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The coinvariant algebra is a complete intersection with one-dimensional socle

Statement

Assume the Axiom of Choice, inherited from the published invariant-theory items. Let W act on the Cartan space h by reflections and on S=S(h) by graded algebra automorphisms, with coinvariant algebra C=S/I as in The coinvariant algebra of a finite Weyl group. Let w1,…,wr be homogeneous basic invariants of page degrees 2d1,…,2dr, where d1,…,dr are the classical degrees (deg⁡h=1; for the Cartan of sln they are 2,3,…,n), so that SW=C[w1,…,wr] (Chevalley shephard todd for finite weyl groups), and let ρ:S→C be the quotient by the ideal I=(w1,…,wr). Put N:=∑i=1r(di−1). Then:

  1. The sequence w1,…,wr is a homogeneous S-regular sequence and C is a complete intersection: C=S/(w1,…,wr) with Hilb⁡(C,t)=∏i(1−t2di)(1−t2)r=∏i(1+t2+⋯+t2(di−1)), so that dim⁡CC2N=1 and Cj=0 for j>2N.
  2. The multiplication pairing Ci×C2N−i→C2N≅C is nondegenerate for every i, and consequently soc⁡(C)={c∈C:C+c=0}=C2N is one dimensional.
  3. Equivalently, C is a graded Gorenstein algebra with one-dimensional socle in the top degree 2N.

Facts & Assumptions

Given: A finite Weyl reflection group W acting on the Cartan space h of rank r, the symmetric algebra S=S(h) with page grading deg⁡h=2, homogeneous basic invariants w1,…,wr of page degrees 2di, the ideal I=(w1,…,wr), the coinvariant algebra C=S/I, and a basis x1,…,xr of h∗ viewed as degree-two elements of S.

[F1]

Under AC, SW=C[w1,…,wr] with the wi algebraically independent and homogeneous of positive page degree 2di, I=S S+W, C is a finite-dimensional commutative graded C-algebra with C0=C generated in degree two, and ρ:S→C is the quotient map (Chevalley shephard todd for finite weyl groups, The coinvariant algebra of a finite Weyl group, The Axiom of Choice).

[F2]

Minimal homogeneous invariant generators f1,…,fm of I=S S+W have common zero set {0}, satisfy m=r, and form an S-regular sequence; every homogeneous lift of a homogeneous basis of C is a graded free SW-basis of S (Reflection basic invariants form a regular sequence).

[F3]

For a finite sequence x=(x1,…,xn) in a commutative ring and a module M, the Koszul complex K(x;M) has Hi=0 for i>n and Hn(K(x;M))={m∈M:xim=0 for all i}; if M is finite free and x is M-regular, then K(x;M) is a finite free resolution of M/(x)M. The differential preserves internal degree when the xi are given their degrees, the top exterior generator e1∧⋯∧en carrying the sum of the degrees of the xi (Koszul Complex Of A Sequence With Coefficients, Basic Koszul Homology, Koszul Complex Resolves A Regular Quotient).

[F4]

Under AC, Hilb⁡(S/Iord,t)=∏i(1+t+⋯+tdi−1) and ∏idi=∣W∣ in the classical normalization deg⁡h=1 (Weyl coinvariant hilbert series has order w dimension).

[F5]

In the polynomial ring S=C[x1,…,xr], the variables form a regular sequence with S/(x1,…,xr)=C, and S/(x1,…,xi)≅C[xi+1,…,xr] (Polynomial rings in finitely many commuting indeterminates by iteration).

[F6]

Under AC (hence Dependent Choice) the two constructions of Tor⁡nS(−,−) by resolving either variable are naturally isomorphic (Tor from a projective resolution of the left module, Tor from a projective resolution of the right module, The left and right projective constructions of Tor are naturally isomorphic).

Proof

technique · direct
1.1F1

The invariant ideal is generated by the basic invariants: I=S S+W=(w1,…,wr), because SW=C[w1,…,wr] and every element of S+W is a polynomial in the wi with zero constant term. Hence C=S/(w1,…,wr); since C is generated by the images of the degree-two elements, its augmentation ideal satisfies C+=(x1,…,xr)C.

1.2F1F2F3

The r basic invariants form an S-regular sequence: they are minimal homogeneous invariant generators of I (they generate I, and no wi lies in the ideal generated by the others, since applying the SW-linear Reynolds projection to a relation in S would give a relation in C[w1,…,wr], where no variable belongs to the ideal generated by the others), and by [F2] the minimal homogeneous invariant generators of I are r in number with common zero set {0} and form an S-regular sequence; consequently, by [F3], K(w;S) is a finite free resolution of C.

1.3F3F5

The variables x1,…,xr form an S-regular sequence with S/(x1,…,xr)=C=:k, by [F5]; consequently, by [F3], K(x;S) is a finite free resolution of k.

1.4F1F3algebra

Koszul differentials vanish after base change to k: tensoring K(w;S) with k multiplies by the images of the wi in k, which lie in the positive-degree part and hence act as zero; so Hr(K(w;S)⊗Sk)=Kr(w;S)⊗Sk, a one-dimensional space in internal degree ∑i2di.

2.1F3F6step 1.2step 1.4

First computation: by resolution 1.2, resolving the C variable, and the balance isomorphism [F6], Tor⁡rS(C,k)≅Hr(K(w;S)⊗Sk), which by step 1.4 is one dimensional and concentrated in internal degree ∑i2di.

2.2F3F6step 1.3

Second computation: by resolution 1.3, resolving the k variable, and [F6], Tor⁡rS(C,k)≅Hr(C⊗SK(x;S))=Hr(K(x;C)); by [F3] the top homology is {c∈C:xic=0 for all i}, placed in internal degree 2r above the degrees of its elements, since e1∧⋯∧er carries degree 2r.

2.3F3F4step 1.2algebra

Hilbert series: applying the Euler characteristic to the finite free resolution K(w;S) of C gives Hilb⁡(C,t)=∏i(1−t2di)⋅Hilb⁡(S,t)=∏i(1−t2di)(1−t2)r=∏i(1+t2+⋯+t2(di−1)), the last equality by cancelling one factor 1−t2 per invariant. Hence Hilb⁡(C,t) is a polynomial of degree 2N with leading coefficient 1, so dim⁡CC2N=1 and Cj=0 for j>2N; the classical formula [F4] gives the same series after substituting t2 for t.

3.1F6step 2.1step 2.2

Comparing steps 2.1 and 2.2 through the natural isomorphism [F6] identifies the top Koszul homology of step 2.2 with a one-dimensional space in internal degree ∑i2di; shifting back by the degree 2r of the top exterior generator, the space {c∈C:xic=0 for all i} is one dimensional and concentrated in internal degree ∑i2di−2r=2∑i(di−1)=2N.

4.1step 1.1step 2.3step 3.1

Since C+=(x1,…,xr)C by step 1.1, the space of step 3.1 is exactly the socle soc⁡(C)={c∈C:C+c=0}; it is one dimensional in degree 2N. The top graded piece C2N is one dimensional by step 2.3, and every element of C2N is annihilated by C+ because C has no degrees above 2N; hence 0≠C2N⊆soc⁡(C) and both are one dimensional in degree 2N, so soc⁡(C)=C2N.

5.1step 2.3step 4.1algebra∎

Nondegeneracy of the top pairing: let 0≠c∈Ci be homogeneous and consider the nonzero graded ideal cC of the finite-dimensional graded algebra C; let m be the largest degree with (cC)m≠0, so m≤2N by step 2.3. Choose 0≠y∈(cC)m; then C+y⊆(cC)>m=0, so y∈soc⁡(C)=C2N by step 4.1, forcing m=2N. Writing y=cb with b∈C2N−i gives a nonzero product cb, so the pairing Ci×C2N−i→C2N≅C has no nonzero left radical; by commutativity it has no nonzero right radical either, and finite-dimensionality of the two sides makes it a perfect pairing for every i. Hence C is a graded Gorenstein algebra with one-dimensional socle in top degree 2N.

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