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Reduced degree into the 0-sphere is homotopy invariant and multiplicative
Statement
Let be a balanced oriented finite -manifold, so that every map has a reduced degree, and let be a map (The reduced degree of a map into the 0-sphere).
(i) If is continuous and , then for every ; in particular .
(ii) If is any map and denotes its reduced degree as a self-map of , then .
Facts & Assumptions
Given: A balanced oriented finite -manifold with and a map .
is oriented by the boundary orientation of : the point has sign and has sign . A reduced degree is defined only for a balanced source: , and then for a map . For itself this reads (The reduced degree of a map into the 0-sphere).
carries the subspace topology (Euclidean spheres and closed balls as subspaces of , Subspace topology: the traces of the open sets, its closed sets and its bases, the continuity of the inclusion, and the characteristic property of a map into a subspace). The interval is order-convex, hence connected, and a product of connected spaces is connected (A subset of is connected if and only if it is order-convex, that is, an interval, A product of connected spaces is connected in the product topology, and that argument is a theorem of ZF; for an infinite index set it is the assertion that the product of nonempty spaces is nonempty that uses the Axiom of Choice); in particular every is connected.
In the two singletons are open for the subspace topology: and (Euclidean spheres and closed balls as subspaces of , Subspace topology: the traces of the open sets, its closed sets and its bases, the continuity of the inclusion, and the characteristic property of a map into a subspace). A continuous map from a connected space into is therefore constant: the preimages of the two disjoint open singletons would otherwise separate the domain.
Proof
Proof technique: direct; split the composition law by the three possible reduced degrees of the self-map .
The product is the disjoint union of the connected subsets , one for each ; a continuous map from a connected space into is constant, so is constant on each , hence for all and ; equal maps have equal reduced degree, which proves (i).
Suppose is not constant. A map is determined by the pair , so a nonconstant sends and to different values; hence is either the identity, with and for both , or the antipodal map , with , so that for all ; then and, by linearity of the defining signed count, , while by [F1], the identity and the antipodal map having reduced degrees and ; thus .
If is constant with value , then is the constant map and by balance, while by [F1]; hence again , which completes (ii).
Depends on
- The reduced degree of a map into the 0-sphere
- Euclidean spheres and closed balls as subspaces of $\mathbb{R}^n$
- Subspace topology: the traces of the open sets, its closed sets and its bases, the continuity of the inclusion, and the characteristic property of a map into a subspace
- A subset of $\mathbb{R}$ is connected if and only if it is order-convex, that is, an interval
- A product of connected spaces is connected in the product topology, and that argument is a theorem of ZF; for an infinite index set it is the assertion that the product of nonempty spaces is nonempty that uses the Axiom of Choice
Used by
- Isolated fixed point and local fixed point index Definition
- Negation scales the local index by (-1)ⁿ Lemma
- The index sum of an outward field is the Gauss degree Lemma
- The local fixed point index is independent of chart, ball and neighbourhood Lemma
- The local fixed point index is invariant under conjugation by a local diffeomorphism Lemma
- The local index is independent of chart, ball and trivialization Lemma
- Small-time flow fixed point indices and vector field zero indices Proposition
- The index of a nondegenerate fixed point is the sign of det(I-Df) Theorem
- The index of a nondegenerate vector-field zero Theorem
Dependency tree · two levels
47 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- Allen Hatcher, Algebraic Topology, §2.1 and §3.1 (standard reference, not scraped)