Alphabeta Math
TheoremStatement: Literature-sourcedProof: AI-adaptedprecheck passjudge pass (gpt-5.6-terra)audited 2026-08-26
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Plane harmonic functions satisfy the mean-value property

Statement

Every plane harmonic function satisfies both the circle and disc mean-value properties of The circle and disc mean-value properties.

Facts & Assumptions

Given: A harmonic function u on an open set Ω, a point a∈Ω, and a radius r>0 with D(a,r)‾⊆Ω.

[L1]

Every open disc is star-shaped and therefore homologically simply connected, and every harmonic function on such a domain is the real part of a holomorphic function (Star-shaped plane domains are homologically simply connected, Harmonic conjugates exist on homologically simply connected plane domains).

[L2]

A holomorphic function equals its average on every smaller concentric circle (A holomorphic function equals its average on every circle inside a larger concentric holomorphy disc).

Proof

technique · direct
1.1L1choose

Because the closed disc D(a,r)‾ lies in the open set Ω, choose R>r with D(a,R)⊆Ω. The restriction of u to this disc is harmonic, so [L1] gives a holomorphic function F on D(a,R) with Re⁡F=u there.

2.1step 1.1L2

For every 0<t≤r, applying [L2] to F on the circle of radius t and taking real parts gives u(a)=12π∫02πu(a+teiθ) dθ.

3.1step 2.1

The circle formula of the definition is step 2.1 at t=r.

4.1step 2.1algebra∎

Multiplying the identity of step 2.1 by 2t/r2 and integrating from 0 to r gives the disc formula of the definition, because 2r2∫0rt dt=1.

Depends on

Used by

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Sources