Alphabeta Math
ExampleConstruction: AI-adaptedVerification: AI-adaptedprecheck pass
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Moving coordinates: the substituted Hamiltonian of a spring on a uniformly moving support, its conservation and the non-conservation of the mechanical energy

Physical scope

A worked check of the Hamiltonian description in a time-dependent chart: a one-label model with a spring whose equilibrium point is attached to a support moving uniformly at a prescribed velocity, described in the co-moving coordinate; the substituted Lagrangian has a velocity-linear term, the substituted Hamiltonian is conserved, it differs from the model's mechanical energy by the product of the support velocity and the momentum, and the mechanical energy changes at the rate of the explicit time dependence of the potential. All quantities are model values of the declared idealization; no measurement is reported.

Example

Declare the one-label model of the force branch of Adopted force model: force maps, the equation of motion, additive composition of force contributions and frame covariance with N=1, mass m>0, time window I0=R, configuration domain Q=R3 and potential U(t,x):=12k(x1−v0t−c)2 with constants k>0, v0∈R and c∈R, and no residual forces: the label is attached by a spring of stiffness k to a support whose position is the prescribed function v0t+c, so the force map is F=(−k(x1−v0t−c),0,0) and the mechanical Lagrangian is L=K−U with K(v)=12m∣v∣22 (Potential presentations of a force model, potential and mechanical energy, closed versus exact force fields, local potentials and equipotential level sets, The action functional of a force model with a potential presentation: the mechanical Lagrangian, its chart instance and its dimensions). Introduce the co-moving coordinates X(t,y):=(y1+v0t+c, y2, y3), a time-dependent coordinate map with Xq=I3, and the substituted Lagrangian L′(t,y,w):=L(t,X(t,y), Xt(t,y)+Xq(t,y)w). This L′ is a generic fibre-full time-dependent Lagrangian chart of The Legendre map of a time-dependent Lagrangian: regularity and hyperregularity; it need not be a K−U presentation in a static coordinate map. The model units are [k]=μτ−2 (newtons per metre), [v0]=ℓτ−1 (metres per second), [c]=[y0]=ℓ (metres), [q]=μℓτ−1 (momentum, kilograms metres per second), and [ω]=τ−1 (radians per second with dimensionless radians). Here y0 and q are initial co-moving position and first momentum, respectively. Then:

  1. L′(t,y,w)=12m(w1+v0)2+12m(w22+w32)−12ky12, its fibre derivative is p′=Lw′(t,y,w)=(m(w1+v0), mw2, mw3), and the coordinate change reproduces the model's equation: a C2 curve y satisfies the Euler-Lagrange equation of L′ exactly when x(t)=X(t,y(t)) satisfies mx¨1=−k(x1−v0t−c), mx¨2=mx¨3=0 (Time-dependent coordinate maps transform the potential-part equation into the substituted Euler-Lagrange equation).
  2. L′ is hyperregular on its chart with inverse branch w=(p1′/m−v0, p2′/m, p3′/m) and Hamiltonian H′(t,y,p′)=p1′22m−v0p1′+p2′22m+p3′22m+k2y12=(p1′−mv0)22m+k2y12+p2′2+p3′22m−mv022, so that on the first coordinate the momentum p1′ equals the inertial momentum p1=mx˙1 of The momentum of a potential presentation: the fibre derivative of the mechanical Lagrangian, the Cartesian momentum Mv and generalized momenta while the branch velocity is shifted, y˙1=p1′/m−v0.
  3. Hamilton's equations of H′ are y˙1=p1′/m−v0, p˙1′=−ky1, y˙i=pi′/m, p˙i′=0 for i=2,3; they imply my¨1=−ky1, equivalently mx¨1=−k(x1−v0t−c), so the co-moving description is equivalent to the model's motion and the induced curve x is a motion (The associated first-order system, motions, maximal motions and the Newtonian flow of a force model).
  4. along the solutions the Hamiltonian H′ is conserved — it has no explicit time dependence in the co-moving chart — while the model's mechanical energy E=K+U obeys, on the first axis, H′=E−v0p1′,E′(t)=−kv0y1(t). At any time when v0y1(t)≠0, the energy derivative is nonzero; in particular, the displayed solution has nonconstant E when v0y0≠0. With data y1(0)=y0, p1′(0)=q and ω:=k/m the explicit solution is y1(t)=y0cos⁡ωt+q−mv0mωsin⁡ωt,p1′(t)=−mωy0sin⁡ωt+(q−mv0)cos⁡ωt+mv0.

All quantities are model values of the declared idealization; the moving support is a prescribed external mechanism, and no measurement is reported.

Facts & Assumptions

Given: The one-label model with the moving-support spring potential, the co-moving coordinate map X, the substituted Lagrangian L′ with its momentum p′ and Hamiltonian H′, and the initial data y0,q of clause 4.

[F2]

Rheonomic coordinate covariance (Time-dependent coordinate maps transform the potential-part equation into the substituted Euler-Lagrange equation, The stationary-action criterion and the potential-part Euler-Lagrange equation): for a C3 coordinate map X(t,q) with invertible Xq and substituted Lagrangian L~(t,q,v)=L(t,X,Xt+Xqv), one has EL~(q)=XqTEL(x) along induced curves, so the substituted Euler-Lagrange equation is equivalent to the model's potential-part equation.

[F3]

Verification

technique · direct; substitute the co-moving coordinate map, identify the resulting chart as a mechanical chart Lagrangian with a linear velocity term, and evaluate its branch, Hamilton equations, conservation identity and explicit solution
1.1F1F2F5algebra

The map X(t,y)=(y1+v0t+c,y2,y3) is of class C3 with Xq=I3 invertible everywhere, so [F2] applies; computing the substitution gives L′(t,y,w)=12m(w1+v0)2+12m(w22+w32)−12ky12 and, by [F2], the substituted Euler-Lagrange equation is equivalent to mx¨1=−k(x1−v0t−c), mx¨2=mx¨3=0; its fibre derivative is p′=(m(w1+v0),mw2,mw3), which is clause 1.

2.1F3step 1.1algebra

The first-coordinate block of L′ has the form 12mw12+mv0w1−V(y1) with V=12ky12−12mv02, and the remaining blocks have the same form with G=m, A=0, V=0; by [F3] the chart is hyperregular with w1=p1′/m−v0, wi=pi′/m, and branch Hamiltonian H′=p1′2/(2m)−v0p1′+12ky12+(p2′2+p3′2)/(2m), which is clause 2 in its two displayed forms.

3.1F2F3F5step 1.1step 2.1algebra

Differentiating the first form of H′ in step 2.1 gives Hp1′′=p1′/m−v0, Hy1′=ky1 and, for i=2,3, Hpi′′=pi′/m, Hyi′=0; hence Hamilton's equations are y˙1=p1′/m−v0, p˙1′=−ky1 and y˙i=pi′/m, p˙i′=0 for i=2,3; differentiating the first and substituting the second gives my¨1=−ky1, and since x˙1=y˙1+v0=p1′/m and x1−v0t−c=y1, this is exactly the model's equation of step 1.1, so the induced curve is a motion.

4.1F4step 2.1step 3.1givenalgebra

Along a motion x one has E=K+U=12m∣x˙∣2+12ky12=∣p′∣2/(2m)+12ky12 and therefore H′=E−v0p1′; from [F4] applied to the present potential, ∂tU(t,x(t))=−kv0(x1(t)−v0t−c)=−kv0y1(t), and d≡0, so E′(t)=−kv0y1(t). Thus E′(t)≠0 whenever v0y1(t)≠0; for the initial data in clause 4, v0y0≠0 makes E′(0)=−kv0y0≠0 and hence E is not constant.

4.2F5step 3.1algebra

The displayed curves satisfy y1(0)=y0 and p1′(0)=q, and by [F5] their derivatives are y˙1=−y0ωsin⁡ωt+((q−mv0)/m)cos⁡ωt and p˙1′=−mω2y0cos⁡ωt−ω(q−mv0)sin⁡ωt=−ky1(t), using ω2=k/m; moreover y˙1=p1′/m−v0 and the other coordinates are free, so the displayed pair solves the Hamilton system of step 3.1 with the prescribed data.

5.1step 3.1step 4.1algebra

H′ has no explicit dependence on t in the co-moving chart, and along solutions of step 3.1 its total derivative is Hy1′y˙1+Hp1′′p˙1′=(ky1)(p1′/m−v0)+(p1′/m−v0)(−ky1)=0; the remaining momentum terms have derivatives (pi′/m)p˙i′=0 for i=2,3 by step 3.1; hence H′ is conserved while E′=−kv0y1 need not vanish.

6.1step 1.1step 2.1step 3.1step 4.1step 5.1step 4.2∎

Conclusion: clauses 1-4 are verified on the declared data; the co-moving chart is a time-dependent chart of the same model, its Hamiltonian is conserved and differs from the mechanical energy by v0p1′, and the displayed solution has nonconstant mechanical energy when v0y0≠0, exactly as the energy balance specifies.

Remarks

Depends on

Dependency tree · 2 levels

Sources