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Sub-Gaussian projection risk bounds

Statement

Let n≥1, let V⊆Rn be a fixed subspace of dimension r, and let μ∈V. Suppose Y=μ+ε, where ε∈Rn is centered sub-Gaussian with proxy σ2≥0 in the linear-functional sense of Sub-Gaussian variables and vectors, and sub-exponential variables. Put μ^=PVY. Then μ^−μ=PVε. If r=0 or σ2=0, this error is zero almost surely. If r≥1 and σ2>0, for every t>0,

P(∥μ^−μ∥22>t)≤2⋅6rexp⁡ ⁣(−t8σ2).

Consequently, for every 0<δ<1,

P ⁣(1n∥μ^−μ∥22≤8σ2n[rlog⁡6+log⁡ ⁣(2δ)])≥1−δ,

and

E[1n∥μ^−μ∥22]≤8σ2n(rlog⁡6+log⁡2+1310). For r≥1, both bounds are at most Cσ2(r+log⁡(1/δ))/n and Cσ2r/n, respectively, for a universal constant C. In the fixed-design model Y=Xθ∗+ε with μ=Xθ∗∈col⁡(X), this is the fitted vector of Fixed-design least squares as orthogonal projection.

Facts & Assumptions

Given: A fixed subspace V⊆Rn, a mean vector μ∈V, and centered vector noise satisfying the stated proxy inequality.

[F1]

A centered vector Z∈Rn is sub-Gaussian with proxy σ2 when Eeλ⟨u,Z⟩≤eσ2λ2∥u∥22/2 for all u∈Rn and λ∈R (Sub-Gaussian variables and vectors, and sub-exponential variables).

[F2]

A centered sub-Gaussian vector in Rq with proxy σ2 obeys P(∥Z∥2≥a)≤2(1+2/ϵ)qexp⁡ ⁣(−(1−ϵ)2a22σ2) for a>0, 0<ϵ<1, and σ2>0; proxy zero gives zero tail (Finite sub-Gaussian maxima and epsilon-net reduction).

[F3]

Orthogonal projection has its component in the subspace and its residual orthogonal to that subspace (The orthogonal projection PWv is the W-component in V=W⊕W⊥).

[F4]

A finite-dimensional subspace has an orthonormal basis, including the empty basis in dimension zero (Every finite-dimensional real or complex inner product space has an orthonormal basis).

[F5]
[F7]

In a fixed-design model, the fitted vector is the projection of the observation onto the design column space (Fixed-design least squares as orthogonal projection).

[F8]

Probability is countably subadditive (Basic identities for a probability measure).

[F9]

Risk is the expected loss of a decision rule under the sampling law (Loss functions and risk).

[F10]

Finite linear combinations of integrable random variables are integrable, and expectation is linear; hence linear combinations of the centered coordinates of ε are centered (Linearity, monotonicity, and the modulus bound for expectation).

[F11]

The natural logarithm is the inverse of exp⁡, is strictly increasing, and satisfies the product law and log⁡1=0 (The natural logarithm as the inverse of the exponential function, Order, continuity, range, and the product, quotient, and reciprocal laws for the natural logarithm).

[F12]

For T≥0, c>0, t0≥0, h=c/2, and N∈N, min⁡(T,t0+Nh)≤t0+h∑j<N1{T>t0+jh}. If P(T>t)≤Aexp⁡(−t/c) and t0=clog⁡A, monotone convergence and expectation linearity, with the Archimedean property giving t0+Nh→∞, bound ET by t0+h∑j≥0exp⁡(−j/2). The exponential series gives exp⁡(1/2)≥13/8. Set q=exp⁡(−1/2)=1/exp⁡(1/2)≤8/13<1; the addition law gives exp⁡(−j/2)=qj by induction, and the geometric-series formula gives ∑j≥0exp⁡(−j/2)=1/(1−q)≤13/5 (Monotone convergence for the integral, Every complete ordered field is Archimedean, The exponential addition formula exp⁡(x+y)=exp⁡(x)exp⁡(y), The exponential is positive and satisfies exp⁡(−x)=1/exp⁡(x), The real exponential function and the number e by a power series, Integer powers am, For ∣r∣<1, ∑k≥0rk=1/(1−r), and for ∣r∣≥1 the series diverges).

Proof

1.1F1F4F10algebra

If r≥1, choose an orthonormal basis ϕ1,…,ϕr of V by [F4] and form the coordinate vector Z=(⟨ε,ϕj⟩)j=1r. Each coordinate is integrable and centered by [F10]. For any u∈Rr and λ∈R, Eeλ⟨u,Z⟩=Eeλ⟨∑jujϕj,ε⟩≤eσ2λ2∥u∥22/2 by [F1], since the basis is orthonormal. Thus Z is a centered sub-Gaussian vector with the same proxy.

2.1F2F3step 1.1algebra

For σ2>0, apply [F2] with ϵ=1/2 to Z. Since (1+2/ϵ)r=5r≤6r and (1−ϵ)2/2=1/8, this gives P(∥Z∥22>t)≤2⋅6re−t/(8σ2). The basis coordinates identify ∥Z∥2=∥PVε∥2 by [F3] and uniqueness of projection. If σ2=0, [F2] gives zero probability that this norm exceeds any positive threshold.

3.1F5F8step 2.1given

By [F5], μ^−μ=PV(μ+ε)−μ=PVε, because PVμ=μ. If r=0, then V={0} and μ=0, so the error is zero; if σ2=0, step 2.1 gives the same conclusion. For σ2=0, the zero tail in step 2.1 gives P(∥PVε∥22>1/j)=0 for each integer j≥1; this positive-norm event is their countable union, so [F8] gives probability zero. The positive-rank, positive-proxy tail is step 2.1.

3.2F11step 2.1algebra

For r≥1 and σ2>0, use step 2.1 with t=8σ2[rlog⁡6+log⁡(2/δ)]; [F11] makes this threshold positive, and the right side is δ, proving the probability bound after division by n.

4.1F9F10F11F12step 2.1step 3.1algebra

Put A=2⋅6r, c=8σ2, h=c/2, t0=clog⁡A, and T=∥μ^−μ∥22. In the positive-rank, positive-proxy case, the pointwise bound in [F12], expectation linearity [F10], and monotone convergence give ET≤t0+h∑j≥0P(T>t0+jh). Step 2.1 and [F11] bound each probability by exp⁡(−j/2); [F12] bounds their sum by 13/5. Hence ET≤c(log⁡A+13/10). By [F11], log⁡A=log⁡2+rlog⁡6; division by n gives the stated expected-error bound. By [F9], it is the expected risk under the squared fitted-value loss. The zero-error cases in step 3.1 also satisfy it.

5.1F7given∎

For a fixed-design model with μ=Xθ∗∈col⁡(X), take V=col⁡(X). [F7] identifies μ^ with the estimator in Fixed-design least squares as orthogonal projection, so the displayed bounds apply to that fitted vector.

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