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Convergence of the composed KAM transformations, with derivative and frequency-Lipschitz bounds

Statement

Use the sequences and hypotheses of The KAM parameter sequence: every step satisfies the smallness, truncation, parameter and contraction hypotheses, with n≥2, μ=τ+3n+2, σ0≤s0/32, hj=h04−μj and Ej≤E04−(μ+1)j. The step constants may be enlarged and their smallness constant decreased, depending only on n,τ. Put Λ:=Ωα,τ and Wj:=diag⁡(rj−1In,σj−1In).

Let H0(z,ν)=e0(ν)+ν⋅I+P0(z,ν) be holomorphic and real on real points on Dr0,s0,h0(Λ), with ∣P0∣≤ε0. Suppose at every stage the cited one-step suppliers produce the following data:

  1. A canonical, 2π-equivariant holomorphic phase map Φ~j on Drj/2,sj−8σj,hj(Λ) with the weighted estimates of One KAM step: the affine generator, its canonical time-one flow, and the quadratic remainder bound, affine in I and with angle component independent of I.
  2. A frequency shift vj with ∣vj∣≤Bj:=Cεj/rj=CαEjσjμ, and its inverse ϕj supplied by Elimination of the frequency shift by a holomorphic contraction retraction on Ohj/4(Λ), satisfying ϕj+vj∘ϕj=id, ∣ϕj−id∣≤Bj and ∥Dϕj−In∥≤(16n/7)Bj/hj.
  3. The exact transformed identity Hj(Φ~j(z,ϕj(ν)),ϕj(ν))=ej+1(ν)+ν⋅I+Pj+1(z,ν)=:Hj+1(z,ν), where ∣Pj+1∣≤εj+1 on Drj+1,sj+1,hj+1(Λ).

Define the extended step and composition by Tj(z,ν):=(Φ~j(z,ϕj(ν)),ϕj(ν)),T0∘⋯∘Tj−1(z,ν)=(Ψj(z,ν),χj(ν)), with (Ψ0,χ0)=(id,id). Thus parameter changes in every earlier factor are included. Set Dj:=Brj/2×Ssj−8σj×Ohj+1(Λ),L:={0}×Ss0/4×Λ. There are constants A,CL depending only on n,τ such that:

  1. Tj(Dj+1)⊆Dj; all extended compositions are holomorphic on Dj, take values in D0, and are equivariant in the angles. They are canonical in the phase variables for each real parameter. Every Dj contains L.
  2. On L, Ψj converges uniformly, together with every angular derivative, to Ψ∞, holomorphic in the angles for each label. Writing ΔjΨ:=Ψj+1−Ψj, one has ∣W0ΔjΨ∣≤AEj2−j,∣W0∂ϑiΔjΨ∣≤AEj2−j/σ0.
  3. For every pair ν,ν′∈Λ, sup⁡ϑ∈Ss0/4∣W0(ΔjΨ(0,ϑ,ν)−ΔjΨ(0,ϑ,ν′))∣≤CL(E0/h0)2−j∣ν−ν′∣. Consequently the phase limit has weighted frequency-Lipschitz constant 2CLE0/h0. In the unweighted norm the corresponding bound is 2CL(r0+σ0)E0/h0.
  4. Writing Ψ∞(0,ϑ,ν)=(b(ϑ,ν),ϑ+w(ϑ,ν)), the bounds are ∣b∣≤Ar0E0,∣w∣≤Aσ0E0,∣∂ϑib∣≤Ar0E0/σ0,∣∂ϑiw∣≤AE0. One may impose nAE0≤1/2 by decreasing the initial smallness constant.
  5. The parameter maps converge uniformly on Λ to χ∞, with ∣χ∞−id∣≤AB0 and Lip⁡(χ∞−id)≤CLB0/h0. The exact finite-stage normal form is H0(Ψj(z,ν),χj(ν))=ej(ν)+ν⋅I+Pj(z,ν),∣Pj∣≤εjon Dj.

Facts & Assumptions

Given: The sequence hypotheses, the Hamiltonian family and the specified one-step data.

[F1]

The KAM parameter sequence: every step satisfies the smallness, truncation, parameter and contraction hypotheses gives ηj≤1/8, ηj≤σj, sj≥s0/2, Bj≤hj+1/(16n), hj+1≤hj/4, and Ej≤E0qj, where q=4−(μ+1). In particular rj/r0≤2−j, σj/σ0=2−j and rj/σj≤r0/σ0.

[F2]

One KAM step: the affine generator, its canonical time-one flow, and the quadratic remainder bound supplies ∣Wj(Φ~j−id)∣≤CEj, ∥Wj(DzΦ~j−I)Wj−1∥≤CEj and ∣Wj∂νΦ~j∣≤CEj/hj on Ohj/2, with dimensional constants absorbed into C. Its phase Jacobian is block upper triangular. Elimination of the frequency shift by a holomorphic contraction retraction supplies the inverse bounds in the statement.

Proof

technique · direct; retain the parameter coordinate, use triangular weighted Jacobians, and estimate holomorphic increments on parameter tubes before passing to their label restrictions
1.1givenF1F2algebra

Domain inclusions. On Dj+1 the step moves actions by at most CrjEj, angles by at most CσjEj and parameters by at most Bj. Take the step smallness so that CEj≤1/8. Then rj+1/2+CrjEj≤rj/16+rj/8<rj/2. The angular loss sj−sj+1 is at least 5σj, so sj+1−8σj+1+CσjEj≤sj−9σj+σj/8<sj−8σj. Moreover hj+2+Bj≤hj+1/4+hj+1/(16n)<hj+1. These inequalities also put the input to ϕj in Ohj/4 and its image in Ohj/2. Thus Tj(Dj+1)⊆Dj, and induction defines the extended composition on Dj with image in D0. The exact sequence formula for sj gives sj−8σj≥s0−24σ0≥s0/4, and in fact for the sequence with loss 8σj it gives sj−8σj≥s0−16σ0≥s0/2. Hence the common larger angular strip St, t:=s0/4+2σ0, lies in every Dj at I=0. Equivariance and fixed-parameter canonicity follow by composition; real parameters remain real by the stated real one-step construction.

2.1step 1.1F1F2F3algebra

Phase Jacobians in a fixed weight. Because the phase Jacobians are upper triangular in (I,ϑ), conjugating their error matrices from Wj to W0 leaves diagonal blocks unchanged, multiplies the upper right block by (rj/σj)/(r0/σ0)≤1, and leaves the lower left block zero. Thus ∥W0(DzTj−I)W0−1∥≤CEj. The parameter block satisfies ∥Dϕj∥≤1+(16n/7)Bj/hj. Their products are bounded by exp⁡(C∑Ej) and exp⁡((16n/7)∑Bj/hj) respectively. Here ∑Ej≤2E0 and ∑Bj/hj≤2B0/h0, since Bj/hj=(B0/h0)(Ej/E0)2μj≤(B0/h0)4−j. Decrease the initial smallness so the phase product is at most 2; the parameter product is already at most exp⁡(2/(7⋅4μ))<2, since B0/h0≤(16n4μ)−1. The chain rule therefore gives ∥W0DzΨjW0−1∥≤2 and ∥Dχj∥≤2.

3.1step 2.1F1F2F3algebra

The parameter block of the phase composition. The single-step phase-parameter block in the fixed weight is bounded by CEj2−j/hj, because ∥W0Wj−1∥≤2−j and ∥Dϕj∥≤2. Expanding the parameter block of the product of block triangular extended Jacobians yields one term for each step, with a phase product on its left and a parameter product on its right. Step 2.1 bounds these products by 2, so ∥W0∂νΨj∥≤4C∑k<jEk2−k/hk≤AE0/h0. The last inequality follows from Ek/hk≤(E0/h0)4−k. The same product expansion for Dχj−I gives ∥Dχj−I∥≤AB0/h0. All bounds hold throughout the respective Dj; earlier factors are evaluated at the parameter images established in step 1.1.

4.1step 1.1step 2.1step 3.1F1F3algebra

Holomorphic increments. For (0,ϑ,ν) with ϑ∈St, ν∈Ohj+2(Λ), the straight segment from this point to Tj(0,ϑ,ν) lies in Dj. For the parameter segment this follows by choosing a label within hj+2 of ν: its entire segment stays within hj+2+Bj<hj+1 of that label. The action and angle segments stay inside their convex domains by step 1.1, with the same stronger margins on St. Integrating the derivatives of Ψj along this segment and using steps 2.1-3.1 gives ∣W0ΔjΨ∣≤2CEj2−j+A(E0/h0)Bj≤AEj2−j. Indeed (E0/h0)Bj=(B0/h0)Ej2−μj and B0/h0 is bounded by a dimensional small constant. This estimates both changes of phase and changes of the parameter fed into every earlier factor. Likewise ∣χj+1−χj∣≤2Bj on this parameter tube. Cauchy's estimate with angular margin σ0 gives the displayed first derivative bound on Ss0/4 and, for every multi-index β, the bound ∣W0∂ϑβΔjΨ∣≤Aβ!σ0−∣β∣Ej2−j.

5.1step 4.1F1F3algebra

Frequency Lipschitz bounds without convexity of the label set. A holomorphic function f bounded by M on Oa(Λ) has ∣f(ν)−f(ν′)∣≤4n(M/a)∣ν−ν′∣ for labels ν,ν′. If ∣ν−ν′∣<a/2, their segment stays within a/2 of ν∈Λ, and Cauchy bounds on coordinate discs of radius a/2 give the derivative bound 2nM/a there. If their distance is at least a/2, use ∣f(ν)−f(ν′)∣≤2M. Apply this argument to the weighted phase increment of step 4.1 with a=hj+2. Since Ej2−j/hj+2≤42μ(E0/h0)4−j2−j, it proves clause 3 with a dimensional CL. Apply it also to χj+1−χj, bounded by 2Bj on the same tube. The bound Bj/hj+2≤42μ(B0/h0)4−j makes its Lipschitz series summable. This argument uses no segment contained in Λ and therefore applies to disconnected Diophantine label sets.

6.1step 4.1step 5.1F1F3algebra

Limits and sizes. The bounds of step 4.1 are summable for every fixed angular multi-index, uniformly on L. Their series therefore define Ψ∞, with uniform convergence of all angular derivatives. For each label, holomorphic convergence on St and Cauchy differentiation prove holomorphy and identify these derivative limits with derivatives of Ψ∞. Summing the component bounds gives clause 4 after enlarging A; decreasing the initial smallness gives nAE0≤1/2. The identity phase map has zero parameter derivative, so summing step 5.1 gives clause 3 for the limit. The parameter increments have summable sizes 2Bj and summable Lipschitz constants, yielding χ∞, its displacement bound and its asserted Lipschitz bound relative to the identity.

7.1givenstep 1.1algebra∎

Exact invariance data. By the stated one-step identity, Hj∘Tj=Hj+1. Induction on the extended compositions gives H0(Ψj(z,ν),χj(ν))=Hj(z,ν)=ej(ν)+ν⋅I+Pj(z,ν) on Dj. The perturbation bound holds there because Dj⊆Drj,sj,hj(Λ). The parameter coordinate is essential: for a parameter-dependent H0 the Hamiltonian transported by the phase map at stage j is H0(⋅,χj(ν)). This proves clause 5.

Remarks

The estimates are in a fixed initial weight and retain both action and angle scales. No inequality r0≤σ0 is assumed. Frequency reparametrisation is part of the composition, so the eventual invariant torus has label frequency ν for the Hamiltonian with original parameter χ∞(ν).

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