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TheoremStatement: AI-adaptedProof: AI-generatedprecheck passverified 2026-08-10 (gpt-5.6-terra-codex-subscription)
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If continuously differentiable functions converge at one point and their derivatives converge uniformly on a closed interval, then the functions converge uniformly to a differentiable function whose derivative is the derivative limit

Statement

Let a<b be reals and let fk:[a,b]→R be continuously differentiable: each fk is differentiable on [a,b] and each derivative fk′ is continuous there (Continuity of f:A→R at a point of A and on A: the ε-δ condition, its agreement with lim⁡x→cf(x)=f(c) at a limit point, and continuity at an isolated point). Suppose there is c∈[a,b] such that the real sequence (fk(c)) converges to A, and suppose fk′→g uniformly on [a,b]. Then there is a differentiable function f:[a,b]→R such that

fk⟶f  uniformly,f′=g.

Facts & Assumptions

Given: Reals a<b, a point c∈[a,b], continuously differentiable functions fk:[a,b]→R, convergence fk(c)→A, and uniform convergence fk′→g.

[L1]

A uniform limit of continuous real-valued functions is continuous, and a continuous function on [a,b] is Riemann integrable (The uniform limit of continuous real-valued functions on a metric space is continuous, A continuous function on [a,b] is Riemann integrable, by Heine-Cantor and Riemann's criterion).

[L2]

Uniform convergence of integrable functions preserves integrability and the limit of the integrals (A uniform limit of Riemann-integrable functions is Riemann integrable, and its integral is the limit of their integrals).

[L6]

A uniform bound ∣p−q∣≤η on an interval gives ∣∫uvp−∫uvq∣≤η∣v−u∣ (Uniformly close integrable functions have integrals differing by at most the interval length times their uniform error).

Proof

technique · constructive
1.1

By [L7], each real-continuous derivative fk′ is metric-continuous. The uniform-limit clause of [L1] makes g metric-continuous, and [L7] makes g real-continuous. The integrability clause of [L1] therefore makes every fk′ and g Riemann integrable; [L2] also gives the integrability of the uniform limit.

L1L2L7
1.2

Let ε>0. Choose N0 such that ∣fk(c)−A∣<ε/2 for k≥N0, and choose N1 such that ∣fk′(x)−g(x)∣<ε/(2(b−a+1)) for k≥N1 and all x∈[a,b].

givenchoose
2.1

Fix k and x∈[a,b]. If c<x, restrict fk to [c,x]; its derivative is fk′ there and that derivative is integrable there by steps 1.1 and [L3], so the first clause of [L3] gives fk(x)=fk(c)+∫cxfk′. If x<c, apply that clause on [x,c] and then use orientation; if x=c, use ∫ccfk′=0. Thus in every case fk(x)=fk(c)+∫cxfk′.

step 1.1L3
2.2

Define H(x):=∫axg and construct f:[a,b]→R by f(x):=A+H(x)−H(c)=A+∫cxg.

step 1.1L4construct
3.1

By [L4] and [L5], H is differentiable with H′=g, and therefore the constructed function f=A+H−H(c) is differentiable with f′=g.

step 2.2L4L5
3.2

Choose N at least as large as N0,N1. For k≥N and x∈[a,b], steps 2.2 and 2.1 with [L6] give ∣fk(x)−f(x)∣≤∣fk(c)−A∣+∣∫cxfk′−∫cxg∣<ε/2+ε∣x−c∣/(2(b−a+1))<ε.

step 2.2step 2.1step 1.2L6choosealgebra
4.1

The index N in step 3.2 serves every x∈[a,b], so fk→f uniformly; step 3.1 gives f′=g. Thus the constructed f has both asserted properties.

step 3.2step 3.1discharge-construct∎

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