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Principal Beltrami solutions and uniform inverse-gradient integrability

Statement

Assume the Axiom of Choice and Countable Choice. Fix 0≤κ<1 and R,S>0. For every measurable μ supported in DR={∣z∣<R} with ∥μ∥∞≤κ, there is a unique quasiconformal homeomorphism Φ:C→C satisfying ∂ˉΦ=μ∂Φ,Φ(z)=z+O(1/z)(z→∞). Choose any fixed 2<r≤pκ from the near-two inversion result, and put σ=r−2>0. Uniformly over all these coefficients, ∥Φ−z∥W1,r(C)+∥Φ−z∥∞+[Φ−z]C0,1−2/r≤Cκ,r,R,∫DS∣∂Φ∣−σ dA≤Cκ,r,R,S. The Jacobian and ∂Φ are positive and nonzero almost everywhere, respectively, so the negative power is well-defined almost everywhere. In particular, for any ∣k∣=1 and f(z)=eikΦ(z), ∥f∥W1,r(DS)+∥∣∂f∣−1∥Lσ(DS)≤Cκ,r,R,S. For 0<σ<1 the displayed Lσ quantity means (∫∣∂f∣−σ)1/σ, without asserting a norm triangle inequality.

Facts & Assumptions

Given: The Axiom of Choice and Countable Choice, a coefficient μ and the fixed parameters in the statement.

[F1]

The measurable Riemann mapping theorem gives a sphere homeomorphic solution, unique up to Möbius postcomposition. A 1-quasiconformal map is conformal, and an injective holomorphic map has nonzero derivative. (The measurable Riemann mapping theorem on the sphere, Every 1-quasiconformal homeomorphism is conformal, An injective holomorphic map has no critical point and is biholomorphic onto its image)

[F2]

The inverse of a quasiconformal map has the same dilatation. Both maps preserve null sets, have positive Jacobian almost everywhere, and satisfy the area formula; at common differentiability points their derivatives are inverses. The weighted area formula follows from its set version by simple-function approximation. (The inverse of a quasiconformal map is quasiconformal with the same dilatation, An analytically quasiconformal homeomorphism distorts quadrilateral moduli by at most K)

[F3]

The Cauchy transform has ∂ˉCf=f, ∂Cf=Bf, global W1,r and Hölder bounds for compact Lr data with r>2. The inverse I−μB is bounded on L2 and Lr uniformly for 2≤r≤pκ. (Planar Cauchy and Beurling transforms and near-two Beltrami inversion)

[F4]

Distributional harmonic functions are smooth; an entire bounded holomorphic function is constant. Convolution with an L1 kernel is bounded on L2. (Weyl's lemma for the Laplacian, Liouville's theorem: every bounded entire function is constant, Young's convolution inequality under Countable Choice)

[A1]

The Axiom of Choice is used at [F1]–[F2], and Countable Choice at [F3]–[F4]. (The Axiom of Choice, The Axiom of Countable Choice (ACω))

Proof

Given: The data in the statement.

1.1A1F1givenalgebra

Take a solution from [F1] fixing infinity. Outside DR its coefficient is zero, so it is conformal there. In the infinity chart it is an injective holomorphic map fixing zero with nonzero derivative. Its Taylor expansion there gives az+b+O(1/z) in the original chart, with a≠0. Postcomposition by (w−b)/a gives the principal normalization. Any two principal solutions differ by a Möbius map by [F1]; since both fix infinity this map is affine, and their leading and constant Laurent coefficients force it to be the identity. This proves existence and uniqueness of Φ.

2.1F1F3F4step 1.1algebra

Set h=∂ˉΦ, which is in L2 and has support in D‾R by local quasiconformal Sobolev regularity and the zero coefficient outside. The Cauchy integral for compact L2 data is locally L2: on a fixed target disk the kernel restricted to all differences with DR is in L1, so [F4] applies; outside a larger disk its bound is C∥h∥1/∣z∣. Approximating h by smooth functions in a fixed support disk yields distributionally ∂ˉCh=h and ∂Ch=Bh, the latter by Beurling L2 boundedness. Thus ∂ˉ(Φ−z−Ch)=0. Applying ∂ and [F4] makes this distribution smooth harmonic; the original Cauchy–Riemann equation makes its representative holomorphic. It tends to zero at infinity by the principal normalization and the exterior Cauchy bound. Liouville gives Φ−z=Ch. Therefore ∂Φ=1+Bh, and the Beltrami equation says (I−μB)h=μ.

3.1F3step 2.1algebra

Let hr=(I−μB)−1μ in Lr. Its norm is at most Cκ∥μ∥r≤Cκ,R,r by [F3]. The equation gives hr=0 outside DR, hence hr∈L2 by Hölder on that disk. Compatibility of the L2 and Lr Beurling actions and uniqueness of the L2 inverse imply hr=h from step 2.1. Apply the Cauchy bounds in [F3] to Φ−z=Ch. This proves its W1,r, supremum and Hölder bounds. In particular Φ(DS) lies in a disk of radius S+Cκ,R,r, uniformly in μ.

4.1F2step 3.1algebra

By [F2], Ψ=Φ−1 has coefficient bounded by κ, supported in Φ(D‾R), and has the same principal expansion at infinity. Step 3.1 puts that support inside a fixed disk; applying step 3.1 to Ψ therefore gives a uniform Lr bound for ∂Ψ on every fixed disk. At common differentiability points, the derivative inverse formula gives ∣∂Ψ(Φ(z))∣=1/[(1−∣μ(z)∣2)∣∂Φ(z)∣]. Thus ∣∂Φ(z)∣−σ≤∣∂Ψ(Φ(z))∣σ. Change variables with z=Ψ(w) using [F2]; the bound JΨ≤∣∂Ψ∣2 gives ∫DS∣∂Φ∣−σ≤∫Φ(DS)∣∂Ψ(w)∣σ+2dA(w). Since σ+2=r, step 3.1 and the uniform disk containing Φ(DS) bound the right side. Null-set preservation in [F2] justifies all inverse identities and negative powers on common full-measure sets.

5.1F3step 3.1step 4.1algebra∎

On DS, ∣Φ∣≤S+Cκ,R,r. For ∣k∣=1, the exponential and its derivative are bounded on this range. To justify the Sobolev chain rule, set h=∂ˉΦ and approximate it in Lr by smooth functions hn supported in one fixed larger disk; the density and Cauchy bounds in [F3] give Φn=z+Chn→Φ in W1,r(DS+1) and uniformly on DS. The Cauchy integrals of these smooth data are smooth, and the uniform convergence keeps their ranges on DS in a fixed bounded set. The classical chain rule for fn=eikΦn gives ∂fn=ikeikΦn∂Φn and the corresponding ∂ˉ formula. Uniform convergence of the exponential factors and Lr convergence of the derivatives pass these identities to f=eikΦ in W1,r(DS). Step 3.1 supplies the uniform W1,r bound, while ∣∂f∣−σ≤eσ(S+C)∣∂Φ∣−σ and step 4.1 supply the negative-power bound. This proves the final assertion, including the case σ<1 with its stated integral convention.

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