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Every nonzero fraction is a unit times a power of a uniformiser
Statement
Let be a discrete valuation ring with fraction field , let be its discrete valuation, and let be a uniformiser. Then every nonzero element has a unique expression
with and .
Facts & Assumptions
Given: A discrete valuation ring , its discrete valuation , and a uniformiser .
A uniformiser is an element of value in a discrete valuation ring (Uniformising parameters).
A discrete valuation ring is the nonnegative locus of a surjective valuation (Discrete valuation rings).
Proof
Let and put . Since by [F1], one has . Setting , [F2] gives and , hence . Therefore .
Suppose also that with and . Applying gives because units have valuation . Then . So the expression is unique.
Depends on
Used by
Dependency tree · two levels
5 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- Allen B. Altman and Steven L. Kleiman, A Term of Commutative Algebra, 13th ed., (23.1) (standard reference, not scraped)
- J. S. Milne, A Primer of Commutative Algebra, v4.03, Discrete valuation rings after Example 20.1 (standard reference, not scraped)