Alphabeta Math
TheoremStatement: Literature-sourcedProof: AI-generatedPipeline-generatedprecheck passaudited 2026-08-29
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Every automorphism of the disc is a rotated Blaschke factor

Statement

A holomorphic map f:DD is an automorphism of D if and only if there exist aD and θR such that

f(z)=eiθφa(z)=eiθaz1az(zD).

Facts & Assumptions

Given: A holomorphic self-map f:DD.

[F1]

The automorphism group Aut(D) consists of the biholomorphic self-maps of D (Conformal equivalence and the automorphism group of a domain).

[F2]

Every Blaschke factor is an automorphism of D (Blaschke factors are automorphisms of the disc).

[F3]

Equality in Schwarz's lemma characterizes rotations (Schwarz lemma with the equality cases).

Proof

technique · direct
1.1

Assume first that fAut(D), and let a=f1(0). By [F2], the map g:=fφa is an automorphism of D with g(0)=0.

F1F2givenconstruct
2.1

Applying [F3] to g and to its inverse g1 shows g(z)z and z=g1(g(z))g(z) for every zD, so g(z)=z throughout D. Hence [F3] forces g(z)=eiθz for some real θ.

F1F3step 1.1algebra
3.1

Therefore f(z)=g(φa(z))=eiθφa(z). Conversely, if f(z)=eiθφa(z), then the rotation zeiθz and the Blaschke factor φa are automorphisms, so [F2] and [F1] make f an automorphism.

F1F2step 2.1algebra

Depends on

Used by

Dependency tree · two levels

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Sources