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RemarkRemark: Literature-sourcedProof: Not applicablePipeline-generated
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  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
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Blowing up replaces the center by its projectivized normal directions

Remark

A blowup is not the deletion of the center. Let I be a quasi-coherent ideal sheaf of finite type on a scheme X with zero scheme Z=V(I), and let π ⁣:Bl⁡IX→X be the blowup of Blowup of a scheme along an ideal sheaf, with exceptional subscheme E=π−1(Z) (Exceptional subscheme of a blowup). Then:

Surjectivity is part of the same picture but carries a hypothesis. If the center is empty (I=OX) then π is an isomorphism; if I vanishes identically on an open set, then the blowup has empty fibres over that set, so no unconditional surjectivity holds. In the integral finite-type situations used on this page, a nonzero center ideal has a nonempty dense complement. The proper image of the blowup is closed and contains that complement, hence is all of X. Thus every fiber is nonempty, including the projectivized normal-cone fibers over the center.

Finally, strict transforms record how subvarieties approach the center: a closed subscheme W⊆X has strict transform (Strict transform of a closed subscheme) cut out on the standard affine charts by the saturation of the pullback of its ideal by a local equation of the center, so parts supported entirely in the exceptional locus are removed. A subscheme contained in the center has empty strict transform; a single blowup need not separate all remaining branches.

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