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- AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.
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A holomorphic function vanishing on a nonempty open subset of a domain vanishes identically
Statement
Let , let be a nonempty connected open set, and let be holomorphic (Holomorphic functions on an open subset of ). If there is a nonempty open set such that for every , then on .
This is the several-variable identity theorem at the strength the page supports: the hypothesis is a nonempty open set of zeros. An accumulation point of the zero set is neither assumed nor sufficient in several variables; the companion page records that stronger one-variable statement as false here.
Facts & Assumptions
Given: A nonempty connected open set , a holomorphic function , and a nonempty open set on which .
Holomorphic functions of several variables are smooth; every point has a polydisc on which and all mixed complex derivatives are holomorphic (Holomorphic functions of several variables are smooth and their complex derivatives are holomorphic).
A connected space has no nontrivial clopen subsets (For a topological space the following agree: no separation exists, the only clopen subsets are and , and every continuous map to the two-point discrete space is constant, Separation of a topological space, connected and disconnected spaces, clopen sets, and connected subsets).
The mixed complex derivative notation and the zero-order identity are those in the power-series and smoothness statement [L1]; maps and multi-index derivative notation in Euclidean space supplies the underlying multi-index arithmetic.
Polydiscs in are the coordinatewise discs of Balls, polydiscs and the distinguished boundary in .
Proof
For every multi-index , the derivative is holomorphic and therefore continuous on by [L1]; since on the open set , every derivative of is also on , so the set contains and is therefore nonempty.
The set is closed in , because it is the intersection over all multi-indices of the closed zero sets of the continuous functions .
The set is open in : if , choose a smaller polydisc centred at ; then every coefficient in the power-series expansion of on is , so [L1] gives on , and hence every derivative vanishes on as well, which means .
The set is a nonempty subset of that is both open in and closed in , so connectedness and [L2] force ; in particular vanishes at every point of , hence on .
Remarks
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Why the hypothesis is open-set vanishing and not an accumulation point. In one complex variable, accumulation of zeros implies equality by local factorisation and isolated zeros. In several variables the zero set of a nonzero holomorphic function can contain whole complex hypersurfaces, so the open-set hypothesis is the honest form at this stage.
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What the proof really uses. The proof needs only two page-level tools: holomorphic smoothness and the local power-series expansion. Once every derivative at one point vanishes, the power series on a smaller polydisc is identically zero, and connectedness propagates that local vanishing to the whole set.
Depends on
- Holomorphic functions of several variables are smooth and their complex derivatives are holomorphic
- For a topological space the following agree: no separation exists, the only clopen subsets are $\varnothing$ and $X$, and every continuous map to the two-point discrete space is constant
- Separation of a topological space, connected and disconnected spaces, clopen sets, and connected subsets
- Balls, polydiscs and the distinguished boundary in $\mathbb{C}^m$
- $C^k$ maps and multi-index derivative notation in Euclidean space
- Holomorphic functions on an open subset of $\mathbb{C}^m$
Used by
- The holomorphic functions on a domain in ℂᵐ have no zero divisors Corollary
- A nonzero holomorphic function on ℂ² whose zero set is an unbounded hyperplane Counterexample
- A holomorphic function on a domain in ℂ² vanishing on a set with an accumulation point vanishes identically False statement
- Conventions on this page, and what the several-variable identity theorem does not say Remark
- A nonconstant scalar holomorphic function on a domain in ℂᵐ is an open map Theorem
- An interior local maximum of the modulus forces a scalar holomorphic function to be constant Theorem
Dependency tree · two levels
42 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- J. Lebl, Tasty Bits of Several Complex Variables, v4.4, Thm. 1.2.7 (standard reference, not scraped)
- H. P. Boas, Lecture Notes on Multidimensional Complex Analysis, Ch. 2 (standard reference, not scraped)
- M. Jabbari, Notes for Analysis and Geometry of Several Complex Variables, Thm. 22(7) (standard reference, not scraped)