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LemmaStatement: AI-adaptedProof: AI-adaptedPipeline-generatedprecheck passaudited 2026-10-02
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A reduced prepared hypersurface stays reduced nearby

Statement

Let n≥1 and let W be a Weierstrass polynomial of degree d≥1 in the last variable which is reduced as a germ at the origin of Cn (Reduced holomorphic germ for a hypersurface); write Z(W) for its zero set. Then, after shrinking to the product representative V×D of the finite local projection, every local equation germ of W is reduced: for every q∈Z(W)∩(V×D) the translate of the germ of W at q is a reduced germ at the origin of Cn in the sense of Reduced holomorphic germ for a hypersurface.

The assertion concerns this principal hypersurface equation and its zero set; it is not a statement about arbitrary analytic germs.

Facts & Assumptions

Given: A Weierstrass polynomial W of degree d≥1 in the last variable, reduced as a germ at the origin, and the product neighbourhood V×D of the finite local projection of W.

[F1]

A Weierstrass polynomial of degree d is monic in the last variable, its lower coefficients vanish at the origin, and it is regular in the last variable of order d; a germ is regular of order d when its vertical slice has a zero of exact order d at the origin (Weierstrass polynomials in the last variable, Regular holomorphic germs in the last variable).

[F2]

For a reduced germ that is regular of order d with preparation W, the discriminant DW=Disc⁡T(W) is a nonzero base germ and W is square-free over K=Frac⁡(On−1,0) (Reduced preparation has nonzero discriminant); here the reduced regular germ is W itself, prepared as W=1⋅W.

[F3]

DW(z′)=Disc⁡(W(z′,⋅)) is the coefficient discriminant of the monic slice, and it vanishes exactly when that slice has a repeated root (Discriminant and branch set of a fixed Weierstrass projection, The discriminant is ∏i<j(αi−αj)2 and vanishes exactly when a monic polynomial has a repeated root).

[F4]

A nonzero holomorphic function on a connected open set does not vanish on a nonempty open subset (A holomorphic function vanishing on a nonempty open subset of a domain vanishes identically).

[F5]

Units of a germ ring are exactly the germs with nonzero value at the base point; irreducible elements are nonzero nonunits, so an irreducible germ vanishes at its base point (A germ is a unit exactly when its value at 0 is nonzero, so Om,0 is local, Irreducible and prime elements of an integral domain).

[F6]

A germ regular in the last variable of order m≥1 has, after preparation, a neighbourhood on which every nearby slice has exactly m zeros in a fixed vertical disc, counted with multiplicity (Nearby slices of a regular germ have the same zero count, Weierstrass preparation theorem).

[F7]

A holomorphic function of one variable with a zero at ζ0 factors as (z−ζ0)m times a nonvanishing holomorphic factor there, and a zero of a holomorphic function is a repeated root of a slice exactly when the slice derivative vanishes there (The order of a zero is the exponent in its local holomorphic factorization, A root is repeated exactly when it is also a root of the formal derivative).

Proof technique: direct — a nonreduced local germ would force the slice discriminant to vanish identically on a base neighbourhood, contradicting the nonzero discriminant.

Proof

1.1givenF1F2F3

By [F1] the germ W is regular in the last variable of order d and is its own preparation, so [F2] applies to it: DW is a nonzero base germ and [F3] identifies its vanishing with the existence of a repeated root in the slice W(z′,⋅). Shrink the product representative so that W and DW are defined on the connected base V and the finite-projection conclusions hold.

1.2givenF5assume-contra

Suppose for contradiction that some q=(q′,τ)∈Z(W)∩(V×D) has a nonreduced germ: Wq=g2h for an irreducible germ g at q. By [F5] the germ g is a nonzero nonunit, so g(q′,τ)=0.

2.1step 1.1step 1.2F1

The vertical slice ζ↦g(q′,ζ) is not identically zero near τ: the identity W=g2h holds on a neighbourhood of q, so if that slice vanished identically then the slice ζ↦W(q′,ζ) would vanish identically near τ, contradicting that this slice is the monic polynomial of degree d from step 1.1, which has only finitely many zeros. Hence g is regular in the last variable of some order m≥1 at q, by [F1] and the vanishing of g at q.

3.1step 2.1F6

Choose a product neighbourhood U0×{∣ζ−τ∣<ρ0} of q contained in the neighbourhood where W=g2h holds, and shrink ρ0 so the slice g(q′,⋅) has no zero on ∣ζ−τ∣=ρ0. Prepare the regular germ g at q: g=ugG with G a Weierstrass polynomial of degree m≥1 in the translated coordinates. Apply the stability of the slice zero count [F6] on this chosen disc and shrink the base to a neighbourhood U⊆U0 of q′; every slice g(z′,⋅), z′∈U, then has exactly m≥1 zeros counted with multiplicity in ∣ζ−τ∣<ρ0. In particular the product used below remains inside the factorization neighbourhood.

4.1step 2.1step 3.1F3F7

Fix z′∈U and let ζ be one of the m≥1 zeros of g(z′,⋅) supplied by step 3.1. Because the identity W=g2h holds on a neighbourhood of q, the slices satisfy W(z′,⋅)=g(z′,⋅)2h(z′,⋅) near ζ; by [F7] the slice of g has a zero of some order my≥1 at ζ, so the slice of W vanishes there to order at least 2my≥2. Thus ζ is a repeated root of W(z′,⋅), and [F7] gives ∂TW(z′,ζ)=0 while [F3] gives DW(z′)=0.

5.1step 1.1step 4.1F4discharge-contradiction

Every z′∈U therefore lies in the zero set of DW. If n=1, the base V is the single point of C0; step 4.1 gives DW=0 there, contradicting the nonzero constant DW from step 1.1. If n≥2, DW vanishes on the nonempty open set U, contradicting [F4] on the connected base V because DW is the nonzero base germ from step 1.1. Hence no point q∈Z(W)∩(V×D) has a nonreduced local germ.

6.1step 5.1∎

Shrinking to the product representative V×D fixed in step 1.1, every local equation germ of W at a point of its zero set is reduced, which is the assertion.

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