specified univariate normal law, including variance zero. Multivariate normal law, including singular covariance.

[F6]

Expectation is linear on finite sums of integrable random variables. The Lebesgue integral is linear on L1(μ).

[F7]

Covariance is a centered second moment and is bilinear in finite linear combinations. Moments, variance, and covariance on a probability space, Covariance is symmetric and bilinear in finite linear combinations.

[F8]

A fixed finite-dimensional linear map is continuous and Borel measurable, so its composition with a Borel random vector is a Borel random vector. Every Euclidean linear map has a unique matrix and satisfies ∥Lh∥2≤K∥h∥2 for some K≥0, A continuous map has Borel preimages of Borel sets.

[F9]

A univariate normal law has characteristic function exp⁡(itm−t2σ2/2). Characteristic function of a normal law.

[F10]

The characteristic function of Nd(m,Σ) is exp⁡(itTm−tTΣt/2). Characteristic function of a multivariate normal law.

[F11]

The characteristic function of a multivariate-normal law uniquely determines its Borel probability law, including singular covariance. Characteristic function of a multivariate normal law.

[A1]

Proof

Given: The hypotheses in the Statement.

1.1F1F3F6

By [F1], Y−Xβ=Zb+ε is centered. Linearity [F6] gives EY=Xβ, and [F3] gives Cov⁡(Y)=V.

2.1A1F1F2F4F5F6F7step 1.1

Fix u∈Rn−p. Since XTK=0 by [F4], uTKTY=uTKT(Zb+ε), a scalar linear projection of the jointly Gaussian vector in [F2]; it is normal by [F5]. Its mean is zero by [F1] and [F6], and its variance is uTKTVKu by step 1.1 and covariance bilinearity [F7].

3.1F8F9F10F11step 2.1∎

By [F8], Q=KTY is a Borel random vector. For each u, [F9] and step 2.1 give EeiuTQ=exp⁡(−uTKTVKu/2). This is the characteristic function of Nn−p(0,KTVK) by [F10]; uniqueness [F11] gives the stated law. Its mean and covariance do not depend on β, so neither does its law.

Depends on

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