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DefinitionDefinition: Literature-sourcedProof: AI-adaptedPipeline-generatedjudge pass (gpt-6.1-sol)audited 2026-10-08
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Left-invariant means on L∞ of a locally compact group

Definition

Let G be a locally compact Hausdorff group with fixed left Haar measure μ. Write L∞(G):=L∞(G,μ;C) for the complex a.e.-class space of Complex L∞ space of a locally compact group. For g∈G define the left translate by Lgf(x):=f(g−1x). It is well defined on classes and isometric, and Lg1Lg2=Lg1g2.

For a bounded complex-linear functional, write ∥m∥:=sup⁡{∣m(f)∣:∥f∥∞≤1} for its operator norm.

A mean on L∞(G) is a complex-linear functional m:L∞(G)→C such that m(f)≥0 whenever f≥0 and m(1G)=1, where 1G is the class of the constant-one function. It is left invariant if m(Lgf)=m(f) for every g∈G and f∈L∞(G). Every mean has operator norm one and satisfies ∣m(f)∣≤m(∣f∣)≤∥f∥∞. Equivalently, a mean is a positive complex-linear functional of norm one.

Facts & Assumptions

Given: A locally compact Hausdorff group G with fixed left Haar measure μ and the complex normed space L∞(G).

[A1]

The left Haar measure is a nonzero Borel measure and satisfies μ(gE)=μ(E) for every Borel set E⊆G and g∈G (Left Haar integral and left Haar measure).

[F1]

The elements of L∞(G) are complex measurable functions modulo almost-everywhere equality; its operations are well defined, its norm is the essential supremum, and it is a complex normed vector space (Complex L∞ space of a locally compact group).

[F2]

Left translation x↦g−1x is a homeomorphism of G; a continuous map has Borel preimages of Borel sets (Topological group: multiplication and inversion are continuous, Group and abelian group, A continuous map has Borel preimages of Borel sets, The Borel sigma-algebra of a topological space).

[F3]

Complex conjugation, real and imaginary parts, and the modulus have their coordinate definitions and conjugation/multiplicativity laws, including zz‾=∣z∣2, ∣zw∣=∣z∣∣w∣, and ∣z‾∣=∣z∣ (Real and imaginary parts, complex conjugation, and modulus, Conjugation is an involutive real-field automorphism, zz‾=∣z∣2, and modulus is definite, multiplicative, and subadditive).

[F4]

For z=a+bi, ∣Re⁡z∣=∣a∣≤a2+b2=∣z∣; the inequality follows because b2≥0 and squaring is monotone on the nonnegative reals (Basic properties of the absolute value, Squaring is monotone on the nonnegatives, Squares of nonzero elements are positive).

Proof

technique · direct
1.1A1F1F2constructalgebra

For g∈G, the composition x↦f(g−1x) is Borel measurable by [F2]. If f=f′ outside a Borel null set N, then Lgf=Lgf′ outside gN, which is null by [A1]; thus Lg is well defined on a.e. classes. For each t>0, {x:∣Lgf(x)∣>t}=g{y:∣f(y)∣>t}, so [A1] preserves every superlevel-set measure and hence the essential-supremum norm. Direct calculation gives Le=I and Lg1Lg2=Lg1g2.

1.2F1F3F4givenalgebra

Let m be a positive complex-linear functional on L∞(G). If u is real-valued, write u=u+−u− with u+=(u+∣u∣)/2 and u−=(−u+∣u∣)/2, so u+,u−≥0 and both remain in L∞(G) by [F1, F3]. Positivity makes m(u+) and m(u−) real, so m(u) is real. Thus, writing f=Re⁡f+iIm⁡f, one has m(f‾)=m(f)‾. If m(f)≠0, set α:=m(f)‾/∣m(f)∣. By [F3], ∣α∣=1 and m(Re⁡(αf))=Re⁡(αm(f))=∣m(f)∣; since Re⁡(αf)≤∣αf∣=∣f∣ by [F3, F4], positivity gives ∣m(f)∣≤m(∣f∣). This inequality is immediate as well when m(f)=0.

2.1A1F1step 1.2givenalgebra∎

The constant-one class has norm one: μ(G)>0 by nonzeroness in [A1], so its superlevel set is G for 0<t<1 and empty for t≥1. For every ϵ>0, the essential-supremum definition [F1] gives ∣f∣≤(∥f∥∞+ϵ)1G almost everywhere. If m is positive, then m(1G)≥0 and m(∣f∣)≤(∥f∥∞+ϵ)m(1G); letting ϵ decrease to zero and using step 1.2 yields ∣m(f)∣≤∥f∥∞m(1G), so m is bounded. Taking the supremum on the unit ball and testing at 1G shows ∥m∥=m(1G). Consequently positivity and m(1G)=1 imply ∥m∥=1, and positivity with ∥m∥=1 implies m(1G)=1. For a mean this also gives ∣m(f)∣≤m(∣f∣)≤∥f∥∞.

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