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Ricci, scalar and Einstein tensors of the FLRW metric in product charts

Statement

Let (I,Σ,γ,k,a) be an FLRW model datum with conversion constant c>0, with spacetime M=I×Σ and metric g (FLRW model data: warped product metric, cosmic time, comoving congruence, scale factor and Hubble parameter, The constant-curvature spatial model of a homogeneous cosmology), let ∇ be its metric-selected connection, and let Rabcd, Ric⁡ab, S and Gab be the curvature components, Ricci tensor, scalar curvature and Einstein tensor of ∇ (The Riemann curvature operator and the derived Ricci, scalar and Einstein tensors, Tensoriality of the curvature, its coordinate formula and its point-normal metric formula, Metric compatibility, torsion freedom and the metric-selected connection class). In a product chart (x0,x1,x2,x3) with x0=t, with a˙ the derivative of the scale factor and H=a˙/a:

(a) Ric⁡00=−3a¨a, Ric⁡0i=0, and Ric⁡ij=(aa¨+2a˙2c2+2k)γij for i,j∈{1,2,3};

(b) S=6(a¨ac2+H2c2+ka2);

(c) G00=3(a˙2+kc2)a2, G0i=0, and Gij=−(2aa¨+a˙2c2+k)γij for i,j∈{1,2,3}.

All displayed component functions are smooth on the chart domain; the identities are equalities of the components of the respective tensor fields in the product chart and hold at every point.

Facts & Assumptions

Given: An FLRW model datum with c>0, its spacetime, metric, connection ∇, curvature data and a product chart (x0,x1,x2,x3) with x0=t.

[L1]

In the product chart the Christoffel symbols are Γ000=Γ00i=Γi00=0, Γ0ij=aa˙γij/c2, Γi0j=Hδij and Γijk=(3)Γijk, where (3)Γ are the symbols of the spatial metric γ (Christoffel symbols of the FLRW metric in product charts).

[L2]

The curvature components are given by Rabcd=∂cΓadb−∂dΓacb+∑e(ΓaceΓedb−ΓadeΓecb), and R is a smooth (1,3)-tensor whose curvature data are independent of the chart used (Tensoriality of the curvature, its coordinate formula and its point-normal metric formula clause (b), The Riemann curvature operator and the derived Ricci, scalar and Einstein tensors, The algebraic symmetries of the curvature tensor and the symmetry of the Ricci and Einstein tensors).

[L3]

Ric⁡bd=∑a,cgacRabcd with Rabcd=∑egaeRebcd; equivalently, in every orthonormal frame Ric⁡bd=∑cRcbcd, which is the trace tr⁡(Z↦R(Z,∂d)∂b) of the curvature endomorphism (The Riemann curvature operator and the derived Ricci, scalar and Einstein tensors clause (c), Ricci curvature, Ricci curvature is symmetric and basis independent, The inverse metric, musical isomorphisms and index raising). Moreover S=∑a,bgabRic⁡ab and Gab=Ric⁡ab−12Sgab (The Riemann curvature operator and the derived Ricci, scalar and Einstein tensors clause (c)).

[L4]

The remaining components of the inverse metric in the product chart are g00=−c−2 and gij=a(t)−2γij, and ∑jγijγjl=δil (Christoffel symbols of the FLRW metric in product charts [L2], The inverse metric, musical isomorphisms and index raising).

[L5]

The spatial metric γ has constant sectional curvature k, so its three-dimensional Ricci tensor is Ric⁡(γ)ij=2kγij; in the component convention shared with [L2] this reads ∑l(3)Rlilj=2kγij, where (3)R are the curvature components of γ computed from the symbols (3)Γ (Constant-curvature three-manifolds: equivalence of constant sectional curvature, the tensor identity and the Ricci condition, Ricci curvature, Riemannian metric and riemannian manifold).

Proof

technique · direct substitution of the Christoffel symbols in the curvature formula, organized by the index families, followed by the traces
1.1L1L2L3L6algebra

(The Ric⁡00 component.) By [L3], Ric⁡00=∑cRc0c0. In the sum, the term c=0 is R0000=0 because every term of [L2] contains a symbol Γ⋅00 or Γ00⋅, all of which vanish by [L1]. For c=i the same formula gives Ri0i0=∂iΓi00−∂0Γii0+∑e(ΓiieΓe00−Γi0eΓei0)=0−H˙−∑eΓi0eΓei0, using Γi00=0 and Γii0=Hδii=H from [L1]; the remaining quadratic term is −∑eΓi0eΓei0=−∑m(Hδim)(Hδmi)=−H2, because the terms with e=0 contain the vanishing symbol Γ0i0. Summing over c=0,1,2,3 gives Ric⁡00=3(−H˙−H2)=−3a¨/a, where H˙=a¨/a−(a˙/a)2=a¨/a−H2 by [L6].

1.2L1L2L3L5algebra

(The spatial components.) By [L3], Ric⁡ij=∑cRcicj=R0i0j+∑kRkikj. For the term c=0, [L2] and [L1] give R0i0j=∂0Γ0ji−∂jΓ00i+∑e(Γ00eΓeji−Γ0jeΓe0i)=∂0(aa˙γij/c2)+0−∑m(aa˙γjm/c2)(Hδmi), since Γ00e=0 and Γ0je=0 for e=0; with ∂0(aa˙)=aa¨+a˙2 and aa˙H=a˙2 this is (aa¨+a˙2−a˙2)γij/c2=aa¨γij/c2. For the spatial terms, substituting [L1] into [L2] and summing over k separates the γ-symbols from the time-dependent symbols exactly as in the third family of Christoffel symbols of the FLRW metric in product charts: the terms with some index 0 contribute the total 3Haa˙γij/c2−Haa˙γij/c2=2a˙2γij/c2, and the remaining terms are ∑k(∂k(3)Γkji−∂j(3)Γkki+∑m((3)Γkkm(3)Γmji−(3)Γkjm(3)Γmki))=∑k(3)Rkikj=2kγij by [L5]. Adding the two contributions gives Ric⁡ij=(aa¨+2a˙2)γij/c2+2kγij, which is claim (a).

2.1L1L2L3algebra

(The mixed components vanish.) By [L3], Ric⁡0i=∑cRc0ci. The term c=0 vanishes as in step 1.1. For c=j, [L2] and [L1] give Rj0ji=∂jΓji0−∂iΓjj0+∑e(ΓjjeΓei0−ΓjieΓej0)=0−0+∑m((3)ΓjjmHδmi−(3)ΓjimHδmj), since the terms with e=0 contain Γ0i0=Γ0j0=0 and the spatial derivatives of the functions H(t)δji vanish; substituting δmi and δmj and summing over j gives H∑j((3)Γjji−(3)Γjij)=0 by the symmetry of the spatial symbols. Hence Ric⁡0i=0.

2.2L3L4L6step 1.1step 1.2algebra

(Scalar curvature.) By [L3] and [L4], S=g00Ric⁡00+gijRic⁡ij=−c−2(−3a¨/a)+a−2γij(aa¨+2a˙2c2γij+2kγij). Using γijγij=3 by [L4], S=3a¨/(ac2)+3(aa¨+2a˙2)/(a2c2)+6k/a2=6(a¨/(ac2)+H2/c2+k/a2), since aa¨/a2=a¨/a and a˙2/a2=H2 by [L6]. This is claim (b).

3.1L3L4step 1.1step 2.1step 1.2step 2.2algebra∎

(Einstein tensor and conclusion.) By [L3] and [L4], G00=Ric⁡00−12Sg00=−3a¨/a+12c2S=−3a¨/a+3a¨/a+3H2+3kc2/a2=3(a˙2+kc2)/a2 by step 2.2; G0i=Ric⁡0i−12Sg0i=0 by step 2.1; and Gij=Ric⁡ij−12Sgij=(aa¨+2a˙2c2+2k)γij−3(a¨ac2+H2c2+ka2)a2γij=−(2aa¨+a˙2c2+k)γij by steps 1.2 and 2.2. This is claim (c), and it completes the proof of all three claims.

Remarks

Depends on

Dependency tree · 2 levels

Sources