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Finite-dimensional coherent cohomology over a field

Statement

Assume the Axiom of Choice, inherited from the proper finiteness theorem and the basis-extraction corollary cited below (The Axiom of Choice). Let k be a field (Field), let X be a scheme proper over k, that is, the structure morphism X→Spec⁡k is proper (Proper morphisms), and let F be a coherent OX-module (Coherent module sheaves). Then for every q≥0 the k-vector space Hq(X,F) of sheaf cohomology (Sheaf cohomology as right derived global sections) is finite-dimensional over k (Finite-dimensional vector space, and its dimension dim⁡FV; infinite-dimensional means having no finite basis), and only finitely many of the groups Hq(X,F) are nonzero. More precisely, choose a finite affine open cover of X with no empty members when X≠∅, and use the empty cover when X=∅. If n is its number of members, then Hq(X,F)=0 for every q≥n, so the vanishing bound is the length of the cover and does not depend on F.

The empty source X=∅, the zero sheaf F=0, the degree q=0 and every field k are included.

Facts & Assumptions

Given: A field k, a proper morphism X→Spec⁡k and a coherent OX-module F; the Axiom of Choice is inherited from the cited suppliers.

[F1]

A field is a Noetherian ring: its only ideals are (0) and the whole field, so every ideal is finitely generated. (A field has only the zero ideal and itself, hence is Noetherian)

[F2]

Finite generation and vanishing for proper coherent cohomology: for a Noetherian ring A, a proper morphism X→Spec⁡A and a coherent F, each Hq(X,F) is a finitely generated A-module; choose a finite affine open cover with no empty members when X is nonempty and use the empty cover when X is empty, and let n be its number of members. Then Hq(X,F)=0 for every q≥n. The cited theorem assumes both AC and DC; AC in this corollary supplies DC by the choice-implication theorem. (Finite coherent cohomology for proper schemes, AC implies DC implies countable choice)

[F3]

A module over a field is a vector space: the axioms for a k-module are exactly the vector-space axioms over k, so every Hq(X,F) is a k-vector space. (Vector space over a field, Generated submodule, cyclic and finitely generated modules, module basis and free module)

[F4]

Finitely generated modules and finite spanning sets: a module M over a ring is finitely generated when it is generated by finitely many of its elements, that is, when there are m1,…,ms∈M with every element of M a finite linear combination of the mj; a set of vectors spans a vector space when its linear combinations fill it. Hence a finitely generated k-module is a k-vector space with a finite spanning set. (Generated submodule, cyclic and finitely generated modules, module basis and free module, Linear combination of a finite list, and the span span⁡(S) as the smallest linear subspace containing S)

[F5]

Basis extraction: assuming the Axiom of Choice, every spanning subset of a vector space contains a basis. (Every spanning subset of a vector space contains a basis)

[F6]

Finite-dimensionality: a vector space is finite-dimensional over its field when it has a finite basis, and the zero space is finite-dimensional of dimension 0 via the empty basis. (Finite-dimensional vector space, and its dimension dim⁡FV; infinite-dimensional means having no finite basis)

[F7]

The Axiom of Choice is the choice principle named in the statement. (The Axiom of Choice)

Proof

technique · direct: specialise the proper finiteness theorem to the base field, where a finitely generated module is a vector space with a finite spanning set, extract a finite basis, and read off the finite vanishing range from the cover-length bound
1.1F1F2

The base is Noetherian. By [F1] the field k is a Noetherian ring, and AC supplies the DC premise of [F2] by the choice-implication theorem cited there. If X is empty, choose the empty cover; if X is nonempty, choose a finite affine open cover and discard any empty members, leaving at least one member. Write n for the number of members of this chosen cover. Thus [F2] applies to the proper morphism X→Spec⁡k and the coherent module F: each Hq(X,F) is a finitely generated k-module, and Hq(X,F)=0 for every q≥n.

1.2F3F4F5F61.1

Finite-dimensionality in every degree. By [F3] each Hq(X,F) is a k-vector space, and by 1.1 it is finitely generated as a k-module, hence has a finite spanning set by [F4]; [F5] produces a basis of Hq(X,F) inside that finite spanning set, which is a finite basis, so Hq(X,F) is finite-dimensional over k by [F6].

1.3F21.1

Only finitely many nonzero groups. The cover chosen in 1.1 exists because X is proper, hence quasi-compact, over the affine base Spec⁡k. By 1.1, Hq(X,F)=0 for every q≥n, so the only degrees that can be nonzero are q=0,1,…,n−1, a finite set (empty when X=∅).

2.1F2F4F5F6F71.11.2∎

Boundaries and choice accounting. If X=∅ then n=0, all groups vanish by 1.1, and each is finite-dimensional of dimension 0 by [F6]; if F=0 all groups vanish in the same way. Degree q=0 is covered by 1.2 together with all other degrees. The field k is arbitrary, in particular k=F2 and fields of every characteristic are allowed, and only the trivial ring A=0 is excluded by the hypothesis that k is a field. The Axiom of Choice [F7] supplies DC for the proper finiteness theorem through [F2] and is also used by the basis extraction of [F5], which is the only place where a basis is selected; the finite spanning sets of [F4] are supplied by 1.1, so no selection from an infinite family occurs.

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Sources