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4 results · all verified · 3 also independently AI-judged
Every result on this page is machine-checked by a proof checker and read in full and owner-audited; the judge is an additional, independent cross-model AI review of the proofs. The 1 not AI-judged were verified by owner audit (typically over a confirmed judge false positive), not failures.

Iterative Restriction and Comb-Extraction Lemmas — Examples

1 · Prerequisites

2 · Summary

These examples keep the Section 2 lemmas concrete. They show leaf-reducibility for P5, unpack the nearly covered sparse-pair inequalities numerically, run a sample iteration for the multiplicative sparsity-drop lemma, and spell out the finite adjacency pattern of the comb outcome together with its external complete vertex.

3 · Logical flowchart

4 · Definitions, theorems and proofs

None yet.

5 · Examples, counterexamples and false statements

ExampleConstruction: Literature-sourcedVerification: AI-generatedprecheck passjudge pass (gpt-5.6-terra)audited 2026-09-01Open item page →

The five-vertex path is leaf-reducible

Example

The singleton family {P5} is leaf-reducible.

Facts & Assumptions

Given: The path graph P5.

[L1]

A family is leaf-reducible if deleting one leaf from one member leaves a modified family with the Erdős-Hajnal property (Leaf-reducible finite graph families).

[L2]

Every P4-free graph has a clique or stable set of size at least the square root of its order (Every P4-free graph has a clique or stable set of size at least the square root of its order).

[L3]

A graph has the Erdős-Hajnal property when its forbidden induced-subgraph class has some positive exponent (The Erdős–Hajnal property and an Erdős–Hajnal constant for a hereditary graph class).

Verification

technique · direct
1.1

An endpoint of P5 is a leaf, and deleting it leaves the four-vertex path P4.

givenL1
2.1

By [L2], the class of P4-free graphs has the positive exponent 1/2, so [L3] says that P4 has the Erdős-Hajnal property. Therefore the modified singleton family {P4} satisfies the condition in [L1].

step 1.1L2L3
3.1

Hence the singleton family {P5} is leaf-reducible.

step 2.1L1
ExampleConstruction: AI-adaptedVerification: AI-generatedprecheck passjudge pass (gpt-5.6-terra)audited 2026-09-01Open item page →

A nearly covered sparse pair at small parameters

Example

For y=28 and x=29, suppose a graph G of order 240 satisfies the sparse-graph, non-2y4-sparsity, and no-large-sparse-pair hypotheses of the nearly covered sparse-pair lemma. Its conclusion asks for a set B of size at least 28 and a set A of size at least (1328)240 such that A is 216-sparse to B and every vertex of B has at least 218A neighbours in A.

Facts & Assumptions

Given: The parameters y=28, x=29, a graph G with V(G)=240, and all hypotheses of the cited lemma.

[L1]

Under those hypotheses, the lemma produces disjoint sets A,B with By4V(G), A(13y)V(G), A y2-sparse to B, and every vertex of B having at least x2A neighbours in A (A sparse graph without a large sparse pair has a large nearly covered sparse pair).

Verification

technique · arithmetic unpacking
1.1

Substituting y=28 and V(G)=240 into [L1] gives y4V(G)=232240=28 and (13y)V(G)=(1328)240.

L1algebra
2.1

The same substitution gives y2=216 and x2=218, so the sparsity and neighbourhood conclusions in [L1] become exactly the numerical conditions stated above.

step 1.1L1algebra
ExampleConstruction: AI-adaptedVerification: AI-generatedprecheck passjudge pass (gpt-5.6-terra)audited 2026-09-01Open item page →

A numeric run of the multiplicative iteration in Lemma 2.9

Example

Take c=24,x=28,b1=2,b2=3,b3=3. Then b1b2=6=b2+b3, so the iteration lemma predicts an x-sparse induced subgraph of size at least x6V(G)=248V(G).

Facts & Assumptions

Given: The numerical parameters displayed above.

[L1]

Under the lemma's hypotheses, the output size is at least xb1b2V(G) (Iterated sparse restriction reaches the target sparsity threshold).

Verification

technique · arithmetic unpacking
1.1

The equality b1b2=23=6 and b2+b3=3+3=6 shows that the required inequality b1b2b2+b3 is tight in this example.

givenalgebra
2.1

Applying [L1] gives a final induced subgraph of size at least xb1b2V(G)=(28)6V(G)=248V(G). This makes the multiplicative exponent bookkeeping explicit in one concrete case.

step 1.1L1algebra
ExampleConstruction: AI-adaptedVerification: AI-generatedprecheck passaudited 2026-09-01Open item page →

A four-tooth comb with an external complete vertex

Example

Let a1,a2,a3,a4,v be five vertices and let Bi={bi} for i=1,2,3,4. If the only edges among these nine vertices are aibi for 1i4 and vbi for 1i4, then ((ai,Bi):i[4]) is a four-tooth comb and the outside vertex v is complete to the tooth blocks and anticomplete to the teeth.

Facts & Assumptions

Given: The nine labelled vertices above with exactly the displayed edges.

[L1]

A comb is given by distinct teeth ai, disjoint blocks Bi, each tooth complete to its own block and anticomplete to the other blocks (Combs in a graph).

Verification

technique · direct finite check
1.1

For each i[4], the tooth ai is adjacent to the unique vertex of its own block Bi={bi} and to no vertex of the other three blocks. Therefore ((ai,Bi):i[4]) satisfies [L1].

L1given
2.1

By construction the vertex v is adjacent to every bi and to none of the teeth ai. So v has exactly the extra adjacency pattern singled out in the comb outcome of the lemma.

step 1.1given

Sources