Alphabeta Math
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Cartesian Gaussian moments and exponent-parameter derivatives

Statement

Let p>0 and α∈N03. If any component of α is odd, then ∫R3xαe−p∥x∥22 dx=0. If αj=2kj for j=1,2,3, then ∫R3xαe−p∥x∥22 dx=π3/2∏j=13(2kj)!4kjkj! pkj+1/2. For every q∈N0, differentiation with respect to p is valid and dqdpq∫R3xαe−p∥x∥22 dx=(−1)q∫R3∥x∥22qxαe−p∥x∥22 dx.

Facts & Assumptions

Given: p>0, a multi-index α∈N03, and the Lebesgue integral convention of Cartesian Gaussian primitives, contractions, and integral conventions.

[F3]

Tonelli's theorem for nonnegative measurable functions on a sigma-finite product: nonnegative measurable functions on a sigma-finite product may be integrated by sections in either order.

[F4]

Fubini's theorem for L^1 functions on a sigma-finite product: absolutely integrable functions on a sigma-finite product have equal iterated and product integrals.

[F5]

Dominated convergence: pointwise convergence under a single integrable majorant permits passage of the limit through the integral.

[F6]

Mean value theorem on a closed real interval: a difference quotient of a differentiable scalar function is bounded by the supremum of its derivative on the intervening segment.

[F7]

Change of variable in an improper integral: a monotone differentiable surjection between intervals preserves convergent improper integrals when its derivative and the target integrand are locally Riemann integrable and the proper change-of-variable hypotheses hold on every compact truncation. Each singular end is treated separately, with orientation adjusted for decreasing substitutions.

[L9]

The exponential function is smooth and (exp⁡)′=exp⁡ and Sum, product, quotient, and chain rules from difference quotients: the exponential is smooth with derivative itself; finite sums, products and polynomial compositions obey the product, power and chain rules. Applying these rules one coordinate or parameter at a time justifies every displayed finite Gaussian derivative.

[F8]

The real exponential function and the number e by a power series: ex is given by its convergent power series for real x.

Proof

1.1givenF1F2F7F8algebraL9

For each integer d≥0, ∣x∣de−px2 is absolutely integrable. If d>0, differentiating rde−pr2/2 shows it increases up to r=d/p and decreases afterwards, so it is bounded by (d/p)d/2; for d=0 it is bounded by 1. Thus ∣x∣de−px2≤Cde−px2/2 for a finite Cd, whose right-hand side is integrable by scaling and [F1], [F7]. Write Jk(p)=∫Rx2ke−px2 dx for k≥0. Then J0(p)=π p−1/2 by scaling y=p x and [F1], [F7], and odd moments vanish by x↦−x, now with absolute convergence established. All these scaling and reflection maps are linear surjections with continuous derivatives; the integrands are continuous on every compact truncation, so [F7] applies separately at both infinite ends. Fix k≥1 for the moment recurrence below. For its boundary term choose an integer N>(2k−1)/2. By [F8] and e−pR2/2≤1, R2k−1e−pR2≤N!(2/p)NR2k−1−2N⟶0. Integration by parts [F2] on [−R,R] with dv=xe−px2dx=−d(e−px2)/(2p) therefore gives Jk(p)=(2k−1)Jk−1(p)/(2p) after R→∞. Iterating yields Jk(p)=π(2k)!/(4kk!pk+1/2).

2.1givenF3F4step 1.1algebra

The absolute value of each three-dimensional integrand is a product of three one-dimensional polynomial-Gaussian factors. Their integrals are finite by step 1.1, so [F3] and then [F4] factor the integral into the product of the three one-dimensional moments. If a component is odd, its factor is zero; otherwise multiplying the three formulas from step 1.1 gives the displayed expression.

3.1givenF5F6step 1.1step 2.1inductionL9∎

Fix p0>0 and restrict p to [p0/2,3p0/2]. The absolute value of each q-th parameter derivative integrand is bounded by ∥x∥∣α∣+2qe−(p0/2)∥x∥2. This is integrable by step 2.1: bound ∥x∥d≤(∣x1∣+∣x2∣+∣x3∣)d, expand the finite power, and use the absolute one-dimensional moments established in step 1.1. Difference quotients for one derivative are bounded by the corresponding next polynomial-Gaussian majorant by [F6]; [F5] therefore passes each limit through the integral. Repeating this argument q times gives the stated factor (−1)q∥x∥2q.

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