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A Gaussian error contrast has the induced multivariate-normal law
Statement
Assume AC and the Gaussian branch of the finite-dimensional mixed model. Let have full column rank with , let be an error-contrast matrix, and let . Then The contrast law does not depend on . The matrix may be singular; positive definiteness is a separate hypothesis when a density is needed.
Facts & Assumptions
Given: The centered Gaussian mixed model, AC, a full-rank fixed design, and an error-contrast matrix .
with centered , covariance matrices , and independent of . Finite-dimensional linear mixed model with explicit longitudinal roles.
Under AC, the concatenated vector has a multivariate-normal law. Gaussian branch of the linear mixed model.
The response covariance is . Marginal covariance of the linear mixed model.
An error-contrast matrix has shape and satisfies . Error-contrast matrix for a full-rank fixed design.
Every scalar linear projection of a multivariate-normal vector has the specified univariate normal law, including variance zero. Multivariate normal law, including singular covariance.
Expectation is linear on finite sums of integrable random variables. The Lebesgue integral is linear on .
Covariance is a centered second moment and is bilinear in finite linear combinations. Moments, variance, and covariance on a probability space, Covariance is symmetric and bilinear in finite linear combinations.
A fixed finite-dimensional linear map is continuous and Borel measurable, so its composition with a Borel random vector is a Borel random vector. Every Euclidean linear map has a unique matrix and satisfies for some , A continuous map has Borel preimages of Borel sets.
A univariate normal law has characteristic function . Characteristic function of a normal law.
The characteristic function of is . Characteristic function of a multivariate normal law.
The characteristic function of a multivariate-normal law uniquely determines its Borel probability law, including singular covariance. Characteristic function of a multivariate normal law.
AC holds. The Axiom of Choice.
Proof
Given: The hypotheses in the Statement.
By [F1], is centered. Linearity [F6] gives , and [F3] gives .
Fix . Since by [F4], , a scalar linear projection of the jointly Gaussian vector in [F2]; it is normal by [F5]. Its mean is zero by [F1] and [F6], and its variance is by step 1.1 and covariance bilinearity [F7].
By [F8], is a Borel random vector. For each , [F9] and step 2.1 give . This is the characteristic function of by [F10]; uniqueness [F11] gives the stated law. Its mean and covariance do not depend on , so neither does its law.
Depends on
- Finite-dimensional linear mixed model with explicit longitudinal roles
- Gaussian branch of the linear mixed model
- Error-contrast matrix for a full-rank fixed design
- Multivariate normal law, including singular covariance
- Moments, variance, and covariance on a probability space
- Marginal covariance of the linear mixed model
- The Lebesgue integral is linear on $L^1(\mu)$
- Covariance is symmetric and bilinear in finite linear combinations
- Every Euclidean linear map has a unique matrix and satisfies $\|Lh\|_2\le K\|h\|_2$ for some $K\ge0$
- A continuous map has Borel preimages of Borel sets
- Characteristic function of a normal law
- Characteristic function of a multivariate normal law
- Uniqueness of a law from its characteristic function
- The Axiom of Choice
Used by
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Sources
- Fan Li, STA610 Lecture 4: Maximum Likelihood Estimation and Inference for the Hierarchical Normal Model, PDF pp. 4–5 (standard reference, not scraped)
- Duchateau, Janssen, and Rowlands, Linear Mixed Models, Chapter 2 §2.4.2 (standard reference, not scraped)