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The negative-half bilinear form is symmetric, nondegenerate and integral

Statement

Let Uq−=⨁ν∈Q+Uq−[−ν] be the negative half of the Drinfeld-Jimbo algebra of a finite symmetrizable Cartan datum with aii=2 (The Drinfeld-Jimbo quantized enveloping algebra by generators and relations, Positive, negative and toral quantum subalgebras and their root gradings), with skew derivations ei′,ei′′ (Kashiwara's skew derivations ei′ and ei′′ on the negative half), and let ( , ) be a bilinear form on Uq−.

(i) Existence and symmetry. A bilinear form with (1,1)=1 and (FiP,Q)=(P,ei′(Q)) for all i,P,Q exists on Uq−; every normalized homogeneous form satisfying these conditions is symmetric; and by the uniqueness of The Lusztig-Kashiwara bilinear form on the negative half: the recursion there is exactly one such form. No separate right-adjunction formula for (P,QFi) is asserted: in the rank-one subalgebra a formula (P,QFi)=c (ei′′P,Q) with constant c is false, as the explicit values in (iv) show.

(ii) Orthogonality. (Uq−[−ν],Uq−[−μ])=0 whenever ν≠μ.

(iii) Nondegeneracy. For every 0≠x∈Uq− there is y∈Uq− with (x,y)≠0; equivalently, the restriction of the form to each finite-dimensional graded piece Uq−[−ν] is nondegenerate.

(iv) Integrality on the word lattice. Let A=Z[q,q−1] (The Laurent polynomial ring as the principal localisation of Z[t] at t) and let W⊆UA− be the A-span of the monomials Fi1⋯Fik (k≥0). Then W⊆UA− (because Fik=[k]i!Fi(k) and [k]i!∈A), and (W,W)⊆A. On the larger divided-power lattice UA− the form is not A-valued: in the rank-one subalgebra generated by a single Fi one has, for all a,b≥0, (Fi(a),Fi(b))=δabqi−a(a−1)/2[a]i!=δab1[a]qi2!, in particular (Fi(2),Fi(2))=1/(1+qi2)∉A; here [a]qi2!=∏m=1a(1+qi2+⋯+qi2(m−1)). Globally, with Aloc=A[s−1:s∈S], the localization of A inverting the multiplicative set S generated by {[r]i!:i∈I,r≥1} (equivalently inverting the Gaussian factorials [r]qi2!), one has (UA−,UA−)⊆Aloc: divided-power words are word vectors divided by finite products of these factorials. This is an exact denominator bound, not an A-integrality assertion on UA− in this normalization.

Facts & Assumptions

Given: The negative half with its grading, the derivations ei′,ei′′ and the integral form UA with W⊆UA−⊆Uq− (The Lusztig divided-power integral form UA), and the axioms (H), (N), (R) of The Lusztig-Kashiwara bilinear form on the negative half: the recursion.

[F1]

The generic Serre halves H+,H− over Q(q) have primitive generators ei,fi, braided tensor multiplication (u⊗v)(u′⊗v′)=q−⟨deg⁡u′,deg⁡v⟩uu′⊗vv′, and a nondegenerate pairing ⟨ , ⟩ zero on unequal opposite degrees, with ⟨ei,fj⟩=δij/(qi−qi−1), ⟨1,1⟩=1 and both Hopf adjunctions. Opposite finite-dimensional components are dual. This is Generic quantum Serre halves have classical PBW ranks and a nondegenerate Hopf pairing (ii), with its declared AC use. The actual negative half has the separate symmetric Serre presentation by Triangular decomposition of a quantized enveloping algebra (ii), so replacing its Fi by ei, respectively fi, gives algebra isomorphisms φ+:Uq−→H+ and φ−:Uq−→H−, with opposite root degrees. The symmetric color form is ⟨αi,αj⟩=diaij (Symmetrizable Cartan data for quantum groups).

[F2]

Axioms (H) and (N) together with (R) determine a form uniquely: peeling first letters writes every positive-height P as P=∑iFiPi and evaluates B(P,Q)=∑iB(Pi,ei′Q), reducing the height, with base B(1,Q)=ε(Q) (The Lusztig-Kashiwara bilinear form on the negative half: the recursion).

[F3]

ei′ is Q(q)-linear, and on words ei′(Fj1⋯Fjm)=∑t:jt=iqi−aij1−⋯−aijt−1Fj1⋯Fjt^⋯Fjm with coefficients in A; also ei′(Fi(n))=qi−(n−1)Fi(n−1) and ei′Fj=qi−aijFjei′+δij (Kashiwara's skew derivations ei′ and ei′′ on the negative half).

[F4]

Fi(n)=Fin/[n]i!, Fin=[n]i!Fi(n), and [m]i=qi−(m−1)[m]qi2 with [a]qi2!=∏m=1a(1+qi2+⋯+qi2(m−1)) (Quantum integers, factorials, Gaussian binomials and divided powers at qi).

[F5]

1+qi2∉A× in A=Z[q,q−1]: its value at q=1 is 2, and no Laurent polynomial of the form (1+qi2)−1 lies in A (an inverse in the domain Q[q,q−1] would force 1=(1+qi2)⋅Laurent). The Laurent polynomial ring as the principal localisation of Z[t] at t is used for the Laurent-ring arithmetic.

Verification

technique · construct the form by transporting and rescaling the generic braided pairing; derive its skew adjunction and symmetry on words, and recover uniqueness by first-letter peeling; and compute integrality by height induction on word vectors, with the rank-one recursion for the exact divided-power denominators
1.1F1algebra

Construction, homogeneity and nondegeneracy. For ν=∑iniαi put cν=∏i(qi−qi−1)ni≠0 and, for P,Q∈Uq−[−ν], define B(P,Q)=cν⟨φ+(P),φ−(Q)⟩ using [F1]. Set B to zero on unequal degrees and extend bilinearly over the algebraic direct sum. The isomorphisms ensure this is defined on the actual Serre quotient. The form is homogeneous and has B(1,1)=1; each component is nondegenerate because its pairing is dual and cν is nonzero. Thus (ii) and (iii) hold, including the global assertion by selecting a nonzero component of a vector with finite support. The rescaled pairing still satisfies both Hopf adjunctions: in each nonzero summand the two factor degrees add to ν, and cν1cν2=cν. Its generator values are now δij.

2.1step 1.1F1F2F3algebra

Adjunction, symmetry and uniqueness. In the braided coproduct of a word w=Fj1⋯Fjm, the component with first factor of degree −αi is ∑t:jt=iq−∑s<t⟨αjs,αi⟩fi⊗φ−(w∖t): the letter at position t crosses precisely the earlier letters assigned to the second factor. The rescaled Hopf adjunction of step 1.1 therefore gives B(FiP,w)=∑t:jt=iqi−∑s<taijsB(P,w∖t)=B(P,ei′w) by [F3]; unequal degrees give zero on both sides, so this proves (R) for all P,Q by linearity. Repeated deletion gives, for equal-length words u=Fi1⋯Fim and v=Fj1⋯Fjm, the formula B(u,v)=∑πq−∑a<b, π(a)>π(b)⟨αia,αib⟩, where π ranges over bijections with jπ(a)=ia; if their color degrees differ the value is zero. Indeed the first deletion chooses π(1), its crossing exponent records exactly the inversions involving that first letter, and induction accounts for the remaining inversions, with empty-word value 1. The map π↦π−1 preserves the exponent after interchanging the two words because the color form is symmetric, so B is symmetric. Finally [F2] identifies every normalized homogeneous form satisfying (R) with B. This proves (i), without attributing existence or symmetry to the Statement of the separation lemma.

3.1step 2.1F2F3F4algebra

Integrality on the word lattice. We show B(u,v)∈A for classes of words u,v by induction on the total height of u plus deg⁡v (in fact on the height of the first argument): if u=1, then B(1,v)=ε(v)∈{0,1}⊆A; if u=Fiw then B(u,v)=B(w,ei′v), and ei′v is an A-linear combination of classes of words of strictly smaller height by [F3], so the induction hypothesis applies. By bilinearity B(W,W)⊆A, and W⊆UA− because Fik=[k]i!Fi(k) with [k]i!∈A by [F4].

3.2step 1.1step 2.1F3F4F5algebra

The rank-one divided-power values. Fix i and assume I={i} for the computation, so that the rank-one subalgebra is the free algebra on Fi and ei′(Fim)=qi−(m−1)[m]iFim−1 by inducting on m from ei′Fim=qi−2Fiei′Fim−1+Fim−1. Dividing by [m]i! gives ei′(Fi(m))=qi−(m−1)Fi(m−1). Put bm:=B(Fi(m),Fi(m)). Using Fi(m)=[m]i−1FiFi(m−1) and (R), bm=[m]i−1B(Fi(m−1),ei′(Fi(m)))=qi−(m−1)[m]i−1bm−1 with b0=1, so bm=qi−m(m−1)/2/[m]i!. By [F4], [m]i!=qi−m(m−1)/2[m]qi2!, hence bm=1/[m]qi2!=∏j=1m(1+⋯+qi2(j−1))−1; for m≠n the two divided powers have different heights, so B(Fi(m),Fi(n))=0 by homogeneity. At m=2 this is 1/(1+qi2)∉A by [F5]. This proves the rank-one clause of (iv) and shows that the form is not A-valued on UA−.

4.1step 3.1step 3.2F1F3F4algebra∎

The right-adjunction failure and the global denominator bound. First, no constant c makes (P,QFi)=c(ei′′P,Q) hold on the rank-one subalgebra: (Fi,Fi)=B(Fi,Fi)=1 and (Fi,Fi⋅1)=1 force c=1 from (ei′′Fi,1)=(1,1)=1, but (Fi2,Fi2)=[2]i2b2=(qi+qi−1)2/(1+qi2)=1+qi−2 while (ei′′Fi2,Fi)=(1+qi2)(Fi,Fi)=1+qi2, which differs; this justifies the parenthetical in (i). Second, every element of UA− is an A-linear combination of divided-power words ∏iFi(ri) with coefficients in A (the divided powers generate UA− by definition), and each such word is its underlying ordinary word divided by the finite product ∏i[ri]i!; by bilinearity of B and B(W,W)⊆A from step 3.1, B(UA−,UA−)⊆Aloc=A[s−1:s∈S]. Since [r]i!=qi−r(r−1)/2[r]qi2! by [F4] and qi±1∈A×, inverting the [r]i! is the same as inverting the Gaussian factorials [r]qi2!; the bound is exact in rank one by step 3.2. This completes (iv).

Depends on

Used by

Cited to discharge well-definedness by The Lusztig-Kashiwara bilinear form on the negative half: the recursion.

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