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Stieltjes inversion and uniqueness for probability measures on the real line

Statement

Assume the Axiom of Countable Choice.

Let μ be a Borel probability measure on R, with Stieltjes transform mμ(z)=∫(x−z)−1 dμ(x) for Im⁡z>0. For every a<b and x∈R, μ((a,b))+12μ({a})+12μ({b})=lim⁡η↓01π∫abIm⁡mμ(u+iη) du,μ({x})=lim⁡η↓0η Im⁡mμ(x+iη). If two Borel probability measures on R have the same Stieltjes transform on the upper half-plane, then they are equal.

Statement references

Bai and Silverstein, Appendix B.2, printed pp. 514–523 (complete book PDF).

Junyi Liao, §1.3.1, printed pp. 17–18 (complete lecture notes).

Facts & Assumptions

Given: Countable choice, a Borel probability measure μ, and its Stieltjes transform under the (x−z)−1 convention.

[A1]

The Axiom of Countable Choice supplies a choice function for each countable family of nonempty sets (The Axiom of Countable Choice (ACω)).

[F1]

The transform is mμ(z)=∫(x−z)−1 dμ(x) for Im⁡z>0 (Stieltjes transform of a probability measure on the real line).

[F2]

Fubini permits interchanging the integrals for an integrable function on the product measure space (Fubini's theorem for L^1 functions on a sigma-finite product).

[F3]

Dominated convergence passes pointwise limits through an integral under an integrable bound (Dominated convergence).

[F4]

A pi-system generating a sigma-algebra determines any containing lambda-system (Dynkin's pi-lambda theorem).

[F5]

Tonelli's theorem identifies the product integral of a nonnegative measurable function on a sigma-finite product with either iterated integral (Tonelli's theorem for nonnegative measurable functions on a sigma-finite product).

Proof

Given: Countable choice, μ, and, for the uniqueness claim, two Borel probability measures μ,ν with equal transforms.

1.1A1F1F2F3F5F6givenalgebra

The kernel K(x,u)=η/((x−u)2+η2) is continuous on R2 and hence Borel measurable; rational open rectangles form a countable basis, so B(R2)=B(R)⊗B(R)⊆B(R)⊗L(R). Restricting the second coordinate to the Lebesgue-measurable interval [a,b] preserves product measurability. Its integral in u is ∫abη(x−u)2+η2 du=arctan⁡b−xη−arctan⁡a−xη≤π. By [F6], Lebesgue measure restricted to [a,b] is finite, and the probability measure μ is finite. Tonelli [F5] shows that the product integrand has integral at most πμ(R)=π, so it belongs to L1 on the product space. Fubini [F2] therefore gives 1π∫abIm⁡mμ(u+iη) du=∫Kη,a,b(x) dμ(x),Kη,a,b(x)=1π(arctan⁡b−xη−arctan⁡a−xη). The kernel lies in [0,1] and tends pointwise to 1 on (a,b), 1/2 at either endpoint, and 0 elsewhere. [F3] gives the interval formula in the Statement, including endpoint atoms.

1.2F1F3algebra

For any x∈R, ηIm⁡mμ(x+iη)=∫η2(t−x)2+η2 dμ(t). The integrand is bounded by 1 and tends to 1{x}(t) as η↓0. Dominated convergence [F3] proves the atom formula.

2.1step 1.1step 1.2algebra

If mμ=mν, step 1.2 gives equality of their point masses at every x. Step 1.1 then gives μ((a,b))=ν((a,b)) for every a<b.

3.1F4step 2.1algebra∎

The family P={∅,R}∪{(a,b):a<b} is a pi-system: the intersection of two open intervals is another open interval or empty. It generates the Borel sigma-algebra because open intervals form a basis. The class of Borel sets on which μ and ν agree is a lambda-system: it contains R because both measures are probabilities, is closed under complements by finite total mass, and is closed under disjoint countable unions by countable additivity. Step 2.1 and [F4] therefore give equality on every Borel set, so μ=ν.

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