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A transitive Borel G-space with a quasi-invariant measure class is ergodic

Statement

Assume AC. Let G be a second-countable locally compact Hausdorff topological group, H≤G a closed subgroup, and μ a nonzero quasi-invariant Radon measure on G/H. If E⊆G/H is Borel with μ(E △ gE)=0 for every g∈G, then μ(E)=0 or μ((G/H)∖E)=0. Equivalently, any transitive system of imprimitivity on G/H whose measure class is the quasi-invariant class is ergodic.

Facts & Assumptions

Given: AC, the group G, closed subgroup H, the quotient q:G→G/H, a nonzero quasi-invariant Radon measure μ on G/H, and a Borel E⊆G/H with μ(E△gE)=0 for all g.

[F1]

q is continuous and open, G/H is a standard Borel G-space with Borel action, q−1(gE)=g q−1(E) for the left action, and a Borel set F⊆G/H is μ-null if and only if q−1(F) is Haar null (Compact lifts and averaging onto C_c(G/H), Second-countable locally compact Hausdorff spaces are Polish, and homogeneous quotients are standard Borel, Haar null classes and Borel descent on a homogeneous space, Left group actions, transitive actions, and faithful actions).

[F3]

Tonelli applies to nonnegative product-measurable functions on sigma-finite measure spaces (Tonelli's theorem for nonnegative measurable functions on a sigma-finite product). Right translation by t scales left Haar measure by a positive scalar, so it preserves Haar-null Borel sets; this holds at the Borel-measure level, not only for Cc integrals (Modular function of a locally compact group, Borel-level form). Left Haar measure on G is sigma-finite because G is sigma-compact by [F1].

[F4]

For a transitive system of imprimitivity on G/H, invariance of a spectral projection P(B) under the representation means P(gB)=P(B) for all g, and P is strongly countably additive, so P(B△gB)=0 whenever P(gB)=P(B) (Systems of imprimitivity for a Borel G-space, Scalar and complex measures from a pvm).

Proof

technique · direct

Given: AC, the data and the invariant Borel set E of the statement.

1.1F1F2

Lift the indicator: f(t):=1E(q(t)). For every g, applying the hypothesis to g−1 gives μ(E△g−1E)=0, so by [F1] the set q−1(E△g−1E) is Haar null. Since q(gt)=gq(t), one has f(gt)=1E(gq(t))=1g−1E(q(t)), which equals f(t)=1E(q(t)) at every t outside q−1(E△g−1E); hence f∘Lg=f Haar-a.e. for every g∈G.

2.1F1F3step 1.1

The function (g,t)↦∣f(gt)−f(t)∣ is Borel and hence product-measurable, since multiplication is continuous and the Borel sigma-algebra of a product of second-countable spaces is the product Borel sigma-algebra. By step 1.1 each integral in t is zero. Tonelli therefore gives ∫G∫G∣f(gt)−f(t)∣ dg dt=0, so for Haar-almost every t, f(gt)=f(t) for Haar-almost every g.

3.1F3step 2.1

Choose t0 with the preceding property; the conull set is nonempty since Haar measure is nonzero. The exceptional set of g is Haar null, and its right translate by t0 remains null by [F3]. Substituting u=gt0 therefore gives f(u)=f(t0) for Haar-almost every u. Since f(t0)∈{0,1}, f=1q−1(E) is Haar-a.e. zero or Haar-a.e. one.

4.1F1step 3.1

By the null-class equivalence of [F1], f=0 Haar-a.e. gives μ(E)=0 and f=1 Haar-a.e. gives μ((G/H)∖E)=0. This proves the first assertion.

5.1F4step 4.1F5∎

Equivalence with ergodicity of transitive systems: let (U,P) be a transitive system on G/H whose null class (the class of P-null Borel sets) is the quasi-invariant class, and let P(B) be invariant under U. Then P(gB)=P(B) for all g, so P(B△gB)=0 by [F4] and hence B△gB is null for every measure in the quasi-invariant class; applying [step 4.1] to a representative μ gives μ(B)=0 or μ(Bc)=0, and translating back gives P(B)=0 or P(B)=I. Thus the system is ergodic.

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