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Thermal frequency cutoffs may be removed under the envelope

Statement

Under the thermal-envelope hypotheses, let χm:(0,∞)→C be Borel, ∣χm∣≤1, and ∣χm(ω)∣2→1 almost everywhere. Write ft and W for the functions in the envelope lemma. Then ∫∣χm∣2ft→∫ft, uniformly for all real t, with error bounded by ∫(1−∣χm∣2)W→0. In particular the compact-shell choices χm=1[1/m,m] suffice. If the integrability hypothesis fails, this lemma asserts no unregulated correlation or distributional limit.

Facts & Assumptions

Given: The thermal-envelope hypotheses, including Countable Choice and its Borel measure conventions, and the cutoff functions in the Statement.

[F1]

The envelope supplies the measure on I=(0,∞), its Borel conventions and inherited Countable Choice hypothesis, the formulas for Nβ,ft,W, measurable W≥0 with ∫W=M<∞, and absolutely integrable ft for every real t. An absolute thermal envelope controls radial correlations

[F2]

Dominated convergence applies to measurable complex functions under one nonnegative integrable majorant. Dominated convergence

[F3]

The modulus of an integral is bounded by the integral of its modulus for an integrable complex function. The modulus of an integral is bounded by the integral of the modulus

[F4]

The integral is complex-linear on integrable functions. The Lebesgue integral is linear on L¹(μ)

[F5]

The Borel sigma-algebra is generated by open sets; a measurable map has measurable inverse images of all measurable codomain sets. The Borel sigma-algebra of a topological space A measurable function between measurable spaces

[F6]

The real indicator of a measurable set is measurable. An indicator function is measurable exactly when its set is measurable

[F7]

Continuous maps have Borel preimages, measurable maps compose, and maps into Rn are measurable exactly when all real coordinates are measurable. A continuous map has Borel preimages of Borel sets Composition with a Borel measurable outer map preserves measurability A map into ℝⁿ is measurable exactly when its coordinates are measurable

[F9]

The nonnegative integral is monotone, and a measurable real or complex function with finite integral of its modulus is integrable. Monotonicity and nonnegative homogeneity of the nonnegative integral Integrable real and complex functions, and their integrals

[F10]

The real exponential is strictly increasing, and ∣eix∣=1 for real x. The exponential function is strictly increasing exp(x+iy)=eˣ(cos y+i sin y), |exp(x+iy)|=eˣ, and e^iπ+1=0

Proof

Goal: Prove the uniform cutoff-error estimate, its convergence to zero, and applicability of the compact-shell indicators.

1.1F1F5F7F8F11algebra

Put qm=∣χm∣2, hm=(1−qm)W, gm,t=qmft, and rm,t=(qm−1)ft. The real and imaginary parts of χm and ft are Borel by [F1], [F5] and [F7]. For χm=am+ibm, the polynomial am2+bm2 gives Borel qm: the coordinate tuple is measurable, the polynomial is continuous by [F8], and composition is measurable by [F7]. The same argument applied to the tuples of real coordinates of qm,ft,W gives Borel hm and both real coordinates of gm,t,rm,t; the coordinate criterion then gives their complex measurability. Modulus is continuous because [F11] gives ∣∣z∣−∣w∣∣≤∣z−w∣, so their moduli are also Borel by [F7]. All these functions are finite-valued.

2.1F1F9F10F11step 1.1algebra

Since βω>0, [F10] gives eβω>e0=1 and hence Nβ(ω)>0. The formula in [F1] and the unit modulus of both phases give ∣ft∣≤∣κ∣2ω2[Nβ+(Nβ+1)]=W by [F11]. Since 0≤qm≤1, we obtain ∣gm,t∣≤W and ∣rm,t∣≤hm≤W. Step 1.1 supplies measurability, so monotonicity in [F9] gives ∫∣gm,t∣≤M, ∫∣rm,t∣≤M, and ∫hm≤M. Thus these cutoff products and error densities are integrable by [F9]; ft is integrable by [F1].

3.1F3F4F9step 2.1

By linearity on the integrable functions just established and by the integral triangle inequality, ∣∫qmft−∫ft∣=∣∫rm,t∣≤∫∣rm,t∣≤∫hm. The last comparison uses [F9]. This bound holds for every real t with the same right-hand side.

4.1F1F2step 1.1step 2.1step 3.1

The hypothesis qm→1 almost everywhere and finiteness of W give hm→0 almost everywhere. The functions hm and the zero limit are measurable, and 0≤hm≤W with ∫W=M<∞. Hence [F2] yields ∫hm→0. Together with step 3.1, this is uniform convergence on the entire real time axis with the asserted error bound.

5.1F1F5F6F7step 4.1∎

For every positive integer m, the interval [1/m,m] is closed in I: its complement is the union of two relatively open intervals. It is therefore Borel by [F5]. Its real indicator is measurable by [F6], and adjoining its identically zero imaginary coordinate makes it Borel into C≃R2 by [F7]. It is bounded by one, and for each ω>0 every sufficiently large integer m satisfies 1/m≤ω≤m; thus its squared modulus converges pointwise to one. These shell cutoffs satisfy all hypotheses of the preceding steps. If W is nonintegrable, the domination hypothesis used here fails and the lemma makes no claim about unregulated or distributional limits.

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