Alphabeta Math
TheoremStatement: Literature-sourcedProof: AI-adaptedprecheck passaudited 2026-08-16
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  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

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A covering map induces an injective homomorphism on fundamental groups

Statement

For a covering p:(E,e0)→(B,b0), the induced homomorphism p∗:π1(E,e0)→π1(B,b0) is injective.

Facts & Assumptions

Given: The objects, hypotheses, and choice principles stated above.

[F1]

Let p:E→B be a covering, H:Y×I→B a homotopy, and H~0:Y→E a lift of H(−,0). There is a unique lift H~:Y×I→E of H extending H~0. (Existence and uniqueness of homotopy lifts through a covering map).

[F2]

Let f:X→Y be continuous and let x0∈X. Composition sends a loop α at x0 to the loop f∘α at f(x0). Using the loop classes and fundamental group of def-based-loops-and-fundamental-group, the proposed induced homomorphism is f∗:π1(X,x0)⟶π1(Y,f(x0)),f∗([α]):=[f∘α]. The next theorem proves that this value is independent of the representative, that it is a group homomorphism in the sense of def-group-homomorphism, and that induced maps respect identities, composition and homotopies that fix the basepoint. (The homomorphism on fundamental groups induced by a pointed continuous map).

[F3]

A topological space X is simply connected when it is nonempty and path-connected (def-path-connected) and, for every x0∈X, the group π1(X,x0) has exactly one element. (Simply connected topological spaces).

Proof

technique · direct
1.1givenF2F1F3

If a loop upstairs maps to a nullhomotopic loop downstairs, lift a nullhomotopy with the given loop as its initial edge.

2.1step 1.1F2

Uniqueness forces the opposite edge to be constant, yielding a nullhomotopy upstairs.

3.1step 2.1F2

Preserve the chosen basepoints and the exact published definition of the induced map.

4.1step 3.1∎

The preceding construction and implications establish the assertion.

Depends on

Used by

Dependency tree · two levels

13 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources