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LemmaStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedaudited 2026-10-02
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Fibre degree of the finite locally free map to the projective line

Statement

Assume the Axiom of Choice (The Axiom of Choice). Let k be a field, let C be a normal proper curve over k (Degree divisor proper curve) with function field K=k(C), let f∈K× be transcendental over k, and let φf:C→Pk1 be the finite locally free morphism of degree d=[K:k(f)] with φf#(t)=f constructed in Proper normal curve rational function map. Here Pk1=U0∪U1 with U0=Spec⁡k[t] and U1=Spec⁡k[u], u=t−1, is the standard cover (Relative projective space from standard charts).

  1. Zero fibre. The fibre over the origin satisfies ∑x∈C: φf(x)=0ord⁡x(f) [κ(x):k]=d.
  2. Pole fibre. The fibre over the point at infinity satisfies ∑x∈C: φf(x)=∞(−ord⁡x(f)) [κ(x):k]=d.

Both sums are finite, every summand is a positive integer, and ord⁡x is the order at x of Order codimension one rational function.

Facts & Assumptions

Given: A field k, a normal proper curve C over k with generic point η and function field K=OC,η, the Axiom of Choice, an element f∈K× transcendental over k, and the finite locally free morphism φf:C→Pk1 of degree d=[K:k(f)] with φf#(t)=f on U0=Spec⁡k[t] and φf#(u)=f−1 on U1=Spec⁡k[u] (Proper normal curve rational function map).

[F1]

φf is finite, and for each standard affine chart V of Pk1 the preimage φf−1(V) is affine with coordinate ring BV; for V=U0 the ring B0 is a free k[t]-module of rank d with k[t]→B0, t↦f, and for V=U1 the ring B1 is a free k[u]-module of rank d with u↦f−1 (Proper normal curve rational function map, Finite morphisms of schemes).

[F2]

Pk1 is covered by U0=Spec⁡k[t] and U1=Spec⁡k[u] glued along tu=1; the origin 0 is the closed point t=0 of U0 with residue field k, the point at infinity ∞ is the closed point u=0 of U1, also with residue field k, and Pk1 is separated over k (Relative projective space from standard charts).

[F3]

C is an integral, proper, one-dimensional k-scheme; it is Noetherian, so its underlying space is Noetherian, and every open subset of C is quasi-compact. For a closed point x the residue field κ(x) is a finite extension of k (Degree divisor proper curve, Every algebra of finite type over a Noetherian ring is a Noetherian ring).

[F4]

Let x be a closed point of C. Then OC,x is a discrete valuation ring with fraction field K, and the normalized valuation of f∈K× is ord⁡x(f); a uniformiser of OC,x is denoted πx (Height-one localizations of normal Noetherian domains are DVRs, Order codimension one rational function).

[F5]

If V is a discrete valuation ring with uniformiser π and y=uπn with u∈V× and n≥0, then V/(y) has length n as a V-module (Length and valuation in a DVR).

[F6]

For φf:X→S, a point x∈X, s=φf(x) and the fibre Xs, there is a canonical isomorphism OXs,x≅OX,x/msOX,x (Stalks of the scheme-theoretic fibre).

[F7]

For a ring map A→B and a prime p⊆A the fibre of Spec⁡B→Spec⁡A over p is Spec⁡(B⊗Aκ(p)); moreover the points of the fibre correspond exactly to the points of Spec⁡B contracting to p, with unchanged residue fields (Coordinate ring of an affine fibre, Points and topology of a fibre).

[F8]

For an ideal I⊆R and an R-module M there is a natural isomorphism M⊗R(R/I)≅M/IM; tensor products commute with direct sums; and evaluation of polynomials at 0 identifies k[t]/(t)≅k (M⊗RR/I≅M/IM naturally, Tensor products commute with arbitrary direct sums, First isomorphism theorem for rings: R/ker⁡f≅im⁡f).

[F9]

A finite-dimensional k-algebra is Artinian: every descending chain of ideals stabilizes because their finite k-dimensions cannot keep decreasing. Under AC an Artinian ring R is canonically the product of its localizations at its finitely many maximal ideals (An Artinian ring is canonically the finite product of its localizations at its maximal ideals). For a finite-dimensional k-algebra this is a k-algebra isomorphism, so dim⁡kR=∑mdim⁡kRm. For a local finite-dimensional k-algebra S with residue field λ, a composition series with r factors isomorphic to λ gives dim⁡kS=r[λ:k], by additivity of k-dimension in the filtration (Composition series and length of a module). This does not require a λ-vector-space structure on S.

[F10]

The base change of a finite morphism is finite; a finite morphism is affine, so the preimage of every affine open is affine (Finite morphisms of schemes).

Proof

1.1F1F2F6F7F8F10

The fibre C0:=C×Pk1Spec⁡k over 0 is canonically Spec⁡(B0/tB0), and dim⁡kΓ(C0,OC0)=d. Since 0∈U0 and U0 is open, the structure morphism Spec⁡k→Pk1 with image 0 factors through U0, so C0≅φf−1(U0)×U0Spec⁡k. By [F10] and [F1] the scheme φf−1(U0)=Spec⁡B0 is affine and Spec⁡B0→U0=Spec⁡k[t] is affine, so [F7] identifies C0 with Spec⁡(B0⊗k[t]k), which is Spec⁡(B0/tB0) by [F8]. Since B0 is a free k[t]-module of rank d, [F8] gives B0/tB0≅(k[t]/(t))d≅kd as k-vector spaces, so the coordinate ring has k-dimension d. A base change of a finite morphism is finite, so C0 is finite over Spec⁡k and has finitely many points.

1.2F2F3F4F71.1

The underlying set of C0 is exactly the set of closed points x of C with ord⁡x(f)>0. By [F7] the points of C0 are the points x of C with φf(x)=0; since C0 is finite over k by 1.1, its points are closed in C0 and are closed points of the one-dimensional k-scheme C (the generic point η maps to the generic point of Pk1 because φf is nonconstant and C is integral, so η∉C0). A point x maps to 0 exactly when x lies in φf−1(U0), so that f is regular at x, and the image of f in κ(x) is zero; for the discrete valuation ring OC,x this is exactly the condition ord⁡x(f)>0.

1.3F3F4F5F6F91.2

For every x∈C0 one has OC0,x≅OC,x/(f) and dim⁡kOC0,x=ord⁡x(f) [κ(x):k]. By 1.2 the point x is a closed point with n:=ord⁡x(f)>0 and f=uπxn with u a unit of the discrete valuation ring OC,x. By [F6] applied to φf and the point 0∈Pk1, OC0,x≅OC,x/m0OC,x; since φf#(t)=f, the ideal m0OC,x is (f), so OC0,x≅OC,x/(f). By [F5] this is a module of length n over OC,x, with a composition series whose n factors are isomorphic to κ(x); each factor has k-dimension [κ(x):k] by [F3], and dimensions add along this filtration of k-vector spaces by [F9]. Hence dim⁡kOC0,x=n [κ(x):k].

1.4F91.11.21.3

The identity ∑x∈C0ord⁡x(f)[κ(x):k]=dim⁡kΓ(C0,OC0)=d holds. By 1.1 the ring Γ(C0,OC0)=B0/tB0 is a finite-dimensional k-algebra, hence Artinian, and its maximal ideals are the finitely many points x∈C0 with local rings OC0,x. By [F9] it is the product of those local rings, so its k-dimension is the sum of the k-dimensions computed in 1.3, namely ∑x∈C0ord⁡x(f)[κ(x):k]; by 1.1 this equals d. This is the zero-fibre identity.

1.5F1F2F4F5F6F7F8F9

Pole fibre. The fibre C∞:=C×Pk1Spec⁡k over the point at infinity is Spec⁡(B1/uB1), dim⁡kΓ(C∞,OC∞)=d, its points are exactly the closed points x with ord⁡x(f)<0, and dim⁡kOC∞,x=(−ord⁡x(f))[κ(x):k] for such x. The point ∞ lies in U1=Spec⁡k[u] and has residue field k, so the argument of steps 1.1 and 1.2 applies verbatim to the chart U1 and the coordinate u, whose pullback is f−1: the fibre is Spec⁡(B1⊗k[u]k)=Spec⁡(B1/uB1), and B1/uB1≅kd because B1 is free of rank d over k[u]. A point x of C maps to ∞ exactly when x∈φf−1(U1) and f−1∈mx, i.e. ord⁡x(f)<0; since f−1=uπx−n with −n=ord⁡x(f−1)>0, [F5] gives length −n and step 1.3 gives dim⁡kOC∞,x=(−n)[κ(x):k]. The Artinian product argument of step 1.4 now yields ∑x∈C∞(−ord⁡x(f))[κ(x):k]=dim⁡kΓ(C∞,OC∞)=d.

2.1F1F21.41.5∎

Both displayed identities hold: for every normal proper curve C/k and every f∈K× transcendental over k, the zero and pole fibres of the finite locally free morphism φf have degree d=[K:k(f)], computed respectively as ∑ord⁡x(f)[κ(x):k] and ∑(−ord⁡x(f))[κ(x):k]. The Axiom of Choice is used exactly as declared, through the construction input [F1] and the Artinian decomposition input [F9]; no further choice is made.

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